Problem 31
Question
Simplify and reduce each expression. $$ 3 x^{2}+19 x+20=0 $$
Step-by-Step Solution
Verified Answer
The roots of the equation are \( x = \frac{-4}{3} \) and \( x = -5 \).
1Step 1: Identify the Quadratic Equation
We are given the quadratic equation in the form \( ax^2 + bx + c = 0 \). Here, \( a = 3 \), \( b = 19 \), and \( c = 20 \).
2Step 2: Apply the Quadratic Formula
The quadratic formula is \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \). We'll substitute the values of \( a \), \( b \), and \( c \) into this formula.
3Step 3: Calculate the Discriminant
First, find the discriminant \( \Delta = b^2 - 4ac \). This helps determine the nature of the roots. Substitute \( b = 19 \), \( a = 3 \), and \( c = 20 \) to get \( \Delta = 19^2 - 4(3)(20) = 361 - 240 = 121 \).
4Step 4: Determine the Roots Using the Discriminant
Since \( \Delta = 121 \) is a perfect square, the roots are real and rational. Use \( x = \frac{-19 \pm \sqrt{121}}{6} \), where \( \sqrt{121} = 11 \).
5Step 5: Simplify for Each Root
Calculate each root. For the positive square root: \( x_1 = \frac{-19 + 11}{6} = \frac{-8}{6} = \frac{-4}{3} \). For the negative square root: \( x_2 = \frac{-19 - 11}{6} = \frac{-30}{6} = -5 \).
Key Concepts
Quadratic FormulaDiscriminantReal and Rational Roots
Quadratic Formula
The quadratic formula is a powerful tool used to solve quadratic equations of the form \( ax^2 + bx + c = 0 \). This formula is particularly useful when factoring is difficult or impossible. The formula is given as:\[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]This means that, by substituting the coefficients \( a \), \( b \), and \( c \) from the equation, we can effectively find the values of \( x \) that solve the equation. Let’s break it down:
- - **\( b \):** The coefficient of \( x \).
- - **\( a \):** The coefficient of \( x^2 \).
- - **\( c \):** The constant term.
Discriminant
The discriminant is a key component of the quadratic formula, given by the expression \( b^2 - 4ac \). It plays a crucial role in determining the nature of the roots we might find from a quadratic equation. Here is why the discriminant is vital:
- - **It helps us determine the type of roots:**
- If \( \Delta > 0 \), the roots are real and distinct.
- If \( \Delta = 0 \), the roots are real and equal.
- If \( \Delta < 0 \), the roots are complex and not real.
- - **Calculates the number of solutions:** As \( \Delta \) changes, so does the nature of the solutions.
Real and Rational Roots
When we talk about real and rational roots in the context of quadratic equations, we're referring to specific solutions where the values of \( x \) are both real numbers and rational numbers. Here's what that means:
- - **Real roots:** Solutions that exist on the number line. These can be plotted and seen visually.
- - **Rational roots:** Roots that can be expressed as fractions or whole numbers. Essentially, they can be written as \( \frac{p}{q} \) where \( p \) and \( q \) are integers and \( q eq 0 \).
Other exercises in this chapter
Problem 31
Solve each inequality. $$ 4\left(x^{2}-36\right)
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Solve each equation. $$ \frac{5}{n-3}-\frac{3}{n+3}=1 $$
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Use the method of completing the square to solve each quadratic equation. $$ y^{2}-7 y+3=0 $$
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Write each of the following in terms of \(i\) and simplify. $$ \sqrt{-\frac{16}{25}} $$
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