Problem 31
Question
For Problems \(21-40\), evaluate each expression. $$ \log _{10} 0.1 $$
Step-by-Step Solution
Verified Answer
The value of \(\log_{10} 0.1\) is -1.
1Step 1: Understand the Logarithm Definition
The expression \(\log_{10} 0.1\) asks us to find the power to which the base 10 must be raised to produce 0.1. In general, \(\log_b a = c\) means \(b^c = a\). Here, the base \(b\) is 10, and \(a\) is 0.1.
2Step 2: Set Up the Equation
Based on the logarithm definition, we set \(10^x = 0.1\), where \(x\) is the exponent we are trying to find. This will tell us what power of 10 equals 0.1.
3Step 3: Rewrite 0.1 as a Power of 10
We know that 0.1 can be rewritten as \(\frac{1}{10}\) or \(10^{-1}\). So, the equation becomes \(10^x = 10^{-1}\).
4Step 4: Solve the Exponent Equation
Since the bases are the same (both are 10), we can equate the exponents: \(x = -1\).
Key Concepts
ExponentiationBase 10 LogarithmSolving Equations
Exponentiation
Exponentiation is a fundamental operation in mathematics. It involves raising a number, known as the base, to the power of an exponent. The expression \(b^n\) signifies that the base \(b\) is multiplied by itself \(n-1\) more times. So, for example, \(2^3 = 2 \times 2 \times 2 = 8\).
Exponentiation is a concept that conveys repeated multiplication. It is crucial in fields ranging from algebra to calculus. Understanding it allows us to comprehend powers of numbers, growth patterns, and even computing logarithms.
When dealing with exponentiation, there is a particular interest in specific bases like 10, which is commonly used in scientific notation and logarithms. Knowing how to manipulate and understand powers of 10 is especially useful in handling large or small values efficiently.
Exponentiation is a concept that conveys repeated multiplication. It is crucial in fields ranging from algebra to calculus. Understanding it allows us to comprehend powers of numbers, growth patterns, and even computing logarithms.
When dealing with exponentiation, there is a particular interest in specific bases like 10, which is commonly used in scientific notation and logarithms. Knowing how to manipulate and understand powers of 10 is especially useful in handling large or small values efficiently.
Base 10 Logarithm
The base 10 logarithm, often written as \(\log_{10}\) or just \(\log\) in many contexts, helps us find the power we need to raise 10 in order to get another number. It answers questions like: "How many tens do I multiply to get this number?" In other words, if we have \(\log_{10} a = c\), we mean that \(10^c = a\).
Base 10 logarithms are ubiquitous in science and engineering because they simplify dealing with very large or very small numbers. For instance:
Base 10 logarithms are ubiquitous in science and engineering because they simplify dealing with very large or very small numbers. For instance:
- Sound intensity is often measured in logarithmic units called decibels.
- pH levels in chemistry are also logarithmic, indicating acidity or basicity.
Solving Equations
Solving equations, particularly those involving logarithms or exponentials, involves finding the unknown variable that satisfies the equation. To solve an equation means to find all the values of the variable that make the equation true.
In our exercise, we started with \(10^x = 0.1\). By recognizing that 0.1 can be written as \(10^{-1}\), we changed the equation to \(10^x = 10^{-1}\). Since both sides have the same base, we equated the exponents, resulting in \(x = -1\).
This example illustrates a common method of solving equations - expressing both sides in terms of the same base.
In our exercise, we started with \(10^x = 0.1\). By recognizing that 0.1 can be written as \(10^{-1}\), we changed the equation to \(10^x = 10^{-1}\). Since both sides have the same base, we equated the exponents, resulting in \(x = -1\).
This example illustrates a common method of solving equations - expressing both sides in terms of the same base.
- If \(b^x = b^y\), then \(x = y\).
- This property makes it simple to solve many exponential or logarithmic equations.
Other exercises in this chapter
Problem 31
For Problems \(23-32\), approximate each of the following logarithms to three decimal places. $$ \log _{3} 720 $$
View solution Problem 31
For Problems \(31-40\), use your calculator to find \(x\) when given \(\ln x\). Express answers to five significant digits. $$ \ln x=0.4721 $$
View solution Problem 31
Strontium- 90 has a half-life of 29 years. If there are 400 grams of strontium initially, how much, to the nearest gram, will remain after 87 years? After 100 y
View solution Problem 31
For Problems \(1-34\), solve each equation. $$ (27)\left(3^{x}\right)=9^{x} $$
View solution