Problem 31
Question
For the following problems, solve each conditional equation. If the equation is not conditional, identify it as an identity or a contradiction. $$ \frac{k}{15}+20=10 $$
Step-by-Step Solution
Verified Answer
Answer: -150
1Step 1: Write down the given equation
We have the equation:
$$
\frac{k}{15} + 20 = 10
$$
2Step 2: Isolate the term with the variable 'k'
To isolate the term with the variable 'k', we need to subtract 20 from both sides of the equation:
$$
\frac{k}{15} + 20 - 20 = 10 - 20
$$
Which simplifies to:
$$
\frac{k}{15} = -10
$$
3Step 3: Solve for 'k'
Now that we have isolated the term with the variable 'k', we can solve for 'k' by multiplying both sides of the equation by 15:
$$
15 \cdot \frac{k}{15} = -10 \cdot 15
$$
The 15 on the left side of the equation cancels out with the denominator, leaving:
$$
k = -150
$$
4Step 4: Verify that the equation is conditional and state the solution
Since we were able to find a unique value for 'k' that makes the equation true, it is a conditional equation. The solution to the given equation is:
$$
k = -150
$$
Key Concepts
Conditional EquationsIdentitiesContradictionsAlgebraic Manipulation
Conditional Equations
Conditional equations are equations that are true only for specific values of the variable involved. They do not hold true for every value, just particular solutions, which makes them conditional. For example, in the exercise given, the equation \( \frac{k}{15} + 20 = 10 \) is only true when \( k = -150 \). If you substitute any other value for \( k \), the equation wouldn't be equal on both sides. This type of equation is quite common in algebra, where you're tasked with finding the precise value or values that satisfy the balance on either side of the equation.
- Identify by finding one unique solution.
- Check by substituting the solution back into the original equation to verify it holds true.
Identities
Identities refer to equations that are true for all possible values of the variable involved. These are expressions that balance perfectly no matter what number replaces the variable.
Unlike conditional equations, identities do not rely on finding a specific solution. They are universal truths, like \( a + b = b + a \), which illustrates the commutative property of addition.
Unlike conditional equations, identities do not rely on finding a specific solution. They are universal truths, like \( a + b = b + a \), which illustrates the commutative property of addition.
- Always holds true, create no limit on variable values.
- Broadly applicable across various scenarios.
Contradictions
Contradictions in algebra are equations that do not have any solutions. No matter what value you plug into the variable, the equation never balances. This means, mathematically, the left side and the right side can never be equal. A simple example may be \( x + 2 = x \).
Upon simplifying, you would end up with an untrue statement like \( 2 = 0 \), indicating there are no valid solutions.
Upon simplifying, you would end up with an untrue statement like \( 2 = 0 \), indicating there are no valid solutions.
- Leads to logical impossibilities.
- No solution exists that can satisfy the equation.
Algebraic Manipulation
Algebraic manipulation involves using algebraic rules and operations to rearrange or simplify equations or expressions in order to isolate variables and solve for unknowns. This process is crucial in handling all types of equations, whether they are conditional, identities, or contradictions.
For instance, in the provided exercise, algebraic manipulation was key to isolating \( k \):
For instance, in the provided exercise, algebraic manipulation was key to isolating \( k \):
- Subtracting \( 20 \) from both sides simplified the equation.
- Multiplying by \( 15 \) solved for the variable.
Other exercises in this chapter
Problem 31
The length of a rectangle is 6 meters more than three times the width. The perimeter of the rectangle is 44 meters What are the dimensions of the rectangle?
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For the following problems, translate the following phrases or sentences into mathematical expressions or equations. When a number is divided by four, the resul
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In the following problems, solve each of the conditional equations. $$ \frac{m}{7}=-8 $$
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Solve each of the conditional equations. $$ h-8=14 $$
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