Problem 31
Question
Subtract the polynomials using the vertical format. \(5 x-2\) from \(12 x+6\)
Step-by-Step Solution
Verified Answer
The result is \(7x + 8\).
1Step 1: Arrange Vertically
Write the two polynomials vertically, aligning the like terms. The polynomial to be subtracted, \(5x - 2\), is written below \(12x + 6\). It looks like this:\[\begin{array}{r}12x + 6 \- (5x - 2)\end{array}\]
2Step 2: Subtract Coefficients of Like Terms
Subtract the coefficients of the \(x\) terms and the constant terms separately. Start from the left of the polynomials:- For the \(x\) terms: \(12x\) minus \(5x\) equals \(7x\).- For the constant terms: \(6\) minus \(-2\) equals \(8\) because subtracting a negative is the same as adding.The result is:\(7x + 8\).
3Step 3: Write the Final Expression
Combine the results from Step 2 to write the final expression as:\[7x + 8\]
Key Concepts
Vertical FormatLike TermsSubtracting CoefficientsNegative Numbers in Subtraction
Vertical Format
When subtracting polynomials, the vertical format is a convenient way to organize and visually process the equation. Just like adding large numbers, arranging polynomials in vertical format helps keep track of like terms more accurately. In this process, you align the polynomials vertically. Make sure each term lines up, so variables and powers match correctly.
In our example, we have:
In our example, we have:
- The polynomial, \(12x + 6\), on top.
- The polynomial, \(5x - 2\), directly below it.
Like Terms
"Like terms" are terms within polynomials that have the same variable raised to the same power. In subtraction, always focus on these terms, as they are the only ones that can be directly combined by addition or subtraction.
For example, in the equation:
For example, in the equation:
- The terms \(12x\) and \(5x\) are like terms because both contain \(x\) raised to the first power.
- Constant numbers, like \(6\) and \(-2\), are also like terms.
Subtracting Coefficients
After like terms are aligned, the next step is to subtract their coefficients. Coefficients are the numerical parts in front of the variables. The key here is to deal with each pair of coefficients separately.
In our example:
In our example:
- For terms with \(x\), subtract \(5\) from \(12\), giving you \(7x\).
- For constant terms, subtract \(-2\) from \(6\). Remember that subtracting a negative is equivalent to adding, resulting in \(6 + 2 = 8\).
Negative Numbers in Subtraction
Working with negative numbers in subtraction can be tricky, but it becomes simple once you grasp the rule that subtracting a negative number is like adding its absolute value. This is crucial when we get to terms like the constant \(-2\) in our example.
Think about the expression "minus a negative" as "plus the positive." So when subtracting
Think about the expression "minus a negative" as "plus the positive." So when subtracting
- \(-2\) from \(6\), you are actually performing \(6 + 2 = 8\).
Other exercises in this chapter
Problem 31
Find each indicated product. Remember the shortcut for multiplying binomials and the other special patterns we discussed in this section. $$(y-7)^{2}$$
View solution Problem 31
Find each product. $$(-a b)(-3 a b)(-6 a b)$$
View solution Problem 32
Solve each equation. You will need to use the factoring techniques that we discussed throughout this chapter. $$20 x^{2}+41 x+20=0$$
View solution Problem 32
Factor completely each of the polynomials and indicate any that are not factorable using integers. $$6 x^{2}+13 x-33$$
View solution