Problem 31
Question
Sketch the graph of the rational function. To aid in sketching the graphs, check for intercepts, symmetry, vertical asymptotes, and horizontal asymptotes. $$f(x)=\frac{1}{x+3}$$
Step-by-Step Solution
Verified Answer
The graph of the function \(f(x)=\frac{1}{x+3}\) has a y-intercept at (0, 1/3), a vertical asymptote at x = -3, and a horizontal asymptote at y = 0. It is not symmetric about the y-axis or the origin.
1Step 1: Intercepts
Find where the function intersects the x-axis and the y-axis. The x-intercept is found when f(x) = 0. For the given function, f(x)=(1/(x+3)), the function will never equals 0, hence there are no x-intercepts. The y-intercept is found by evaluating the function at x = 0. In the given function, at x=0 the function f(x) becomes f(0)= 1/3, hence the y-intercept is at (0, 1/3).
2Step 2: Symmetry
This function f(x)=(1/(x+3)) is not symmetrical around the y-axis or the origin. The function does not pass the vertical line test for symmetry about the y-axis or the origin. The test is to replace x with -x in the equation and see if the same equation results. Here this is not the case, thus the graph isn't symmetric.
3Step 3: Vertical Asymptotes
A vertical asymptote is found when the function approaches infinity. For the function f(x)=(1/(x+3)), this happens when the denominator equals zero, i.e., when x+3 = 0, hence at x = -3. So, the function has a vertical asymptote at x = -3.
4Step 4: Horizontal asymptotes
A function has a horizontal asymptote if, as the function approaches positive or negative infinity, the function approaches a certain constant. In the case of the function f(x)=(1/(x+3)), as x approaches positive or negative infinity, the function approaches 0. Therefore, the function has a horizontal asymptote of y = 0.
Key Concepts
InterceptsAsymptotesGraph SketchingSymmetry
Intercepts
When working with rational functions like \( f(x) = \frac{1}{x+3} \), finding intercepts helps you understand where the graph crosses the axes.
- X-intercept: This is where the graph crosses the x-axis, meaning \( f(x) = 0 \). For rational functions, the numerator must be zero for there to be an x-intercept. Since the numerator is 1 and never zero, there are no x-intercepts for this function.
- Y-intercept: This is where the graph crosses the y-axis, found by evaluating \( f(x) \) at \( x = 0 \). For \( f(x) = \frac{1}{x+3} \), plugging in \( x = 0 \) gives \( f(0) = \frac{1}{3} \). Thus, the y-intercept is at \( (0, \frac{1}{3}) \).
Asymptotes
Asymptotes are lines that the graph of a function approaches but never actually touches or crosses. They help in understanding how the graph behaves at extreme values of x.
- Vertical Asymptote: Occurs where the function is undefined. For \( f(x) = \frac{1}{x+3} \), the denominator is zero when \( x = -3 \), which creates a vertical asymptote at this point.
- Horizontal Asymptote: Describes the behavior of the graph as \( x \) approaches positive or negative infinity. For this function, as \( x \) heads toward infinity, \( f(x) \) approaches 0. Hence, it has a horizontal asymptote at \( y = 0 \).
Graph Sketching
Graph sketching for rational functions involves integrating information about intercepts and asymptotes.
- Start by plotting intercepts, as we have a y-intercept at \( (0, \frac{1}{3}) \).
- Draw the vertical asymptote at \( x = -3 \). The graph will never touch this line, instead, it will stretch towards infinity as it approaches \( x = -3 \) from both sides.
- Include the horizontal asymptote at \( y = 0 \). This indicates that as \( x \) moves far left or right, \( f(x) \) gets closer and closer to zero.
Symmetry
Symmetry in a graph can make sketching easier and often reveals interesting properties about the function. For \( f(x) = \frac{1}{x+3} \), checking for symmetry can help in understanding the function's balance or any pattern it may follow.
- To check for y-axis symmetry, substitute \( -x \) for \( x \) and see if the result is the original function. This doesn't hold here as \( f(-x) = \frac{1}{-x+3} \) is not equivalent to \( f(x) \).
- For origin symmetry, replacing \( x \) with \( -x \) and \( f(x) \) with \( -f(x) \) should give an equivalent function. Again, this condition is not satisfied.
Other exercises in this chapter
Problem 31
Use synthetic division to divide. Divisor \(x-2\) Dividend $$-3 x^{4}$$
View solution Problem 31
Sketch the graph of the quadratic function. Identify the vertex and intercepts. $$f(x)=-x^{2}+2 x+5$$
View solution Problem 31
Find all the zeros of the function and write the polynomial as a product of linear factors. $$f(x)=x^{4}+10 x^{2}+9$$
View solution Problem 31
Perform the indicated operation and write the result in standard form. $$(\sqrt{-10})^{2}$$
View solution