Problem 31
Question
Solve the equation if possible. $$ 24-6 r=6(4-r) $$
Step-by-Step Solution
Verified Answer
The equation is true for all real values of \(r\).
1Step 1: Distribute the 6 on the right side of the equation
The right side of the equation is \(6(4-r)\). To simplify, distribute the 6 into the parentheses: \(24 - 6r = 24 - 6r\).
2Step 2: Verify if the equation is true
After the distribution in step 1, both sides of the equation became identical, so the original equation is an identity and holds true for any real value of \(r\).
Key Concepts
Distributive PropertyIdentity EquationReal Numbers
Distributive Property
The distributive property is a fundamental algebraic principle that helps simplify equations and expressions. It's especially useful when you have numbers or variables inside parentheses. Essentially, the distributive property tells us how to multiply a number with a sum or difference inside parentheses.
- It simply states: \( a(b + c) = ab + ac \)
- This means you multiply the number outside the parentheses ("a" in this case) by each of the terms inside the parentheses ("b" and "c").
- \( 6(4 - r) \) means multiplying 6 by both 4 and \( -r \).
- Thus, \( 6 \times 4 \) equals 24 and \( 6 \times -r \) results in \( -6r \).
- Putting these results together, you get \( 24 - 6r \).
Identity Equation
An identity equation is a fascinating concept in mathematics. It’s an equation that is always true, no matter what value you substitute for the variable. This makes it unique because it holds for all numbers, not just specific ones.
- If after simplifying an equation, both sides are identical (like in the original exercise: \( 24 - 6r = 24 - 6r \)), it indicates that the equation is an identity.
- Unlike conditional equations, which are true for specific values of the variable, identity equations are universally true.
Real Numbers
Real numbers are the set of all numbers that you would typically use in everyday life. They include:
- Natural numbers (1, 2, 3, ...)
- Whole numbers (0, 1, 2, 3, ...)
- Integers (..., -3, -2, -1, 0, 1, 2, 3, ...)
- Rational numbers (fractions like \( \frac{1}{2} \) or \( 3.5 \))
- Irrational numbers (like \( \pi \) or \( \sqrt{2} \))
Other exercises in this chapter
Problem 31
Rewrite the equation so that \(x\) is a function of \(y .\) Then use the result to find \(x\) when \(y=-2,-1,0,\) and 1. $$3 y-x=12$$
View solution Problem 31
Solve the equation. $$|-6|+y=11$$
View solution Problem 31
Solve the equation. Round the result to the nearest hundredth. Check the rounded solution. $$ -(d-3)=2(3 d+1) $$
View solution Problem 31
Solve the equation. $$8 x=3$$
View solution