Problem 31
Question
The range of the function \(f(x)=\frac{\sin \left(\pi\left[x^{2}+1\right]\right)}{x^{4}+1}\) where, [ ] is greatest integer function, is (A) \([0,1]\) (B) \([-1,1]\) (C) \(\\{0\\}\) (D) None of these
Step-by-Step Solution
Verified Answer
The range of the function is \(\{0\}\).
1Step 1: Understand the Function
The function is given by \(f(x) = \frac{\sin\left(\pi\left[x^2 + 1\right]\right)}{x^4 + 1}\). Here, \([x^2 + 1]\) represents the greatest integer less than or equal to \(x^2 + 1\).
2Step 2: Analyze the Greatest Integer Function
For any real number \(x\), \(x^2\) is non-negative. Thus, \(x^2 + 1\) ranges from \(1\) to \(\infty\). The greatest integer function \([x^2 + 1]\) will then be an integer \(n\) greater than or equal to 1.
3Step 3: Evaluate the Sine Function
For integer \(n\), \(\sin(\pi n)\) equals 0 because the sine of any multiple of \(\pi\) is 0. Therefore, \(\sin(\pi[x^2 + 1]) = 0\) for any \(x\).
4Step 4: Express the Function
Since the sine function in the numerator is 0 for any \(x\), we can see that \(f(x) = \frac{0}{x^4 + 1} = 0\) for all \(x\).
5Step 5: Determine the Range
The range of a function is the set of possible values for \(f(x)\) as \(x\) varies over all real numbers. Since \(f(x) = 0\) for all \(x\), the range of this function is \(\{0\}\).
Key Concepts
Greatest Integer FunctionTrigonometric FunctionsFunction Analysis
Greatest Integer Function
The greatest integer function, often denoted by the square bracket symbols \([x]\), is a key mathematical concept that helps in stepping down a real number to its largest previous integer. In a more formal sense, for a given real number \(x\), the expression \[ [x] = n \] gives the greatest integer \(n\) such that \(n \leq x\).
This function has unique properties:
This function has unique properties:
- The output is always an integer. So, this function essentially "chops off" the decimal part and retains only the integer portion.
- It is non-decreasing as the \(x\) increases. That means \([x] < [x+1]\) if \(x\) is not already an integer.
- This function is often used when discrete values are necessary from continuous inputs.
Trigonometric Functions
Trigonometric functions relate angles of triangles to ratios between sides. The sine function, one of the key trigonometric functions, oscillates between \(-1\) and \(1\) and repeats its pattern every \(2\pi\) radians. An essential property is that sine of multiples of \(\pi\), is zero. This plays a critical role in the given problem.
When we observe the function \(f(x) = \frac{\sin(\pi[x^2 + 1])}{x^4 + 1}\), the sine component \(\sin(\pi[x^2 + 1])\) is evaluated at integer multiples of \(\pi\), making it zero. This results because:
When we observe the function \(f(x) = \frac{\sin(\pi[x^2 + 1])}{x^4 + 1}\), the sine component \(\sin(\pi[x^2 + 1])\) is evaluated at integer multiples of \(\pi\), making it zero. This results because:
- For any integer \(n\), \[ \sin(\pi n) = 0 \].
- The sine function's behavior simplifies the analysis of the numerator, leading the entire function to become zero.
- This effect is identical and amplified when combined with other functions like the greatest integer function in our exercise.
Function Analysis
Function analysis involves examining the various characteristics of a function, such as domain, range, limits, and behavior. In general, it involves thoroughly understanding how a function behaves over its inputs to predict its outputs. Breaking down each feature helps unravel complex functions into understandable parts.
In the function \(f(x) = \frac{\sin(\pi[x^2 + 1])}{x^4 + 1}\), function analysis is executed by:
In the function \(f(x) = \frac{\sin(\pi[x^2 + 1])}{x^4 + 1}\), function analysis is executed by:
- Determining the domain: The function is defined for all real numbers \(x\) because both the sine and polynomial in the denominator are defined everywhere.
- Finding its behavior: Since \(\sin(\pi[x^2 + 1]) = 0\) for all \(x\), the behavior of the function simplifies to being zero regardless of \(x\).
- Identifying the range: Since every output of \(f(x)\) is zero, the function's range is simply \({0}\).
- Ensuring the denominator isn't zero which \(x^4 + 1\) fulfills as it's always positive.
Other exercises in this chapter
Problem 29
The function \(f:(-\infty,-1] \rightarrow\left(0, e^{5}\right]\) defined by, \(f(x)=e^{x^{3}-3 x+2}\) is (A) Many one and onto (B) Many one and into (C) One-one
View solution Problem 30
The domain of the function \(f(x)=\log _{2}\left(-\log _{1 / 2}\left(1+\frac{1}{\sqrt[4]{x}}\right)-1\right)\) is (A) \(01\)
View solution Problem 32
If \(a f(x)+b f\left(\frac{1}{x}\right)=x+\frac{5}{x},(a \neq b)\), then \(f(x)\) is equal to (A) \(\frac{1}{a^{2}-b^{2}}\left(x+\frac{1}{x}\right)\) (B) \(\fra
View solution Problem 33
Let \(f: R \rightarrow R\) defined by, \(f(x)=x^{3}+x^{2}+100 x+5 \sin x\), then \(f\) is (A) many-one onto (B) many-one into (C) one-one onto (D) one-one into
View solution