Problem 31
Question
Use series to evaluate the limits. \begin{equation} \lim _{t \rightarrow 0} \frac{1-\cos t-\left(t^{2} / 2\right)}{t^{4}} \end{equation}
Step-by-Step Solution
Verified Answer
The limit is \(-\frac{1}{24}\).
1Step 1: Recall Maclaurin Series for Cosine Function
The Maclaurin series expansion for the cosine function is given by:\[\cos t = 1 - \frac{t^2}{2!} + \frac{t^4}{4!} - \frac{t^6}{6!} + \cdots\]This series will be used to approximate the limit.
2Step 2: Simplify Expression Using Series
Substitute the Maclaurin series of \(\cos t\) into the given limit expression:\[1 - \cos t - \frac{t^2}{2} = 1 - \left(1 - \frac{t^2}{2} + \frac{t^4}{24} - \cdots \right) - \frac{t^2}{2}\]Simplify to get:\[1 - 1 + \frac{t^2}{2} - \frac{t^4}{24} - \frac{t^2}{2} \]which simplifies to \(-\frac{t^4}{24}\).
3Step 3: Evaluate the Limit
Substitute the simplified expression into the limit:\[\lim _{t \rightarrow 0} \frac{-t^4/24}{t^4} = \lim _{t \rightarrow 0} -\frac{1}{24} = -\frac{1}{24}\]The expression simplifies to a constant term as \(t^4\) terms cancel out.
Key Concepts
Series ExpansionLimit EvaluationTrigonometric Limits
Series Expansion
Series expansion is a way of representing functions as infinite sums of terms calculated from the values of their derivatives at a single point. This is especially useful for analyzing functions at points where direct evaluation is challenging. The Maclaurin series is a specific type of series expansion, representing a function as a series around the point 0.
The Maclaurin series for a function \( f(t) \) can be expressed as:
The Maclaurin series for a function \( f(t) \) can be expressed as:
- \( f(t) = f(0) + f'(0)t + \frac{f''(0)t^2}{2!} + \frac{f'''(0)t^3}{3!} + \,\cdots\)
- \( \cos t = 1 - \frac{t^2}{2!} + \frac{t^4}{4!} - \frac{t^6}{6!} + \,\cdots \)
Limit Evaluation
Limit evaluation is a fundamental concept in calculus, involving determining the behavior of a function as the variable approaches a specific value. This process is crucial for understanding behavior near points of indeterminacy, such as \lim_{t \rightarrow 0} \, where direct substitution renders an undefined or infinite expression.
To evaluate limits using series expansions, one substitutes the expanded form of a function into the given expression, then simplifies. In the given problem:
To evaluate limits using series expansions, one substitutes the expanded form of a function into the given expression, then simplifies. In the given problem:
- Substitute: The expansion of \( \cos t \) was substituted into the expression \( 1 - \cos t - \frac{t^2}{2} \).
- Simplify: This results in \( -\frac{t^4}{24} \) after cancellation and simplification.
- The remaining limit, \( \lim_{t \rightarrow 0} \frac{-t^4/24}{t^4} \), simplifies further to the constant \( -\frac{1}{24} \).
Trigonometric Limits
Trigonometric limits are specific limits involving trigonometric functions such as sine, cosine, and tangent. These often come up in calculus when dealing with derivatives and integrals of trigonometric functions. Understanding how to effectively handle these limits is crucial in solving a wide spectrum of calculus problems.
Typically, these limits require transformations to either simplify them or resolve expressions where direct substitution is ineffective. For instance, using the Maclaurin series simplifies the evaluation of such limits near zero.
In the limit \( \lim_{t \rightarrow 0} \frac{1-\cos t- \frac{t^2}{2}}{t^4} \):
Typically, these limits require transformations to either simplify them or resolve expressions where direct substitution is ineffective. For instance, using the Maclaurin series simplifies the evaluation of such limits near zero.
In the limit \( \lim_{t \rightarrow 0} \frac{1-\cos t- \frac{t^2}{2}}{t^4} \):
- The series form made it possible to transform the limit expression into a manageable state.
- Handling \( 1 - \cos t \) efficiently is crucial for evaluating trigonometric limits like this.
Other exercises in this chapter
Problem 30
In Exercises \(27-34,\) use the \(n\) th-Term Test for divergence to show that the series is divergent, or state that the test is inconclusive. $$ \sum_{n=1}^{\
View solution Problem 30
Which of the sequences \(\left\\{a_{n}\right\\}\) in Exercises \(27-90\) converge, and which diverge? Find the limit of each convergent sequence. $$ a_{n}=\frac
View solution Problem 31
Which of the series converge, and which diverge? Use any method, and give reasons for your answers. \begin{equation}\sum_{n=1}^{\infty} \frac{1}{1+\ln n}\end{eq
View solution Problem 31
Find the Taylor series generated by \(f\) at \(x=a.\) \(f(x)=\cos (2 x+(\pi / 2)), \quad a=\pi / 4\)
View solution