Problem 31
Question
Write the standard form of the equation of the circle with the given center and radius. $$\text { Center }(0,0), r=7$$
Step-by-Step Solution
Verified Answer
The equation of the circle in standard form with the given center (0,0) and radius 7 is \(x^2 + y^2 = 49\)
1Step 1: Identify the center and radius
The center is (0,0) and the radius r is 7.
2Step 2: Substitute the values in the formula
Substitute these values into the standard form equation. Here, h is 0, k is 0 and r is 7. The equation becomes: \( (x - 0)^2 + (y - 0)^2 = 7^2 \).
3Step 3: Simplify the equation
By simplifying the equation, we get the standard form of the equation of the circle: \(x^2 + y^2 = 49\).
Key Concepts
Standard FormCircle EquationsRadiusCenter of a Circle
Standard Form
The standard form of the equation of a circle is a simplified way to express the relationship between the x and y coordinates of any point on the circle. It is given by:
\[ (x - h)^2 + (y - k)^2 = r^2 \]
Here, \((h, k)\) are the coordinates of the center of the circle, and \(r\) is the radius. The standard form makes it easy to visualize the circle's properties directly from the equation.
\[ (x - h)^2 + (y - k)^2 = r^2 \]
Here, \((h, k)\) are the coordinates of the center of the circle, and \(r\) is the radius. The standard form makes it easy to visualize the circle's properties directly from the equation.
- The terms \((x - h)^2\) and \((y - k)^2\) ensure that the equation accounts for any shift of the circle’s center from the origin.
- \(r^2\) represents the area a point can be from the center to still lie on the circle.
Circle Equations
Circle equations come in several forms, but the standard form is the most straightforward for basic analysis. The other main form is the general form of a circle's equation:
\[ x^2 + y^2 + Dx + Ey + F = 0 \]
Here, \(D\), \(E\), and \(F\) are constants that can help determine the circle's center and radius if rearranged into the standard form.
\[ x^2 + y^2 + Dx + Ey + F = 0 \]
Here, \(D\), \(E\), and \(F\) are constants that can help determine the circle's center and radius if rearranged into the standard form.
- To convert from the general form to the standard form, you would need to complete the square for both \(x\) and \(y\) terms.
- This conversion makes it easier to read the circle's center and radius directly.
Radius
The radius of a circle is the constant distance from the circle's center to any point on its circumference. In the equation, it appears as \(r\), and in the standard form, its square appears as \(r^2\).
- In the example given, where the radius is 7, it means that every point on the circle is exactly 7 units away from the center \((0,0)\).
- This distance is always positive, and knowing the radius is crucial for constructing the circle or understanding the equation of it.
Center of a Circle
The center of a circle is a point defined by the coordinates \((h, k)\) in the standard form equation. This point indicates where the circle is perfectly balanced in all directions on a coordinate plane.
- For the provided exercise, the center is at the origin, \((0, 0)\). This means the circle is symmetrically placed with respect to both the x and y axes.
- When the center is not at the origin, the equation's terms \((x-h)\) and \((y-k)\) shift the circle accordingly on the plane.
Other exercises in this chapter
Problem 30
Find the domain of each function. $$ f(x)-\frac{7 x+2}{x^{3}-2 x^{2}-9 x+18} $$
View solution Problem 31
If two lines are parallel, describe the relationship between their slopes.
View solution Problem 31
Use the given conditions to write an equation for each line in point-slope form and slope-intercept form. Passing through \((-3,-2)\) and \((3,6)\)
View solution Problem 32
If two lines are perpendicular, describe the relationship between their slopes.
View solution