Problem 32
Question
\(29-34\) Simplify the expression by using a Double-Angle Formula or a Half- Angle Formula. $$ \begin{array}{ll}{\text { (a) } \cos ^{2} \frac{\theta}{2}-\sin ^{2} \frac{\theta}{2}} & {\text { (b) } 2 \sin \frac{\theta}{2} \cos \frac{\theta}{2}}\end{array} $$
Step-by-Step Solution
Verified Answer
(a) \( \cos \theta \); (b) \( \sin \theta \).
1Step 1: Identify the Formula for Part (a)
For the expression \( \cos^2 \frac{\theta}{2} - \sin^2 \frac{\theta}{2} \), we recognize this as a difference of squares. Specifically, it is analogous to \( \cos^2 x - \sin^2 x \), which is the cosine double angle formula: \( \cos 2x = \cos^2 x - \sin^2 x \). Therefore, \( \cos^2 \frac{\theta}{2} - \sin^2 \frac{\theta}{2} = \cos \theta \).
2Step 2: Solution for Part (a)
Using the identified double-angle formula, simplify the expression: \[ \cos^2 \frac{\theta}{2} - \sin^2 \frac{\theta}{2} = \cos \theta \].
3Step 3: Identify the Formula for Part (b)
The expression \( 2 \sin \frac{\theta}{2} \cos \frac{\theta}{2} \) resembles the sine double angle formula: \( \sin 2x = 2 \sin x \cos x \). Thus, \( 2 \sin \frac{\theta}{2} \cos \frac{\theta}{2} = \sin \theta \).
4Step 4: Solution for Part (b)
Apply the sine double-angle formula to simplify: \[ 2 \sin \frac{\theta}{2} \cos \frac{\theta}{2} = \sin \theta \].
Key Concepts
Trigonometric IdentitiesCosine Double-Angle FormulaSine Double-Angle FormulaHalf-Angle Formulas
Trigonometric Identities
Trigonometric identities are essential tools in mathematics, especially when dealing with angles and circular functions. These identities express relationships between trigonometric functions, helping simplify and solve complex problems.
Some important identities include:
Some important identities include:
- Pythagorean Identity: \( \sin^2 x + \cos^2 x = 1 \)
- Sum and Difference Formulas: These are used to find the sine, cosine or tangent of angles summed or subtracted.
- Double-Angle and Half-Angle Formulas: Allow us to express trigonometric functions of multiple angles or fractions of angles in terms of functions of a single angle.
Cosine Double-Angle Formula
The cosine double-angle formula is a specific trigonometric identity that helps simplify expressions involving the cosine of double angles. The formula is given by:
In practical problems, like the given exercise part (a), this formula allows us to simplify \( \cos^2 \frac{\theta}{2} - \sin^2 \frac{\theta}{2} \) to \( \cos \theta \), making calculations easier and the expression more manageable.
- \( \cos 2x = \cos^2 x - \sin^2 x \)
- Additionally, \( \cos 2x \) can also be expressed in alternate forms: \( 2\cos^2 x - 1 \) or \( 1 - 2\sin^2 x \).
In practical problems, like the given exercise part (a), this formula allows us to simplify \( \cos^2 \frac{\theta}{2} - \sin^2 \frac{\theta}{2} \) to \( \cos \theta \), making calculations easier and the expression more manageable.
Sine Double-Angle Formula
The sine double-angle formula provides a way to simplify expressions involving the sine of a doubled angle. The formula is expressed as:
In exercises like part (b) of the original problem, the sine double-angle formula allows us to simplify \( 2 \sin \frac{\theta}{2} \cos \frac{\theta}{2} \) to \( \sin \theta \). This simplification helps reduce complexity, facilitating easier manipulation of trigonometric expressions in calculations or proofs.
- \( \sin 2x = 2 \sin x \cos x \)
In exercises like part (b) of the original problem, the sine double-angle formula allows us to simplify \( 2 \sin \frac{\theta}{2} \cos \frac{\theta}{2} \) to \( \sin \theta \). This simplification helps reduce complexity, facilitating easier manipulation of trigonometric expressions in calculations or proofs.
Half-Angle Formulas
The half-angle formulas are trigonometric identities that express trigonometric functions of half an angle in terms of the square roots of expressions involving that angle. Given their nature, these formulas are particularly helpful in solving trigonometric equations or simplifying expressions.
- \( \sin \frac{x}{2} = \pm \sqrt{\frac{1 - \cos x}{2}} \)
- \( \cos \frac{x}{2} = \pm \sqrt{\frac{1 + \cos x}{2}} \)
- \( \tan \frac{x}{2} = \pm \sqrt{\frac{1 - \cos x}{1 + \cos x}} = \frac{\sin x}{1 + \cos x} \)
Other exercises in this chapter
Problem 32
\(17-34\) . An equation is given. (a) Find all solutions of the equation. (b) Find the solutions in the interval \([0,2 \pi) .\) $$ 4 \sin \theta \cos \theta+2
View solution Problem 32
Prove the identity. $$ \tan \left(x-\frac{\pi}{4}\right)=\frac{\tan x-1}{\tan x+1} $$
View solution Problem 32
\(25-38\) . Find all solutions of the given equation. $$ \cot \theta+1=0 $$
View solution Problem 32
Verify the identity. $$ \frac{\cot x \sec x}{\csc x}=1 $$
View solution