Problem 31
Question
Let \(\mathbf{u}, \mathbf{v},\) and \(\mathbf{w}\) be vectors. Which of the following make sense, and which do not? Give reasons for your answers. $$ \begin{array}{ll}{\text { a. }(\mathbf{u} \times \mathbf{v}) \cdot \mathbf{w}} & {\text { b. } \mathbf{u} \times(\mathbf{v} \cdot \mathbf{w})} \\\ {\mathbf{c} . \mathbf{u} \times(\mathbf{v} \times \mathbf{w})} & {\text { d. } \mathbf{u} \cdot(\mathbf{v} \cdot \mathbf{w})}\end{array} $$
Step-by-Step Solution
Verified Answer
a and c are valid; b and d are not valid.
1Step 1: Understanding Cross and Dot Products
The cross product \( \mathbf{u} \times \mathbf{v} \) results in a vector that is perpendicular to both \( \mathbf{u} \) and \( \mathbf{v} \), and is only defined for three-dimensional vectors. The dot product \( \mathbf{u} \cdot \mathbf{v} \) results in a scalar and is defined for vectors of the same dimension.
2Step 2: Evaluate Expression a: \((\mathbf{u} \times \mathbf{v}) \cdot \mathbf{w}\)
\((\mathbf{u} \times \mathbf{v}) \) is a vector. Since \((\mathbf{u} \times \mathbf{v}) \cdot \mathbf{w} )\) is a dot product between two vectors, it is a valid expression, resulting in a scalar.
3Step 3: Evaluate Expression b: \(\mathbf{u} \times (\mathbf{v} \cdot \mathbf{w})\)
\((\mathbf{v} \cdot \mathbf{w})\) is a scalar. Since we cannot take a cross product between a vector and a scalar, this expression is not valid.
4Step 4: Evaluate Expression c: \((\mathbf{u} \times (\mathbf{v} \times \mathbf{w})\)
\((\mathbf{v} \times \mathbf{w})\) is a vector, so \(\mathbf{u} \times (\mathbf{v} \times \mathbf{w}) \) is defined as the cross product of two vectors, resulting in another vector. Therefore, this expression is valid.
5Step 5: Evaluate Expression d: \(\mathbf{u} \cdot (\mathbf{v} \cdot \mathbf{w})\)
\(\mathbf{v} \cdot \mathbf{w}\) results in a scalar. However, the dot product \(\mathbf{u} \cdot (\text{scalar})\) is not defined because the dot product should be between two vectors. Thus, this expression is not valid.
Key Concepts
Cross ProductDot ProductVectorsScalar Multiplication
Cross Product
The cross product is an essential operation in vector mathematics, particularly for three-dimensional vectors. Calculating the cross product of two vectors results in another vector that is orthogonal, or perpendicular, to the original two. This means if you have vectors \( \mathbf{u} \) and \( \mathbf{v} \), the cross product \( \mathbf{u} \times \mathbf{v} \) will give you a vector pointing out of the plane formed by \( \mathbf{u} \) and \( \mathbf{v} \).
The formula used to find the cross product is based on a determinant and can be expressed as:
The formula used to find the cross product is based on a determinant and can be expressed as:
- \( \mathbf{u} = \langle a_1, b_1, c_1 \rangle \)
- \( \mathbf{v} = \langle a_2, b_2, c_2 \rangle \)
- \( \mathbf{u} \times \mathbf{v} = \langle b_1c_2 - c_1b_2, c_1a_2 - a_1c_2, a_1b_2 - b_1a_2 \rangle \)
Dot Product
The dot product is another fundamental operation in vector calculations, defined for two vectors of the same dimension, producing a scalar. Unlike the cross product, the dot product measures how much one vector goes in the direction of another vector, hence often being described as a measure of similarity in direction.
The dot product of vectors \( \mathbf{u} = \langle a_1, b_1, c_1 \rangle \) and \( \mathbf{v} = \langle a_2, b_2, c_2 \rangle \) can be calculated as follows:
The dot product of vectors \( \mathbf{u} = \langle a_1, b_1, c_1 \rangle \) and \( \mathbf{v} = \langle a_2, b_2, c_2 \rangle \) can be calculated as follows:
- \( \mathbf{u} \cdot \mathbf{v} = a_1a_2 + b_1b_2 + c_1c_2 \)
Vectors
Vectors are fundamental building blocks used in physics and mathematics to represent quantities with both magnitude and direction. Unlike scalars that only have magnitude (like mass or temperature), vectors encompass a directional component, making them ideal for describing forces, velocities, and more in space.
Each vector is typically represented in Cartesian (rectangular) coordinates, such as \( \mathbf{v} = \langle a, b, c \rangle \), where \( a, b, \) and \( c \) are components of the vector along the x, y, and z axes, respectively. This setup is straightforward for calculations and visualizations in three dimensions.
Vectors are not limited to describing physical motion; they also serve as fundamental components in various mathematical operations. Operations on vectors like addition, subtraction, scalar multiplication, dot product, and cross product are manipulations that help solve complex problems in engineering, computer graphics, and more.
Each vector is typically represented in Cartesian (rectangular) coordinates, such as \( \mathbf{v} = \langle a, b, c \rangle \), where \( a, b, \) and \( c \) are components of the vector along the x, y, and z axes, respectively. This setup is straightforward for calculations and visualizations in three dimensions.
Vectors are not limited to describing physical motion; they also serve as fundamental components in various mathematical operations. Operations on vectors like addition, subtraction, scalar multiplication, dot product, and cross product are manipulations that help solve complex problems in engineering, computer graphics, and more.
Scalar Multiplication
Scalar multiplication involves multiplying a vector by a scalar value and is a straightforward operation that scales the vector's magnitude without altering its direction. If you have a vector \( \mathbf{v} = \langle a, b, c \rangle \) and a scalar \( k \), the result of this operation is:
Scalar multiplication is crucial in many applications, allowing for simple yet powerful transformations of vectors in both mathematics and physical sciences. This operation maintains the vector's direction but alters its length, proving invaluable in adjusting vector-based representations within applied mathematics and computational fields.
- \( k\mathbf{v} = \langle ka, kb, kc \rangle \)
Scalar multiplication is crucial in many applications, allowing for simple yet powerful transformations of vectors in both mathematics and physical sciences. This operation maintains the vector's direction but alters its length, proving invaluable in adjusting vector-based representations within applied mathematics and computational fields.
Other exercises in this chapter
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