Problem 31
Question
For the following exercises, describe the end behavior of the graphs of the functions. $$ f(x)=3(4)^{-x}+2 $$
Step-by-Step Solution
Verified Answer
As \(x\to+\infty\), \(f(x)\to2\); as \(x\to-\infty\), \(f(x)\to+\infty\).
1Step 1: Analyze the Function
The function is given by \( f(x) = 3(4)^{-x} + 2 \). This is an exponential decay function because the base of the exponential term, \(4^{-x}\), represents decay as \(x\) increases. The constant \(+2\) shifts the graph vertically.
2Step 2: Determine End Behavior as \(x \to +\infty\)
As \(x\) approaches positive infinity, the term \(3(4)^{-x}\) approaches zero because \((4)^{-x} \) tends towards zero. Thus, the function approaches \(f(x) = 2 \). Therefore, the end behavior as \(x \to +\infty\) is that \(f(x) \to 2\).
3Step 3: Determine End Behavior as \(x \to -\infty\)
As \(x\) approaches negative infinity, the term \(4^{-x}\) grows very large because a negative exponent becomes a large positive exponent when the negative sign is removed. Consequently, \(3(4)^{-x} \) also becomes very large, and \(f(x)\) approaches infinity. Thus, as \(x \to -\infty\), \(f(x) \to +\infty\).
Key Concepts
Understanding End Behavior in Exponential FunctionsExploring Exponential DecayGraph Analysis of Exponential Functions
Understanding End Behavior in Exponential Functions
End behavior in mathematics refers to the behavior of a graph as it approaches positive or negative infinity. It's important to understand this concept when analyzing exponential functions. In the case of the function \( f(x) = 3(4)^{-x} + 2 \), we observe two specific types of end behavior.
As \( x \to +fty \), or as \( x \) becomes a very large positive number, \( 4^{-x} \) tends towards zero. Since this term is multiplied by 3, the entire term \( 3(4)^{-x} \) also approaches zero. The remaining part of the function, due to the constant \(+ 2\), means \( f(x) \to 2 \).
On the other hand, as \( x \to -fty \), or as \( x \) becomes a very large negative number, the exponent negates the negative sign making it positive. Thus, \( 4^{-x} \) grows large, and correspondingly \( 3(4)^{-x} \) becomes large. Here, \( f(x) \to +fty \). Understanding these two behaviors helps analyze the overall graph and makes it easier to predict the function's long-term trends.
As \( x \to +fty \), or as \( x \) becomes a very large positive number, \( 4^{-x} \) tends towards zero. Since this term is multiplied by 3, the entire term \( 3(4)^{-x} \) also approaches zero. The remaining part of the function, due to the constant \(+ 2\), means \( f(x) \to 2 \).
On the other hand, as \( x \to -fty \), or as \( x \) becomes a very large negative number, the exponent negates the negative sign making it positive. Thus, \( 4^{-x} \) grows large, and correspondingly \( 3(4)^{-x} \) becomes large. Here, \( f(x) \to +fty \). Understanding these two behaviors helps analyze the overall graph and makes it easier to predict the function's long-term trends.
Exploring Exponential Decay
Exponential decay is a process where quantities decrease rapidly at first and then slowly over time. This is noticeable in our function \( f(x) = 3(4)^{-x} + 2 \), which models exponential decay.
When the base of an exponential function is between 0 and 1, it depicts decay. Here, the term \((4)^{-x}\) indicates such behavior, as it results in a fraction less than one for positive \(x\). The more \(x\) increases, the smaller \((4)^{-x} \) becomes, reducing the overall value of the term \(3(4)^{-x}\).
When the base of an exponential function is between 0 and 1, it depicts decay. Here, the term \((4)^{-x}\) indicates such behavior, as it results in a fraction less than one for positive \(x\). The more \(x\) increases, the smaller \((4)^{-x} \) becomes, reducing the overall value of the term \(3(4)^{-x}\).
- This gradual decrease is prominent as you move to the right on the x-axis.
- It leads the graph to approach its horizontal asymptote as \(x \to +fty\), which is reflected by the constant term \(+ 2\).
Graph Analysis of Exponential Functions
Graph analysis begins by identifying key features of a function: intercepts, asymptotes, and overall shape. Let’s examine the graph for \( f(x) = 3(4)^{-x} + 2 \).
First, recognize the horizontal asymptote. Here, it's \(y = 2\), which the graph approaches but never quite touches as \(x \to +fty\).
The y-intercept, the point where the graph crosses the y-axis, is attained when \(x = 0\). Plugging zero into our function gives \(f(0) = 3 \cdot (4)^{0} + 2 = 5\). Thus, the y-intercept is at the point \((0, 5)\).
First, recognize the horizontal asymptote. Here, it's \(y = 2\), which the graph approaches but never quite touches as \(x \to +fty\).
The y-intercept, the point where the graph crosses the y-axis, is attained when \(x = 0\). Plugging zero into our function gives \(f(0) = 3 \cdot (4)^{0} + 2 = 5\). Thus, the y-intercept is at the point \((0, 5)\).
- The exponential decay results in a curve that slopes downward from left (as \(x\) decreases) to the horizontal asymptote on the right.
- This graph visually embodies the function’s end behaviors and its decay characteristics.
Other exercises in this chapter
Problem 31
Refer to Table. $$\begin{array}{|c|c|c|c|c|c|c|} \hline \boldsymbol{x} & 1 & 2 & 3 & 4 & 5 & 6 \\ \hline \boldsymbol{f}(\boldsymbol{x}) & 555 & 383 & 307 & 210
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For the following exercises, use this scenario: A tumor is injected with 0.5 grams of Iodine-125, which has a decay rate of \(1.15 \%\) per day. To the nearest
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For the following exercises, use the compound interest formula, \(A(t)=P\left(1+\frac{r}{n}\right)^{n t}\). An account is opened with an initial deposit of \(\$
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For the following exercises, refer to Table 8. $$\begin{array}{ccccccc}{x} & {1} & {2} & {3} & {4} & {5} & {6} \\ {f(x)} & {555} & {383} & {307} & {210} & {158}
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