Problem 31
Question
In Exercises 15-58, find each product. $$ (x+3)(x-3) $$
Step-by-Step Solution
Verified Answer
The product of the given binomial expressions \( (x+3)(x-3) \) is \( x^2 - 9 \)
1Step 1: Distribute the first terms
First, distribute the term \(x\) from the first binomial to each term in the second binomial to get \(x(x-3)\). This simplifies to \(x^2 - 3x\).
2Step 2: Distribute the remaining terms
Next, distribute the term 3 from the first binomial to each term in the second binomial to get \(3(x-3)\). This simplifies to \(3x - 9\)
3Step 3: Combine like terms
Add the two results from steps 1 and 2 together. This gives us \((x^2 - 3x) + (3x - 9)\). Combining like terms, -3x and 3x cancel each other. So, we left with \(x^2 - 9\).
Key Concepts
BinomialsDistributive PropertyCombining Like Terms
Binomials
A binomial is a type of polynomial that contains exactly two terms. In the example given in the exercise, we have two binomials: \( (x+3) \) and \( (x-3) \). These binomials each consist of a linear term and a constant:
- The first binomial, \((x+3)\), includes the terms "\(x\)" and "3".
- The second binomial, \((x-3)\), includes the terms "\(x\)" and "-3".
Distributive Property
The distributive property is a fundamental principle in algebra. It allows us to multiply a term across all terms inside a parenthesis. In the case of binomial multiplication, the distributive property is often applied twice.
In Step 1 of the solution, the term "\(x\)" from the first binomial \((x+3)\) is distributed to each term in the second binomial \((x-3)\). This results in:
Step 2 applies the distributive property with the second term from the first binomial, "3", resulting in:
Using the distributive property effectively is crucial for simplifying expressions, especially as they become more complex. It is a powerful tool that facilitates the handling of algebraic operations.
In Step 1 of the solution, the term "\(x\)" from the first binomial \((x+3)\) is distributed to each term in the second binomial \((x-3)\). This results in:
- \(x \times x = x^2\)
- \(x \times -3 = -3x\)
Step 2 applies the distributive property with the second term from the first binomial, "3", resulting in:
- \(3 \times x = 3x\)
- \(3 \times -3 = -9\)
Using the distributive property effectively is crucial for simplifying expressions, especially as they become more complex. It is a powerful tool that facilitates the handling of algebraic operations.
Combining Like Terms
Combining like terms is the process of simplifying an expression by adding or subtracting terms that have the same variables raised to the same power. In algebra, this step is often necessary after distributing terms. It helps in tidying up expressions and making them much easier to interpret.
In Step 3 of the exercise, you have the expression from the previous steps: \(x^2 - 3x + 3x - 9\). Here, -3x and 3x are like terms since both have the variable "\(x\)" raised to the same power, which is 1. When you combine these like terms, they cancel each other out:
By combining like terms, the expression becomes much clearer and reveals the important features or solutions of the problem. This practice is essential for solving algebraic equations and is a crucial part of most polynomial operations.
In Step 3 of the exercise, you have the expression from the previous steps: \(x^2 - 3x + 3x - 9\). Here, -3x and 3x are like terms since both have the variable "\(x\)" raised to the same power, which is 1. When you combine these like terms, they cancel each other out:
- -3x + 3x = 0
By combining like terms, the expression becomes much clearer and reveals the important features or solutions of the problem. This practice is essential for solving algebraic equations and is a crucial part of most polynomial operations.
Other exercises in this chapter
Problem 31
multiply or divide as indicated. $$ \frac{x^{2}+x-12}{x^{2}+x-30} \cdot \frac{x^{2}+5 x+6}{x^{2}-2 x-3} \div \frac{x+3}{x^{2}+7 x+6} $$
View solution Problem 31
Factor each trinomial, or state that the trinomial is prime. $$9 x^{2}-9 x+2$$
View solution Problem 31
Use the quotient rule to simplify the expressions Assume that \(x>0\). $$ \frac{\sqrt{200 x^{3}}}{\sqrt{10 x^{-1}}} $$
View solution Problem 31
Simplify each exponential expression. $$ \left(x^{3}\right)^{7} $$
View solution