Problem 31
Question
Find an expression for \(a_{n}\) on the basis of the values of \(a_{0}, a_{1}, a_{2}, \ldots .\) $$ -1,2,-3,4,-5, \ldots $$
Step-by-Step Solution
Verified Answer
The expression for \(a_n\) is \((-1)^n (n+1)\).
1Step 1: Identify the Pattern
Look at the given sequence: \(-1, 2, -3, 4, -5, \ldots\). Observe the signs and the values to identify a pattern: the signs alternate between negative and positive, and the absolute values increase by 1 each time.
2Step 2: Establish Sign Alternation
Since the sequence alternates signs, use \((-1)^n\) to describe the alternating sign behavior. This expression returns \(-1\) for odd \(n\) and \(+1\) for even \(n\).
3Step 3: Determine the Absolute Values
The absolute values of the sequence follow the pattern 1, 2, 3, 4, 5, ..., which can be represented as \(n+1\) for \(a_n\).
4Step 4: Combine Both Patterns
Combine the alternation and absolute value patterns to form the full expression for \(a_n\). This is done by multiplying the absolute pattern by the sign alternation: \(a_n = (-1)^n (n+1)\).
Key Concepts
Alternating SequencesRecurrence RelationsMathematical Induction
Alternating Sequences
An alternating sequence is a special type of sequence where the signs of the terms oscillate between positive and negative. In the sequence provided in the exercise
- -1, 2, -3, 4, -5, ...
-
(-1)^n.
- It gives -1 when "n" is odd, indicating a negative term.
- It gives +1 when "n" is even, indicating a positive term.
Recurrence Relations
Recurrence relations are equations that express each term of a sequence in relation to its predecessor(s). In the context of our given sequence
- -1, 2, -3, 4, -5, ...
- You might observe that each term relies on knowing its position, "n", within the sequence.
- Every subsequent term's absolute value increases by exactly 1.
Mathematical Induction
Mathematical induction is a method of mathematical proof typically used to establish that a given statement holds true for all natural numbers. It has two basic steps:
- Base Case: Prove the statement is true for the initial value, usually n = 0 or n = 1.
- Inductive Step: Assume the statement holds for some arbitrary natural number k, and then prove it for k+1.
-
a_n = (-1)^n (n+1)
- Start by proving it for n = 0: clearly,
a_0 = -1, which fits the formula perfectly. - Then, assume
a_k = (-1)^k (k+1)is correct, and provea_{k+1} = (-1)^{k+1} (k+2)fits based on this assumption.
Other exercises in this chapter
Problem 30
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