Problem 31
Question
Let \(f(x)=x^{4}-4 x-1\). a. Use Rolle's Theorem to show that \(f\) has exactly two distinct zeros. b. Plot the graph of \(f\) using the viewing window \([-3,3] \times[-5,5]\)
Step-by-Step Solution
Verified Answer
a. The function \(f(x) = x^4 - 4x - 1\) is a polynomial, and thus continuous and differentiable everywhere. Its derivative, \(f'(x) = 4x^3 - 4\), has a critical point at \(x=1\). The second derivative, \(f''(x)=12x^2\), confirms a local minimum at this point. Since it is an even-degree polynomial with a positive leading coefficient, it must diverge to positive infinity at both ends, implying exactly two distinct zeros.
b. Use a graphing tool to plot the function \(f(x) = x^4 - 4x - 1\) with a viewing window \([-3, 3] \times [-5, 5]\). You should observe a local minimum at x=1 and two distinct zeros where the function intersects the x-axis.
1Step 1: Verify the conditions for Rolle's theorem
Rolle's theorem states that if a function is continuous on the closed interval \([a, b]\), differentiable on the open interval \((a, b)\), and \(f(a) = f(b)\), then there must be at least one number \(c\) in the open interval \((a, b)\) such that the derivative of the function at that point is zero i.e. \(f'(c) = 0\).
The given function \(f(x) = x^4 - 4x - 1\) is a polynomial function, and all polynomial functions are continuous and differentiable everywhere.
2Step 2: Compute the derivative of \(f(x)\) and solve for critical points
Let's find the derivative of the function \(f(x)\):
\(f'(x) = \frac{d}{dx} (x^4 - 4x - 1) = 4x^3 - 4\)
Now let's solve the equation \(f'(x) = 0\):
\(4x^3 - 4 = 0\)
\(x^3 = 1\)
\(x = 1\)
This gives us a critical point, \(x = 1\), where the function changes its concavity. We can confirm that by analyzing the second derivative.
The second derivative is given by:
\(f''(x) = \frac{d^2}{dx^2} (4x^3 - 4) = 12x^2\)
Since \(f''(1) = 12\times 1^2 = 12 > 0\), we can conclude that there is a local minimum at \(x=1\).
3Step 3: Showing exactly two distinct zeros
Now let's analyze the polynomial:
1. As we know, there is a local minimum at \(x=1\).
2. The polynomial \(f(x)\) is even degree (degree 4) and has a positive leading coefficient (the term \(x^4\)). Thus, \(f(x)\) must diverge to positive infinity as x goes to positive or negative infinity.
Since we know that the function has a local minimum and both ends of the graph diverge to positive infinity, the function must intersect the x-axis. As the function passes the local minimum at x=1, it will start increasing again. Since it's an even degree polynomial, the function must cross the x-axis twice for it to go to positive infinity at both ends. Therefore, the function has exactly two distinct zeros.
4Step 4: Plot the graph of \(f(x)\) for the given viewing window
To plot the graph of \(f(x) = x^4 - 4x - 1\) for the viewing window \([-3, 3] \times [-5, 5]\):
1. Choose a graphing tool (e.g., graphing calculator, online plotting tool, or software).
2. Enter the function \(f(x) = x^4 - 4x - 1\).
3. Set up the viewing window with an x-range of -3 to 3 and a y-range of -5 to 5.
4. Analyze the graph and observe the two points (zeros) where the function intersects the x-axis.
The graph should show a local minimum at x=1 and two distinct zeros where the function intersects the x-axis.
Key Concepts
Polynomial FunctionCritical PointsSecond DerivativeFunction Zeros
Polynomial Function
A polynomial function is an expression that consists of variables, coefficients, and non-negative integer exponents. It's structured as a sum of power terms, such as in the function \(f(x) = x^4 - 4x - 1\). Polynomial functions possess certain features that make them special:
- They are always continuous, meaning there are no breaks or gaps in their graph.
- They are differentiable everywhere, enabling us to find derivatives at any point.
- The degree of a polynomial, which is the highest power of the variable, determines the number of possible roots and the end behavior of the function's graph.
Critical Points
Critical points of a function occur where the derivative is zero or undefined. For the polynomial \(f(x) = x^4 - 4x - 1\), we find its derivative as \(f'(x) = 4x^3 - 4\). Setting the derivative \(f'(x)\) to zero helps locate critical points:
- Solve \(4x^3 - 4 = 0\), which simplifies to \(x^3 = 1\). Thus, \(x = 1\) is a critical point.
Second Derivative
The second derivative provides information about the concavity and inflection points of a function. For \(f(x) = x^4 - 4x - 1\), the second derivative is \(f''(x) = 12x^2\). This derivative shows us:
- If \(f''(x) > 0\), the function is concave up, indicating a local minimum.
- If \(f''(x) < 0\), it signifies concave down, suggesting a local maximum.
Function Zeros
The zeros of a function are the x-values where the function evaluates to zero. They represent the points where the graph of the function crosses the x-axis. For \(f(x) = x^4 - 4x - 1\), using Rolle's Theorem and the behavior of polynomial curves:
- A polynomial of degree 4 like \(f(x)\) can have up to 4 zeros, but not necessarily distinct ones.
- Given the local minimum at \(x = 1\) and the end behavior (both ends going to infinity), the polynomial crosses the x-axis twice.
Other exercises in this chapter
Problem 31
Find the limit. $$ \lim _{x \rightarrow \infty} \frac{2 x}{\sqrt{3 x^{2}+1}} $$
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(a) find the intervals on which \(f\) is increasing or decreasing, and (b) find the relative maxima and relative minima of \(\vec{f}\). $$ f(x)=x-2 \sin x, \qua
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Determine where the graph of the function is concave upward and where it is concave downward. Also, find all inflection points of the function. $$ h(x)=\ln |x|
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In Exercises \(25-40\), find the critical number \((s)\), if any, of the function. $$ h(x)=x^{4}-4 x^{3}+12 $$
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