Problem 31
Question
Draw and name all the constitutional isomers of \(\mathrm{C}_{5} \mathrm{H}_{12}\)
Step-by-Step Solution
Verified Answer
Answer: There are three constitutional isomers for the formula \(\mathrm{C}_{5}\mathrm{H}_{12}\): Pentane, Isopentane (2-methylbutane), and Neopentane (2,2-dimethylpropane).
1Step 1: Draw the parent chain for each isomer
First, we need to draw the longest continuous chain of carbon atoms for each isomer. In this case, since we have 5 carbon atoms to work with, we can have chains of 5, 4 or 3 carbon atoms.
2Step 2: Add the remaining hydrogen atoms
Once we have the parent chain, we need to add the remaining hydrogen atoms. In order to maintain proper valency, each carbon must have a total of 4 bonds (including bonds to other carbon atoms).
3Step 3: Identify the different constitutional isomers
After drawing the different possible structures, we need to identify which ones are actually different isomers. It is important to note that if you can rotate or move a molecule in any way to make it look like another, they are considered the same isomer.
4Step 4: Isomer 1: Pentane
A continuous chain of 5 carbon atoms with the remaining hydrogen atoms bonded to make the structure:
\(\displaystyle \mathrm{CH}_{3} -\mathrm{CH}_{2} -\mathrm{CH}_{2} -\mathrm{CH}_{2} -\mathrm{CH}_{3}\)
5Step 5: Isomer 2: Isopentane (2-methylbutane)
A continuous chain of 4 carbon atoms, with one carbon branching off at the second position, to form:
\(\displaystyle \mathrm{CH}_{3} -\mathrm{CH}(\mathrm{CH}_{3}) -\mathrm{CH}_{2} -\mathrm{CH}_{3}\)
6Step 6: Isomer 3: Neopentane (2,2-dimethylpropane)
A continuous chain of 3 carbon atoms, with two carbon atoms branching off at the second position, to form:
\(\displaystyle \mathrm{CH}_{3} -\mathrm{C}(\mathrm{CH}_{3})_{2} -\mathrm{CH}_{3}\)
To conclude, there are three constitutional isomers for the formula \(\mathrm{C}_{5}\mathrm{H}_{12}\): Pentane, Isopentane (2-methylbutane), and Neopentane (2,2-dimethylpropane).
Key Concepts
PentaneIsopentaneNeopentane
Pentane
Pentane, one of the simplest alkanes, is a straight-chain hydrocarbon with the molecular formula \( \mathrm{C}_5\mathrm{H}_{12} \). In the structure of pentane, you'll find five carbon atoms connected in a continuous chain. Each carbon is bonded to enough hydrogen atoms to make sure that each carbon atom forms four covalent bonds, adhering to the tetravalency rule. This gives us the formula:
- \( \mathrm{CH}_3 - \mathrm{CH}_2 - \mathrm{CH}_2 - \mathrm{CH}_2 - \mathrm{CH}_3 \)
Isopentane
Isopentane, also known as 2-methylbutane, is the first branched-chain isomer of pentane with the same formula \( \mathrm{C}_5\mathrm{H}_{12} \). Breaking from the straight chain pattern, isopentane has a four-carbon chain with a methyl group (\( \mathrm{CH}_3 \)) branching off from the second carbon:
- \( \mathrm{CH}_3 - \mathrm{CH} (\mathrm{CH}_3) - \mathrm{CH}_2 - \mathrm{CH}_3 \)
Neopentane
Neopentane, chemically known as 2,2-dimethylpropane, is an interesting isomer of pentane with a high degree of branching. Its structure is more compact than either pentane or isopentane. In neopentane, the three-carbon backbone has two additional methyl groups (\( \mathrm{CH}_3 \)) attached to the central carbon atom, forming:
- \( \mathrm{CH}_3 - \mathrm{C} (\mathrm{CH}_3)_2 - \mathrm{CH}_3 \)
Other exercises in this chapter
Problem 29
Do constitutional isomers always have the same chemical properties?
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