Problem 31
Question
Find the value of each expression. \(\sec \theta,\) if \(\sin \theta=\frac{3}{4} ; 90^{\circ}<\theta<180^{\circ}\)
Step-by-Step Solution
Verified Answer
\(-\frac{4\sqrt{7}}{7}\)
1Step 1: Understanding Trigonometric Identities
We are asked to find \(\sec \theta\). The secant function is the reciprocal of the cosine function, i.e., \(\sec \theta = \frac{1}{\cos \theta}\). Given \(\sin \theta = \frac{3}{4}\), we need to find \(\cos \theta\) to get \(\sec \theta\).
2Step 2: Applying the Pythagorean Identity
The Pythagorean identity states \(\sin^2 \theta + \cos^2 \theta = 1\). Substituting the given \(\sin \theta = \frac{3}{4}\), we calculate: \(\left(\frac{3}{4}\right)^2 + \cos^2 \theta = 1\). Simplifying gives \(\frac{9}{16} + \cos^2 \theta = 1\).
3Step 3: Solving for \(\cos^2 \theta\)
From the equation \(\frac{9}{16} + \cos^2 \theta = 1\), subtract \(\frac{9}{16}\) from both sides to find \(\cos^2 \theta\). This results in \( \cos^2 \theta = 1 - \frac{9}{16}\). Simplifying gives \(\cos^2 \theta = \frac{7}{16}\).
4Step 4: Determining \(\cos \theta\)
Taking the square root of both sides, \(\cos \theta = \pm \frac{\sqrt{7}}{4}\). Since \(90^\circ<\theta <180^\circ\), \(\cos \theta\) is negative because it's in the second quadrant. Thus, \(\cos \theta = -\frac{\sqrt{7}}{4}\).
5Step 5: Calculating \(\sec \theta\)
Now that we have \(\cos \theta = -\frac{\sqrt{7}}{4}\), we find \(\sec \theta = \frac{1}{\cos \theta}\). Therefore, \(\sec \theta = \frac{1}{-\frac{\sqrt{7}}{4}} = -\frac{4}{\sqrt{7}}\). Rationalizing the denominator gives \(\sec \theta = -\frac{4\sqrt{7}}{7}\).
Key Concepts
Secant FunctionPythagorean IdentitySine and Cosine FunctionsTrigonometric Functions in Different Quadrants
Secant Function
The secant function, denoted by \( \sec \theta \), is one of the fundamental trigonometric functions, closely related to the cosine function. In fact, it is the reciprocal of the cosine function. This means that \( \sec \theta = \frac{1}{\cos \theta} \).
- This definition implies that if we know \( \cos \theta \), we can easily determine \( \sec \theta \).
- The function is undefined wherever the cosine function equals zero, because division by zero is undefined.
Pythagorean Identity
The Pythagorean identity is a key concept in trigonometry, establishing a relationship between the sine and cosine functions. It is expressed as:\[ \sin^2 \theta + \cos^2 \theta = 1 \]
- This identity holds for any angle \( \theta \) and is derived from the Pythagorean theorem applied to a unit circle.
- The identity is particularly useful for finding one trigonometric function when the other is known, which is exactly what we did in the original solution.
Sine and Cosine Functions
Sine and cosine functions are fundamental trigonometric functions used to describe relationships in right-angled triangles and unit circles.
- The sine function, \( \sin \theta \), gives the ratio of the length of the opposite side to the hypotenuse in a right-angled triangle.
- The cosine function, \( \cos \theta \), provides the ratio of the adjacent side to the hypotenuse.
- When applied to the unit circle, these functions help to define the coordinates of a point on the circle.
Trigonometric Functions in Different Quadrants
Understanding how trigonometric functions behave in different quadrants is crucial for correctly determining their signs and values.
- In the first quadrant, all trigonometric functions are positive.
- In the second quadrant, sine is positive while cosine and secant are negative. This relates directly to the problem when \(90^{\circ}<\theta<180^{\circ}\).
- In the third quadrant, tangent and cotangent are positive, while sine and cosine are negative.
- In the fourth quadrant, cosine and secant are positive, while sine is negative.
Other exercises in this chapter
Problem 31
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State the vertical shift, amplitude, period, and phase shift for each function. Then graph the function. $$ y=6 \cot \left[\frac{2}{3}\left(\theta-90^{\circ}\ri
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Find the amplitude, if it exists, and period of each function. Then graph each function. \(\frac{3}{4} y=\frac{2}{3} \sin \frac{3}{5} \theta\)
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