Problem 31
Question
Which of the following are equivalent to the definition of limit? (a) For some \(\varepsilon>0\) and every \(\delta>0,0<|x-c|<\delta \Rightarrow\) \(|f(x)-L|<\varepsilon\) (b) For every \(\delta>0\), there is a corresponding \(\varepsilon>0\) such that $$ 0<|x-c|<\varepsilon \Rightarrow|f(x)-L|<\delta $$ (c) For every positive integer \(N\), there is a corresponding positive integer \(M\) such that \(0<|x-c|<1 / M \Rightarrow|f(x)-L|\) \(<1 / N\) (d) For every \(\varepsilon>0\), there is a corresponding \(\delta>0\) such that \(0<|x-c|<\delta\) and \(|f(x)-L|<\varepsilon\) for some \(x\)
Step-by-Step Solution
Verified Answer
Only option (c) is equivalent to the limit definition.
1Step 1: Understanding the Real Definition of Limit
The definition of limit \(\lim_{{x \to c}} f(x) = L\) in \(\varepsilon-\delta\) terms is: For every \(\varepsilon > 0\), there exists a \(\delta > 0\) such that whenever \(0 < |x-c| < \delta\), it follows that \(|f(x)-L| < \varepsilon\).
2Step 2: Analyzing Option A
Option (a) states: For some \(\varepsilon>0\) and every \(\delta>0\), \(0<|x-c|<\delta \Rightarrow |f(x)-L|<\varepsilon\). This is incorrect because it suggests \(\varepsilon\) is chosen before \(\delta\), which is contrary to needing \(\varepsilon\) for every \(\delta\).
3Step 3: Analyzing Option B
Option (b) suggests: For every \(\delta>0\), there is a corresponding \(\varepsilon>0\) such that \(0<|x-c|<\varepsilon \Rightarrow |f(x)-L|<\delta\). This is incorrect because it implies the wrong dependency—\(\varepsilon\) depends on \(\delta\) contrary to the proper definition.
4Step 4: Analyzing Option C
Option (c) states: For every positive integer \(N\), there is a corresponding positive integer \(M\) such that \(0<|x-c|<1/M \Rightarrow |f(x)-L|<1/N\). This adapts numberical equivalents (\(N\) and \(M\)) but maintains the dependency order and concept of the limit definition, thus it is correct.
5Step 5: Analyzing Option D
Option (d) states: For every \(\varepsilon>0\), there is a corresponding \(\delta>0\) such that \(0<|x-c|<\delta\) and \(|f(x)-L|<\varepsilon\) for some \(x\). This is incorrectly phrased because it requires the condition to be true only for 'some' \(x\) rather than 'every', which contradicts the proper definition.
Key Concepts
Epsilon-Delta DefinitionCalculusContinuityMathematical Proofs
Epsilon-Delta Definition
The epsilon-delta definition is a formal way to describe the behavior of limits in calculus. This definition is a cornerstone in understanding how functions behave as they approach a specific point. For the limit of a function \(f(x)\) as \(x\) approaches a point \(c\) to be \(L\), we must show that for every number \(\varepsilon > 0\), there is a corresponding number \(\delta > 0\). This means whenever \(0 < |x-c| < \delta\), then it will always follow that \(|f(x) - L| < \varepsilon\).
The procedure works by defining a window around the point \(c\) that gets increasingly smaller. As \(x\) falls within \(\delta\) distance from \(c\), \(f(x)\) should fall within \(\varepsilon\) distance from \(L\). The word "every" in the definition is crucial; it signifies that this relationship holds true no matter how small \(\varepsilon\) is. It intuitively captures the concept of approaching a value without necessarily reaching it.
The procedure works by defining a window around the point \(c\) that gets increasingly smaller. As \(x\) falls within \(\delta\) distance from \(c\), \(f(x)\) should fall within \(\varepsilon\) distance from \(L\). The word "every" in the definition is crucial; it signifies that this relationship holds true no matter how small \(\varepsilon\) is. It intuitively captures the concept of approaching a value without necessarily reaching it.
Calculus
Calculus is the branch of mathematics that studies change. It deals primarily with derivatives and integrals, concepts invented by Isaac Newton and Gottfried Wilhelm Leibniz. Limits are fundamental to calculus as they allow us to define these two key ideas.
- Derivatives measure how a function changes as its input changes. They also determine the slope of the curve at any point.
- Integrals determine the area under a curve, helping to calculate accumulated quantities, like distance traveled over time.
Continuity
Continuity is a smoothness feature of functions in calculus. A function is continuous at a point if small changes in the input result in small changes in the output. The function doesn't jump or have breaks at that point.
Formally, a function \(f(x)\) is said to be continuous at a point \(c\) if:\[ \lim_{{x \to c}} f(x) = f(c) \]
This means that as \(x\) approaches \(c\), \(f(x)\) approaches its value at that point, \(f(c)\). Continuity involves limits, and the epsilon-delta definition is often used to prove that a function is continuous at certain points.
Formally, a function \(f(x)\) is said to be continuous at a point \(c\) if:\[ \lim_{{x \to c}} f(x) = f(c) \]
This means that as \(x\) approaches \(c\), \(f(x)\) approaches its value at that point, \(f(c)\). Continuity involves limits, and the epsilon-delta definition is often used to prove that a function is continuous at certain points.
- One-sided limits must equal the function value from both directions.
- An interruption, or discontinuity, occurs if \(f(x)\) jumps or has gaps.
Mathematical Proofs
Mathematical proofs are logical arguments that verify the truth of a mathematical statement. They are vital in mathematics to ensure accuracy and to confirm that theories, like the epsilon-delta definition of limits, hold true.
In the case of proving a limit using the epsilon-delta definition:
In the case of proving a limit using the epsilon-delta definition:
- You start by assuming \(\varepsilon > 0\). Find a \(\delta > 0\) that suits our requirements.
- Show that when \(0 < |x-c| < \delta\), it follows \(|f(x) - L| < \varepsilon\).
- This requires algebraic manipulation and intuitive understanding of the behavior of \(f(x)\).
Other exercises in this chapter
Problem 31
Manhattan Island is said to have been bought by Peter Minuit in 1626 for \(\$ 24\). Suppose that Minuit had instead put the \(\$ 24\) in the bank at \(6 \%\) in
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Find the limits. $$ \lim _{x \rightarrow 5^{-}} \frac{x^{2}}{(x-5)(3-x)} $$
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, find \(\lim _{x \rightarrow 2}[f(x)-f(2)] /(x-2)\) for each given function \(\bar{f}\) $$ f(x)=3 x^{2} $$
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What points, if any, are the functions discontinuous? $$ f(x)=\left\\{\begin{array}{ll} x & \text { if } x1 \end{array}\right. $$
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