Problem 32
Question
A function \(f\) is given. (a) Use a graphing calculator to draw the graph of \(f .\) (b) Find the domain and range of \(f\) from the graph. $$ f(x)=x^{2}+4 $$
Step-by-Step Solution
Verified Answer
The domain is \( (-\infty, \infty) \) and the range is \( [4, \infty) \).
1Step 1: Graph the Function
Using a graphing calculator, plot the function \( f(x) = x^2 + 4 \). This will result in a parabola opening upwards, with its vertex at the point (0,4). The graph will be symmetric around the y-axis.
2Step 2: Determine the Domain
The domain of a function corresponds to all the possible x-values the function can accept. Since \( f(x) = x^2 + 4 \) is a quadratic function, it can accept any real number as input. Therefore, the domain is all real numbers, which can be expressed in interval notation as \( (-\infty, \infty) \).
3Step 3: Determine the Range
The range of a function corresponds to all the possible y-values a function can output. For \( f(x) = x^2 + 4 \), since the minimum value of \( x^2 \) is 0 and it increases from there, the minimum output value is \( 4 \). Therefore, the range is all real numbers greater than or equal to 4, written in interval notation as \( [4, \infty) \).
Key Concepts
Graphing ParabolasDomain and RangeVertex of a Parabola
Graphing Parabolas
Parabolas are a special shape in mathematics that we often see in quadratic functions. When you graph a quadratic function like \( f(x) = x^2 + 4 \), you get a curve called a parabola. In this case, because it is in the form \( f(x) = ax^2 + bx + c \), it will produce a U-shaped curve that opens upward because the coefficient of \( x^2 \), which is \( a \), is positive. This graph is symmetrical, meaning if you draw a vertical line through the middle of it, both sides will be mirror images.
Important Points about Graphing Parabolas:
Important Points about Graphing Parabolas:
- The vertex is a key point on the graph. For this particular function, the vertex is at (0, 4).
- Parabolas have an axis of symmetry, a vertical line that runs through the vertex. Here it is the y-axis, or \( x = 0 \).
- Each parabola opens either upwards or downwards based on the leading coefficient \( a \). If \( a > 0 \), it opens upwards, as with \( x^2 + 4 \).
Domain and Range
When dealing with quadratic functions, understanding the domain and range is crucial. The domain of a function refers to all the possible x-values that will work in the function, while the range refers to all possible y-values that the function can output.
Domain:
Domain:
- For quadratic functions like \( f(x) = x^2 + 4 \), the domain is all real numbers because you can place any real number into \( x \) and calculate \( f(x) \).
- This can be written in interval notation as \( (-\infty, \infty) \).
- The range here is slightly different. Since the parabola opens upward and has its lowest point at the vertex, \( y \) values will always be at least 4, the y-coordinate of the vertex.
- Thus, the range of \( f(x) = x^2 + 4 \) is \( [4, \infty) \), meaning all real numbers 4 or greater.
Vertex of a Parabola
The vertex of a parabola is a crucial point that tells us a lot about the graph. It can be seen as the highest or lowest point on the parabola, depending on its orientation. For a function like \( f(x) = x^2 + 4 \), the vertex is found directly from the function itself.
Understanding the Vertex:
Understanding the Vertex:
- The vertex form of a quadratic function is \( f(x) = a(x-h)^2 + k \). It's easy to see the transformation points \( (h, k) \) as the vertex.
- In \( f(x) = x^2 + 4 \), the vertex is \( (0, 4) \) because it can be rewritten as \( f(x) = 1(x-0)^2 + 4 \).
- The x-coordinate of the vertex provides the axis of symmetry, a line that splits the parabola equally, which in our example is \( x = 0 \).
Other exercises in this chapter
Problem 32
\(29-40\) Find the functions \(f \circ g, g \circ f, f \circ f,\) and \(g \circ g\) and their domains. $$ f(x)=x^{3}+2, \quad g(x)=\sqrt[3]{x} $$
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\(29-38=\) Find the maximum or minimum value of the function. $$ f(t)=10 t^{2}+40 t+113 $$
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\(27-32\) : A function \(f\) is given, and the indicated transformations are applied to its graph (in the given order). Write the equation for the final transfo
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Find the inverse function of \(f\). \(f(x)=6-x\)
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