Problem 31
Question
The reaction $$ 2 \mathrm{NO}(\mathrm{g})+2 \mathrm{H}_{2}(\mathrm{~g}) \longrightarrow \mathrm{N}_{2}(\mathrm{~g})+2 \mathrm{H}_{2} \mathrm{O}(\mathrm{g}) $$ is found to be first-order in \(\mathrm{H}_{2}(\mathrm{~g}) .\) Which rate equation cannot be correct? (a) Rate \(=k[\mathrm{NO}]^{2}\left[\mathrm{H}_{2}\right]\) (b) Rate \(=k\left[\mathrm{H}_{2}\right]\) $$ \text { (c) Rate }=k\left[\mathrm{NOl}^{2}\left[\mathrm{H}_{3}\right]^{2}\right. $$
Step-by-Step Solution
Verified Answer
Option (c) is incorrect.
1Step 1: Understanding Reaction Order
The problem states that the reaction is first-order with respect to \(\mathrm{H}_2\). This means the rate of the reaction is directly proportional to the concentration of \(\mathrm{H}_2\). The power of the concentration term for \(\mathrm{H}_2\) in the rate equation should be 1.
2Step 2: Analyzing Rate Equations
Let's analyze each given rate equation to determine if they align with the first-order condition for \(\mathrm{H}_2\):(a) Rate \(=k[\mathrm{NO}]^{2}[\mathrm{H}_{2}]\) - The order with respect to \(\mathrm{H}_2\) is 1, which is consistent.(b) Rate \(=k[\mathrm{H}_{2}]\) - This equation is also consistent as it has a power of 1 for \(\mathrm{H}_2\).(c) Rate \(=k[\mathrm{NO}]^{2}[\mathrm{H}_{3}]^{2}\) - This equation mistakenly uses \(\mathrm{H}_3\) instead of \(\mathrm{H}_2\) and shows a second-order term for \(\mathrm{H}_2\), which is incorrect.
3Step 3: Identifying the Incorrect Equation
Since the reaction is first-order in \(\mathrm{H}_2\), any rate equation suggesting otherwise is incorrect. Option (c) has the mistake of indicating a second-order dependency for \(\mathrm{H}_2\) with a term \([\mathrm{H}_{2}]^2\), and the chemical species are incorrect due to \(\mathrm{H}_3\). Thus, option (c) cannot be correct.
Key Concepts
Reaction OrderRate EquationFirst-order Reactions
Reaction Order
In the realm of chemical kinetics, the term **reaction order** is crucial in understanding how different substances influence the rate of a chemical reaction. This concept reflects how the concentration of one or more reactants affects the rate at which the product is formed. More specifically, it relates to the exponent used in the rate equation for a particular reactant.
- If the order with respect to a reactant is 1, it implies that the rate of reaction is directly proportional to the concentration of that reactant.
- For a zero-order reaction, the rate is unaffected by changes in concentration.
- If the order is 2, the rate is proportional to the square of the reactant's concentration.
Rate Equation
The **rate equation** is an invaluable tool in chemistry, providing a mathematical description of the relationship between the reaction rate and the concentrations of reactants. Each component of the equation corresponds to a reagent and its respective reaction order: \[ ext{Rate} = k[A]^m[B]^n\] In this general form:
- \(k\) is the rate constant specific to a reaction at a given temperature.
- \([A]\) and \([B]\) are the concentrations of the reactants.
- \(m\) and \(n\) are the orders of the reaction with respect to reactants \(A\) and \(B\), respectively.
First-order Reactions
When we discuss **first-order reactions**, we are focusing on reactions where the rate is directly proportional to the concentration of a single reactant. This type of reaction is common and easier to predict and analyze compared to higher-order reactions.The rate law for a first-order reaction can be expressed as:\[ ext{Rate} = k[A]\]In this expression:- \(A\) is the reactant whose concentration directly influences the rate.- \(k\) is the rate constant.A characteristic feature of first-order reactions is their exponential nature. As the reaction progresses, the concentration of the reactant decreases exponentially, which can be represented by the formula:\[[A] = [A]_0e^{-kt}\]This formula helps chemists determine how the concentration changes with time, aiding in reaction monitoring and optimization.Such simplicity in kinetics makes first-order reactions particularly favorable for initial studies in chemical kinetics, helping students and professionals alike gain insight into reaction mechanisms.
Other exercises in this chapter
Problem 29
For each of the rate laws below, determine the order of the reaction with respect to the hypothetical substances \(\mathrm{X}, \mathrm{Y},\) and \(\mathrm{Z}\).
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The decomposition of ammonia to nitrogen and hydrogen on tungsten at \(1100^{\circ} \mathrm{C}\) is zeroth-order with a rate constant of \(2.5 \times 10^{-4} \m
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When phenacyl bromide and pyridine are both dissolved in methanol, they react to form phenacylpyridinium bromide. \(\mathrm{C}_{6} \mathrm{H}_{5}-\stackrel{\mat
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