Problem 32
Question
Amino acid enters in the respiratory pathway at (a) Kreb's cycle (b) Pyruvate (c) Acetyl CoA (d) Any of these
Step-by-Step Solution
Verified Answer
The correct answer is (d) Any of these. Amino acids can enter in the respiratory pathway at different points, including Kreb's cycle and Acetyl CoA. The entry point depends on the specific type of amino acid.
1Step 1: Understand The Respiratory Pathway
The respiratory pathway, or cellular respiration, is a set of metabolic reactions that take place in the cells of organisms to convert biochemical energy from nutrients into adenosine triphosphate (ATP), and then release waste products. The cycles in the pathway include Glycolysis, the Kreb's cycle, and the Electron Transport Chain, among others.
2Step 2: Identify the Entry Point of Amino Acids
Amino acids can enter the respiratory pathway at different points depending on their type. However, they generally enter during the Kreb's cycle or as Acetyl CoA. They first undergo deamination, where the amino group is removed and they are then converted into molecules that can be used in the respiratory pathway.
3Step 3: Summarize The Pathway Entry Points
From the given options, the entry points for amino acids could be the Kreb's cycle or Acetyl CoA. However, as the question specifies a single entry point, and one of the options is 'Any of these', it is the most appropriate choice. It reflects the variable nature of the entry points for amino acids in the respiratory cycle, as they can enter at multiple stages.
Key Concepts
Kreb's cycleamino acid metabolismacetyl CoA entry
Kreb's cycle
The Kreb's cycle, also known as the citric acid cycle or TCA cycle, is a vital part of cellular respiration. It takes place in the mitochondria, the powerhouse of the cell. This cycle is crucial because it completes the oxidation of the organic molecules, thus aiding in the production of ATP. Here, molecules like acetyl CoA are broken down to release energy.
- Once acetyl CoA enters the Kreb's cycle, it combines with oxaloacetate to form citrate.
- Through a series of enzymatic reactions, citrate is progressively broken down, releasing carbon dioxide and transferring energy to carrier molecules like NADH and FADH2.
- This energy is later used in the electron transport chain to produce ATP, the energy currency of cells.
amino acid metabolism
Amino acid metabolism plays a critical role in cellular respiration, providing alternative pathways for energy production. When proteins are digested, they yield amino acids, which can be metabolized to enter the respiratory pathway.
- The first step in amino acid metabolism is deamination, where the amino group is removed, often forming ammonia as a byproduct.
- The remaining carbon skeletons, now called alpha-keto acids, are transformed into various intermediates that feed into the respiratory pathway.
- These intermediates can enter different stages, such as glycolysis, the Kreb’s cycle, or be converted into acetyl CoA depending on the specific amino acid type.
acetyl CoA entry
Acetyl CoA is a central molecule in metabolism and a key entry point into the Kreb's cycle. It forms when pyruvate, the end product of glycolysis, is oxidized. Acetyl CoA is pivotal not just in carbohydrate metabolism, but also in the breakdown of fatty acids and amino acids.
- When amino acids are deaminated, some are converted directly into acetyl CoA.
- This versatile molecule then enters the Kreb's cycle, where it is further oxidized for energy release.
- Besides its role in energy production, acetyl CoA is also crucial for the synthesis of fatty acids and sterols.
Other exercises in this chapter
Problem 30
Respiratory pathway is best defined as (a) Catabolic pathway (b) Anabolic pathway (c) Amphibolic pathway (d) None of these
View solution Problem 31
Glycerol enters the respiratory pathway at (a) Glu-6-phosphate (b) PGA (c) PGAL (d) PEP
View solution Problem 33
Fatty acid for entry into Kreb's cycle is degraded to (a) Pyruvate (b) Citric acid (c) Acetyl-CoA (d) PGA
View solution Problem 35
\(\mathrm{RQ}\) for protein is (a) \(0.8\) (b) \(0.7\) (c) \(0.9\) (d) \(0.5\)
View solution