Problem 31
Question
Find an equation of the line that passes through the given point and has the indicated slope. Sketch the line by hand. Use a graphing utility to verify your sketch, if possible. $$\left(-\frac{1}{2}, \frac{3}{2}\right), \quad m=0$$
Step-by-Step Solution
Verified Answer
The equation of the line is \(y = 3/2\). It's a horizontal line that goes through the point \(-1/2, 3/2\).
1Step 1: Apply the point-slope form
The point-slope form of a line's equation is given by \(y - y_1 = m(x - x_1)\). In this case, \(m = 0\), \(x_1 = -1/2\), and \(y_1 = 3/2\). When inserting these values into the formula, it simplifies to \(y = 3/2\), because any number multiplied by zero equals zero.
2Step 2: Graph the line
The line \(y = 3/2\) runs horizontally at \(y = 3/2\) on the graph. Starting from the \(y\)-intercept that is 3/2, draw a horizontal straight line that runs left and right without ever changing its \(y\)-distance.
3Step 3: Verify the graph
When possible, verify the graph with a graphing tool, which should also show an horizontal line at \(y = 3/2\).
Key Concepts
Point-Slope FormSlope of a LineGraphing Linear Equations
Point-Slope Form
Understanding the point-slope form of a line's equation can be a game-changer for graphing straight lines. It prominently features two pieces of key information – a point that the line passes through, and the line's slope. Formally, the equation is written as \( y - y_1 = m(x - x_1) \) where \( (x_1, y_1) \) represents the coordinates of the given point on the line, and \( m \) is the slope of the line.
This form is particularly useful because it allows you to plug in the coordinates of a known point and the slope value directly. If the slope (\b>m) is zero, as in our example, the equation simplifies marvellously. Multiplying zero by anything still gives you zero, which leads to the horizontal line equation \b>\( y = y_1 \) . To solidify your understanding, try plugging in other points and slopes into the point-slope form and see how it affects the equation.
This form is particularly useful because it allows you to plug in the coordinates of a known point and the slope value directly. If the slope (\b>m) is zero, as in our example, the equation simplifies marvellously. Multiplying zero by anything still gives you zero, which leads to the horizontal line equation \b>\( y = y_1 \) . To solidify your understanding, try plugging in other points and slopes into the point-slope form and see how it affects the equation.
Slope of a Line
The slope is a measure of how steep a line is and the direction it’s going. It’s simply the ratio of the vertical change to the horizontal change between two points on a line. Denoted by the letter \( m \) , it can be calculated by taking two points \b>\( (x_1, y_1) \) and \b>\( (x_2, y_2) \) on the line, and computing \( m = \frac{y_2 - y_1}{x_2 - x_1} \) .
In our exercise, the slope is given as zero. This means the line is not inclined at all—it's flat. A zero slope results in a horizontal line, and irrespective of the horizontal movement, the vertical height remains constant. If you are faced with a negative slope, the line will fall from left to right; a positive slope indicates a rise. Remember, a steeper line corresponds to a larger absolute slope value. Practicing with different slope values can help you predict the orientation of a line quickly!
In our exercise, the slope is given as zero. This means the line is not inclined at all—it's flat. A zero slope results in a horizontal line, and irrespective of the horizontal movement, the vertical height remains constant. If you are faced with a negative slope, the line will fall from left to right; a positive slope indicates a rise. Remember, a steeper line corresponds to a larger absolute slope value. Practicing with different slope values can help you predict the orientation of a line quickly!
Graphing Linear Equations
Graphing is a visual way to represent a linear equation and can reveal valuable insights into the nature of the line it describes. When graphing linear equations, we often use the y-intercept (where the line crosses the y-axis) and the slope. These components guide us in plotting the initial point and determining the line's direction and steepness.
For the linear equation we derived from the point-slope form, \( y = 3/2 \) , drawing the graph is straightforward. You simply locate the y-coordinate of 3/2 on the y-axis and draw a straight, horizontal line across the graph, perfectly parallel to the x-axis. This line doesn't tilt upwards or downwards because the slope is zero—it has no 'rise' over its 'run'. Always try to check your graph against a reliable graphing utility which can confirm whether your sketch accurately captures the essence of the linear equation.
For the linear equation we derived from the point-slope form, \( y = 3/2 \) , drawing the graph is straightforward. You simply locate the y-coordinate of 3/2 on the y-axis and draw a straight, horizontal line across the graph, perfectly parallel to the x-axis. This line doesn't tilt upwards or downwards because the slope is zero—it has no 'rise' over its 'run'. Always try to check your graph against a reliable graphing utility which can confirm whether your sketch accurately captures the essence of the linear equation.
Other exercises in this chapter
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