Problem 31
Question
Show that if \(A^{c}\) is the complement of \(A\), that is, the set of all outcomes in the sample space \(S\) that are not in \(A\), then \(P\left(A^{c}\right)=1-P(A)\).
Step-by-Step Solution
Verified Answer
The probability of the complement event is \( P(A^{c}) = 1 - P(A) \).
1Step 1: Define the Sample Space and Events
The sample space, denoted as \( S \), is the set of all possible outcomes of an experiment. An event \( A \) is any subset of \( S \). The complement of an event \( A \), denoted as \( A^{c} \), consists of all outcomes in \( S \) that are not in \( A \).
2Step 2: Apply Total Probability
The total probability of the sample space \( S \) is always 1, i.e., \( P(S) = 1 \). Events \( A \) and \( A^{c} \) together cover the entire sample space without overlap, meaning \( A \cup A^{c}= S \) and \( A \cap A^{c} = \emptyset \).
3Step 3: Use Probability Addition Rule
The probability of the union of two mutually exclusive events is the sum of their probabilities: \( P(A \cup A^{c}) = P(A) + P(A^{c}) \). Since \( A \cup A^{c} = S \), we have \( P(S) = P(A) + P(A^{c}) \).
4Step 4: Solve for the Complement's Probability
Given that \( P(S) = 1 \), from Step 3, we substitute: \( 1 = P(A) + P(A^{c}) \). We can rearrange to show \( P(A^{c}) = 1 - P(A) \). Thus, the probability of the complement is equal to one minus the probability of the event.
Key Concepts
Sample SpaceComplement of an EventMutually Exclusive Events
Sample Space
In probability theory, the "sample space" is a foundational concept. It represents the set of all possible outcomes that can occur in a particular experiment. Imagine flipping a coin — the sample space here includes two outcomes: heads and tails.
- Denoted by the symbol \( S \), it encompasses every possible result.
- This set is crucial because it defines the range within which probabilities are calculated.
Complement of an Event
The "complement of an event" refers to everything within the sample space that does not contribute to that event. Simply put, if you have an event \( A \), its complement, noted as \( A^c \), includes all outcomes in the sample space \( S \) that are not part of \( A \).
- The idea here is to account for all possibilities: either something happens (event \( A \)), or it doesn’t (event \( A^c \)).
- Mathematically, complements help us determine probabilities of events indirectly. If you know the probability of an event, the complement's probability is just what's left: \( P(A^c) = 1 - P(A) \).
Mutually Exclusive Events
When we discuss "mutually exclusive events," we're referring to events that cannot happen at the same time. Think of rolling a single die — getting a 1 and getting a 2 are mutually exclusive outcomes because both cannot occur simultaneously.
- If two events \( A \) and \( B \) are mutually exclusive, then \( A \cap B = \emptyset \)—they share no outcomes.
- The probability rule for these events is straightforward: \( P(A \cup B) = P(A) + P(B) \) because there's no overlap or double-counting needed.
Other exercises in this chapter
Problem 30
Sketch the region bounded by the graphs of the given equations, show a typical slice, approximate its area, set up an integral, and calculate the area of the re
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Find the area of the surface generated by revolving the given curve about the \(x\) -axis \(y=\sqrt{r^{2}-x^{2}},-r \leq x \leq r\)
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Sketch the region \(R\) bounded by \(y=x+6, y=x^{3}\), and \(2 y+x=0 .\) Then find its area. Hint: Divide \(R\) into two pieces.
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