Problem 31
Question
In your own words, explain the basic steps in solving a system of linear equations by the method of substitution.
Step-by-Step Solution
Verified Answer
The substitution method involves: 1) solving one equation for one variable, 2) substituting this expression into the other equation, 3) solving the resulting single-variable equation, 4) substituting this value back into one of the original equations to solve for the other variable, and 5) verifying the solution by substitifound into the original equations
1Step 1: Understanding the Concept
The method of substitution involves solving one of the equations for one variable in terms of the other variable. This provides an expression that can be substituted into the other equation.
2Step 2: Solving one of the Equations
Choose one of the equations to solve for a specific variable. The choice of which equation and which variable to solve for depends on which will simplify the problem most effectively.
3Step 3: Substituting into the Other Equation
Substitute the expression obtained in the previous step into the other equation. This results in an equation with only one variable.
4Step 4: Solving the Single Variable Equation
Solve this resulting single-variable equation. This will provide the value for one of the variables.
5Step 5: Finding the Second Variable
Substitute the solved value into any of the original equations and solve for the other variable. This will provide the value for the second variable.
6Step 6: Verification by Substitution
Finally, substitute the obtained values of the variables into both the original equations to verify that they satisfy the system of equations
Key Concepts
Method of SubstitutionSolving EquationsAlgebraic ExpressionsVerification of Solutions
Method of Substitution
The method of substitution is a powerful tool used for solving systems of linear equations. It is particularly useful when the equations involve two variables. Here's a simple breakdown of this method:
- First, you choose one of the equations and solve it for one variable in terms of the other. This is typically done by isolating the variable on one side of the equation.
- After doing so, you'll get an expression that you can plug into the other equation. This substitution reduces the number of unknowns in the equation from two to one, simplifying your task significantly.
Solving Equations
When you have performed the substitution and have a new equation with one variable, it's time to solve this equation. The procedure involves the following:
- Perform any necessary algebraic operations to isolate the variable on one side of the equation.
- Use techniques such as adding, subtracting, multiplying, or dividing both sides until you isolate the variable completely.
Algebraic Expressions
Algebraic expressions are key in the method of substitution. They allow us to express a variable in terms of another:
- An algebraic expression typically involves variables, constants, and arithmetic operations such as addition or subtraction.
- When you rearrange an equation during substitution, you're crafting a new algebraic expression.
Verification of Solutions
Once you have found values for the variables, it's crucial to verify these solutions. This step ensures accuracy:
- Substitute the values back into both original equations and check if they satisfy those equations.
- If both equations hold true with your found values, then you have correctly solved the system.
Other exercises in this chapter
Problem 30
In Exercises 27-36, solve the system by graphing. $$ \left\\{\begin{array}{l} 3 x+2 y=-6 \\ 3 x-2 y=6 \end{array}\right. $$
View solution Problem 31
In Exercises 29-34, use a system of linear equations to solve the problem. The total cost of 8 gallons of regular gasoline and 12 gallons of premium gasoline is
View solution Problem 31
In Exercises 27-36, solve the system by graphing. $$ \left\\{\begin{array}{l} 4 x-5 y=0 \\ 6 x-5 y=10 \end{array}\right. $$
View solution Problem 32
In Exercises 29-34, use a system of linear equations to solve the problem. The total cost of 6 gallons of regular gasoline and 11 gallons of premium gasoline is
View solution