Problem 31
Question
Let \(x\) be a continuous random variable that is normally distributed with mean \(\mu=22\) and standard deviation \(\sigma=5 .\) Using Table A, find the following. $$ P(x \geq 20) $$
Step-by-Step Solution
Verified Answer
The probability that \(x\) is greater than or equal to 20 is approximately 0.6554.
1Step 1: Understand the Problem
We need to find the probability that a random variable, which is normally distributed with a mean \(\mu = 22\) and standard deviation \(\sigma = 5\), takes a value greater than or equal to 20.
2Step 2: Standardize the Variable
Convert the variable to a standard normal variable \(Z\). The formula to convert \(x\) to \(z\) is \( z = \frac{x - \mu}{\sigma} \). So, for \(x = 20\), \( z = \frac{20 - 22}{5} = \frac{-2}{5} = -0.4 \).
3Step 3: Use Standard Normal Distribution Table
Look up the Z-table (Table A) to find \( P(Z \geq -0.4) \). Tables typically provide \( P(Z \leq z) \), so we find \( P(Z \leq -0.4) \) first. Looking up the value \(-0.4\), we find \( P(Z \leq -0.4) = 0.3446 \).
4Step 4: Calculate the Desired Probability
Since \( P(Z \geq -0.4) = 1 - P(Z \leq -0.4) \), calculate \( P(X \geq 20) = 1 - 0.3446 = 0.6554 \).
Key Concepts
Standard Normal DistributionZ-score CalculationProbability Calculation
Standard Normal Distribution
The concept of a **Standard Normal Distribution** is a special case of the normal distribution. A standard normal distribution is a continuous probability distribution that follows a normal pattern but is centered around a mean of 0 and has a standard deviation of 1.
Here's what makes it so special and practical:
Here's what makes it so special and practical:
- It's symmetric around the mean.
- The total area under the curve equals 1, representing a whole probability.
- Approximately 68% of the data falls within one standard deviation of the mean, 95% within two, and 99.7% within three, following the empirical rule.
Z-score Calculation
A **Z-score Calculation** is key when working with data following a normal distribution. The Z-score is a measure of how many standard deviations an element is from the mean. By converting a value from a normal distribution to a Z-score, we can understand its position relative to the mean.
The process:
The process:
- Identify the mean (33) and the standard deviation (33) of the distribution.
- Using the formula: \( z = \frac{x - \mu}{\sigma} \), calculate the Z-score. Here, \( \mu \) is the mean, \( \sigma \) is the standard deviation, and \( x \) is the value to convert.
- An example conversion would result in a Z-score that indicates how far 20 is from the average of 22 given a standard deviation of 5.
Probability Calculation
**Probability Calculation** is a crucial step in determining the likelihood that a continuous random variable falls within a certain range in a distribution. Once you calculate a Z-score, the next step involves reading the standard normal distribution table (often called the Z-table).
Steps to perform a probability calculation:
Steps to perform a probability calculation:
- Look up the Z-score value in the Z-table to find a probability value, \( P(Z \leq z) \).
- The Z-table provides cumulative probabilities from the left, so these values tell us the proportion of values below a given Z-score.
- If you need the probability that a value is greater than a certain point, like in our example of \( P(x \geq 20) \), you'll calculate it as \( 1 - P(Z \leq -0.4) \), giving you the area to the right of that Z-score.
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