Problem 31
Question
Use a calculator to estimate \(f^{\prime}(a)\) for the given value of \(a\). $$f(x)=x \cos x ; a=\frac{\pi}{4}$$
Step-by-Step Solution
Verified Answer
The derivative \(f^{\prime}(a)\) is approximately 1.
1Step 1: Understand the Derivative Concept
The derivative of a function at a particular point gives the slope of the tangent line to the function at that point. In this exercise, you need to find the derivative of the function \(f(x) = x \cos x\) at \(a = \frac{\pi}{4}\).
2Step 2: Use the Definition of Derivative
The derivative of a function \(f\) at a point \(a\) can be estimated using the limit definition of derivative: \( f^{\prime}(a) \approx \frac{f(a+h) - f(a)}{h} \) for a small \(h\). Here, set \(h = 0.001\) or a similarly small value for precision.
3Step 3: Calculate \(f(a)\)
Find \(f(a)\) where \(a = \frac{\pi}{4}\): \[ f\left(\frac{\pi}{4}\right) = \frac{\pi}{4} \cos\left(\frac{\pi}{4}\right) \]Since \(\cos\left(\frac{\pi}{4}\right) = \frac{\sqrt{2}}{2}\), calculate\[ f\left(\frac{\pi}{4}\right) = \frac{\pi}{4} \times \frac{\sqrt{2}}{2} \approx 0.555 \]
4Step 4: Calculate \(f(a+h)\) for a Small \(h\)
Choose a small \(h\), for instance, 0.001, and calculate:\[ f\left(\frac{\pi}{4} + 0.001\right) = \left(\frac{\pi}{4} + 0.001\right) \cos\left(\frac{\pi}{4} + 0.001\right) \]Use the calculator to find this value. You'll find that it approximately equals 0.556.
5Step 5: Compute \(f^{\prime}(a)\) Using the Difference Quotient
Substitute the values into the difference quotient to find the derivative:\[ f^{\prime}\left(\frac{\pi}{4}\right) \approx \frac{0.556 - 0.555}{0.001} = 1 \]
Key Concepts
Limit Definition of DerivativeTangent LineTrigonometric Functions
Limit Definition of Derivative
Understanding the limit definition of a derivative is crucial in calculus. This definition helps us understand how a function behaves at a specific point, by estimating the slope of the tangent line. The formula is:
This method works because it mimics the process of taking a limit as \(h\) approaches zero.
Though we use a small nonzero value for \(h\) in practice, this gives us a close approximation. Setting \(h = 0.001\) is often precise. This is how we estimate the slope, which is synonymous with the derivative.
Using this approach, you can find how quickly the function is changing at a particular point, which is essential for deeper analysis in calculus.
- \( f^{\prime}(a) \approx \frac{f(a+h) - f(a)}{h} \)
This method works because it mimics the process of taking a limit as \(h\) approaches zero.
Though we use a small nonzero value for \(h\) in practice, this gives us a close approximation. Setting \(h = 0.001\) is often precise. This is how we estimate the slope, which is synonymous with the derivative.
Using this approach, you can find how quickly the function is changing at a particular point, which is essential for deeper analysis in calculus.
Tangent Line
The tangent line is an essential concept in understanding derivatives. When we talk about finding the derivative at a given point, we are essentially finding the slope of this tangent line.
The tangent line touches the curve of the function at exactly one point without crossing it.
This line shows the immediate rate of change of the function at that point. By calculating the derivative, we are determining this slope.
The tangent line touches the curve of the function at exactly one point without crossing it.
This line shows the immediate rate of change of the function at that point. By calculating the derivative, we are determining this slope.
- In our exercise, the function \(f(x) = x \cos x\) at \(a = \frac{\pi}{4}\) gives us a tangent line with a slope estimated to be 1.
Trigonometric Functions
Trigonometric functions, such as sine and cosine, play a crucial role in calculus and, by extension, in understanding derivatives.
Calculating derivatives of trigonometric functions often involves using identities like \(\cos\left(\frac{\pi}{4}\right) = \frac{\sqrt{2}}{2}\), which simplify calculations.
In our example, knowing the trigonometric value \(\cos\left(\frac{\pi}{4}\right)\) helps us estimate \(f(\frac{\pi}{4})\).
- The function \(f(x) = x \cos x\) combines both an algebraic term and a trigonometric term.
Calculating derivatives of trigonometric functions often involves using identities like \(\cos\left(\frac{\pi}{4}\right) = \frac{\sqrt{2}}{2}\), which simplify calculations.
In our example, knowing the trigonometric value \(\cos\left(\frac{\pi}{4}\right)\) helps us estimate \(f(\frac{\pi}{4})\).
- This foundational knowledge enables you to examine how trigonometric functions change and how their slopes are determined at specific points. This understanding is pivotal in numerous applications across mathematics and engineering.
Other exercises in this chapter
Problem 30
Use a table and/or graph to decide whether each limit exists. If a limit exists, find its value. \(\lim _{x \rightarrow-1} \sqrt{5+3 x}\)
View solution Problem 30
Determine each limit, if it exists. $$\lim _{x \rightarrow-1} \frac{(x+1)^{2}}{2 x^{2}-x-3}$$
View solution Problem 31
Determine each limit. \(f(x)=\frac{x}{(4-x)^{3}}\) (a) \(\lim _{x \rightarrow 4^{+}} f(x)\) (b) \(\lim _{x \rightarrow 4^{-}} f(x)\)
View solution Problem 31
Use a table and/or graph to decide whether each limit exists. If a limit exists, find its value. \(\lim _{x \rightarrow 5} \frac{x^{2}-3 x-10}{x-5}\)
View solution