Problem 31
Question
Use the table feature of a graphing utility to find the first 10 terms of the sequences. (Assume \(n\) begins with 1.) $$a_{n}=(-1)^{n}+1$$
Step-by-Step Solution
Verified Answer
The first 10 terms of the sequence are 0, 2, 0, 2, 0, 2, 0, 2, 0, 2.
1Step 1: Understand the Sequence Formula
The sequence given is \(a_{n}=(-1)^{n}+1\), where \(n\) is the term number starting from 1. This formula uses exponentiation, and with its application, it generates the sequence.
2Step 2: Calculate the First Term
For \(n=1\), substitute \(n\) into the sequence formula: \(a_{1} = (-1)^{1} + 1 = -1 + 1 = 0\). So, the first term is 0.
3Step 3: Calculate the Second Term
For \(n=2\), substitute it into the sequence formula: \(a_{2} = (-1)^{2} + 1 = 1 + 1 = 2\). So, the second term is 2.
4Step 4: Calculate Terms Until the Tenth
Continue this process for \(n=3\) to \(n=10\) using the sequence formula. Notice that the sequence alternates between 0 and 2.
5Step 5: Observe the Sequence Pattern
By looking at the calculated values, you can see that the sequence alternates between 0 when \(n\) is odd, and 2 when \(n\) is even. This is reflected by the \((-1)^n\) part of the formula.
Key Concepts
Sequence FormulaAlternating SequenceGraphing UtilityTerm Calculation
Sequence Formula
A sequence formula is an expression that defines the terms of a sequence. In the exercise you're exploring, the sequence is given by the formula \(a_{n}=(-1)^{n}+1\). Let's break it down:
- \((-1)^n\) is an alternating component, switching signs depending on whether \(n\) (the term index) is odd or even.
- The "+1" shifts the value of the alternating sequence up by one.
Alternating Sequence
An alternating sequence is a type of sequence where the terms alternate between two or more values based on a consistent pattern. In the given sequence, \(a_{n} = (-1)^{n} + 1\), the primary alternating component is \((-1)^n\).
Here’s how it influences the sequence:
Here’s how it influences the sequence:
- When \(n\) is odd, for example \(n=1\), \((-1)^1 = -1\).
- When \(n\) is even, for example \(n=2\), \((-1)^2 = 1\).
- When \(n\) is odd, \(a_n = 0\) (because \(-1+1=0\)).
- When \(n\) is even, \(a_n = 2\) (because \(1+1=2\)).
Graphing Utility
A graphing utility is a tool, either digital like software or a calculator, used to visualize mathematical functions and data. In the context of sequences, graphing utilities are incredibly helpful.
Employing a graphing utility allows you to:
Employing a graphing utility allows you to:
- Plot the terms of a sequence to see visual patterns more readily than with numerical values alone.
- Utilize the table feature to quickly calculate and organize many terms of a sequence.
Term Calculation
Term calculation in a sequence means determining the value of each term based on its position (\(n\)) in the series. For sequences defined with a formula like \(a_{n}=(-1)^{n}+1\), term calculation involves substituting different values for \(n\) and simplifying the expression.
Here are steps for term calculation:
Here are steps for term calculation:
- Identify the formula: \(a_{n}=(-1)^{n}+1\).
- Substitute the term number (e.g., \(n=1, 2, 3\), etc.) into the formula.
- Calculate using the operations specified (exponentiation and addition in this case).
- For \(n=1\), the formula gives \((-1)+1=0\).
- For \(n=2\), it gives \(1+1=2\).
Other exercises in this chapter
Problem 30
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Write the first five terms of the arithmetic sequence. Use the table feature of a graphing utility to verify your results. $$a_{1}=5, d=6$$
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Find the probability for the experiment of drawing two marbles at random (without replacement) from a bag containing one green, two yellow, and three red marble
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