Problem 31
Question
If \(\frac{\sin \alpha}{\sin \beta}=\frac{\sqrt{3}}{2}\) and \(\frac{\cos \alpha}{\cos \beta}=\frac{\sqrt{5}}{2}, 0<\alpha<\beta<\frac{\pi}{2}\), then (A) \(\tan \alpha=1\) (B) \(\tan \alpha=\frac{\sqrt{3}}{\sqrt{5}}\) (C) \(\tan \beta=\frac{\sqrt{3}}{\sqrt{5}}\) (D) \(\tan \beta=1\)
Step-by-Step Solution
Verified Answer
Option (B): \( \tan \alpha = \frac{\sqrt{3}}{\sqrt{5}} \).
1Step 1: Understand the given equations
We have two given ratios: \( \frac{\sin \alpha}{\sin \beta} = \frac{\sqrt{3}}{2} \) and \( \frac{\cos \alpha}{\cos \beta} = \frac{\sqrt{5}}{2} \). Our task is to find either \( \tan \alpha \) or \( \tan \beta \) using these equations.
2Step 2: Express sine and cosine in terms of each other
Using the identity \( \tan x = \frac{\sin x}{\cos x} \), express \( \tan \alpha = \frac{\sin \alpha}{\cos \alpha} \) and \( \tan \beta = \frac{\sin \beta}{\cos \beta} \).
3Step 3: Express sin and cos in terms of \( \alpha \)
From \( \frac{\sin \alpha}{\sin \beta} = \frac{\sqrt{3}}{2} \), we have \( \sin \alpha = \frac{\sqrt{3}}{2} \sin \beta \). Similarly, from \( \frac{\cos \alpha}{\cos \beta} = \frac{\sqrt{5}}{2} \), we have \( \cos \alpha = \frac{\sqrt{5}}{2} \cos \beta \).
4Step 4: Substitute into \( \tan \alpha \)
Express \( \tan \alpha \) as \( \frac{\sin \alpha}{\cos \alpha} = \frac{\frac{\sqrt{3}}{2} \sin \beta}{\frac{\sqrt{5}}{2} \cos \beta} \). Simplifying gives \( \tan \alpha = \frac{\sqrt{3}}{\sqrt{5}} \).
5Step 5: Determine \( \tan \beta \)
Similarly, for \( \tan \beta \), express it as \( \frac{\sin \beta}{\cos \beta} \). Since neither \( \sin \beta \) nor \( \cos \beta \) were explicitly altered, \( \tan \beta = \tan \beta \) remains as is.
6Step 6: Match with given options
Checking the calculated values for \( \tan \alpha \) and \( \tan \beta \) against the options: \( \tan \alpha = \frac{\sqrt{3}}{\sqrt{5}} \) matches with option (B).
Key Concepts
Sine and Cosine RatiosTangent FunctionTrigonometric Identities
Sine and Cosine Ratios
Sine and cosine are fundamental trigonometric functions that relate the angles and sides of a right triangle. These functions are crucial in understanding circular and oscillatory movements. In every right triangle, the sine of an angle is the ratio of the length of the opposite side to the hypotenuse, while the cosine is the ratio of the length of the adjacent side to the hypotenuse.
For example, if we denote an angle by \( \alpha \), then
For example, if we denote an angle by \( \alpha \), then
- Sine Ratio: \( \sin \alpha = \frac{\text{Opposite}}{\text{Hypotenuse}} \)
- Cosine Ratio: \( \cos \alpha = \frac{\text{Adjacent}}{\text{Hypotenuse}} \)
Tangent Function
The tangent function is another essential trigonometric ratio. It is defined as the ratio of the sine of an angle to its cosine. If we consider an angle \( x \), the tangent can be represented as:
In our example, we use the concept of the tangent function to find \( \tan \alpha \). Using the expressions derived for sine and cosine, \( \tan \alpha = \frac{\frac{\sqrt{3}}{2} \sin \beta}{\frac{\sqrt{5}}{2} \cos \beta} \), simplifying this gives \( \tan \alpha = \frac{\sqrt{3}}{\sqrt{5}} \). Hence, the tangent function provides a way to relate all the information we have from sine and cosine ratios.
- \( \tan x = \frac{\sin x}{\cos x} \)
In our example, we use the concept of the tangent function to find \( \tan \alpha \). Using the expressions derived for sine and cosine, \( \tan \alpha = \frac{\frac{\sqrt{3}}{2} \sin \beta}{\frac{\sqrt{5}}{2} \cos \beta} \), simplifying this gives \( \tan \alpha = \frac{\sqrt{3}}{\sqrt{5}} \). Hence, the tangent function provides a way to relate all the information we have from sine and cosine ratios.
Trigonometric Identities
Trigonometric identities are equations involving trigonometric functions that hold true for any value of the variable involved. These identities form the backbone of trigonometry, providing tools for simplifying and solving a wide variety of problems.
A particularly useful identity is the reciprocal identity that relates the tangent function to sine and cosine:
Understanding these identities and how they connect different trigonometric functions is crucial for solving complex exercises efficiently and accurately.
A particularly useful identity is the reciprocal identity that relates the tangent function to sine and cosine:
- \( \tan x = \frac{\sin x}{\cos x} \)
Understanding these identities and how they connect different trigonometric functions is crucial for solving complex exercises efficiently and accurately.
Other exercises in this chapter
Problem 27
The value of \(\cos \theta \cdot \cos 2 \theta \cdot \cos 2^{2} \theta \ldots \cos 2^{n-1} \theta\) for \(\theta=\frac{\pi}{2^{n}+1}\) is (A) 1 (B) \(\frac{1}{2
View solution Problem 28
The sum of the series \(\sin \theta \cdot \sec 3 \theta+\sin 3 \theta \cdot \sec 3^{2} \theta+\) \(\sin 3^{2} \theta \sec 3^{3} \theta+\ldots\) up to \(n\) term
View solution Problem 35
Let \(n\) be a fixed positive integer such that \(\sin \left(\frac{\pi}{2 n}\right)+\cos \left(\frac{\pi}{2 n}\right)=\frac{\sqrt{n}}{2}\), then (A) \(n=4\) (B)
View solution Problem 36
If \(a \cos ^{2} 3 \alpha+b \cos ^{4} \alpha=16 \cos ^{6} \alpha+9 \cos ^{2} \alpha\) is identity, then (A) \(a=1\) (B) \(a=24\) (C) \(b=1\) (D) \(b=24\)
View solution