Problem 31
Question
Develop a grammar that generates each language over {0,1}. $$\\{1,11,1111,11111111, \ldots\\}$$
Step-by-Step Solution
Verified Answer
A context-free grammar G can be defined as a tuple (V, Σ, R, S), where V is a set of non-terminal symbols, Σ is a set of terminal symbols, R is a set of production rules, and S is the start symbol. For our language, the grammar G can be defined as G = (V, Σ, R, S) where:
- V = {S, A},
- Σ = {0, 1},
- R = {S → 1A, A → 1S | ε},
- S is the start symbol.
This grammar will generate the language \(\{1, 11, 1111, 11111111, \ldots\}\) over the alphabet \(\{0, 1\}\) as desired.
1Step 1: Define the Grammar Variables
The grammar G can be defined as a tuple (V, Σ, R, S) where:
- V is a set of non-terminal symbols (variables),
- Σ is a set of terminal symbols (the alphabet),
- R is a set of production rules for mapping the variables, and
- S is the start symbol.
For our language, the alphabet Σ consists of two terminal symbols: {0, 1}, but in the language, we will only use \(\{1\}\).
2Step 2: Define the Non-Terminal Symbols
There will be two non-terminal symbols in our grammar:
1. S: the start symbol,
2. A: a helper symbol in the production rules.
So, V = {S, A}.
3Step 3: Define the Production Rules
To generate the desired language, the production rules can be designed as follows:
1. S → 1A
2. A → 1S | ε
Now, R = {S → 1A, A → 1S | ε}.
4Step 4: Compile the Grammar
Combining all the components, our grammar G is defined as:
G = (V, Σ, R, S) where:
- V = {S, A},
- Σ = {0, 1},
- R = {S → 1A, A → 1S | ε},
- S is the start symbol.
This grammar will generate the language \(\{1, 11, 1111, 11111111, \ldots\}\) over the alphabet \(\{0, 1\}\) as desired.
Key Concepts
Non-Terminal SymbolsProduction RulesDiscrete Mathematics
Non-Terminal Symbols
Non-terminal symbols are one of the essential components of formal grammars in language generation. They represent abstract symbols that can be further expanded into sequences of terminal and/or non-terminal symbols. Think of them like place-holders or variables:
- Start Symbol (S): This is where the generation begins and serves as the primary non-terminal from which production applies.
- Helper Symbol (A): This is an additional non-terminal symbol that helps to form the language.
Production Rules
Production rules are transformative guidelines that define how non-terminal symbols evolve into terminal symbols or sequences thereof. They play a crucial role in grammar by guiding the conversion of abstract symbols into tangible strings:
- S → 1A: This rule specifies that whenever the start symbol S is encountered, it should be transformed into a terminal symbol 1 followed by non-terminal A.
- A → 1S | ε: A transforms into either 1 followed by S, or it can be replaced by ε (epsilon), representing an empty string, which is useful for ending the production sequence.
Discrete Mathematics
Discrete mathematics provides a backbone for understanding structures like formal grammars. It deals with distinct, separated values which is ideal for analyzing and designing computer algorithms and programming languages:
- Formal Grammars: These are a part of discrete mathematics that governs the syntax of languages, especially in computers and linguistic theories.
- Symbolic Representation: The use of symbols (like S, A, 0, and 1) to represent operations and entities in a precise and abstract manner.
- Sets and Sequences: Understanding how sets of symbols can come together under specific rules to form sequences (like the language in our solution).
Other exercises in this chapter
Problem 30
Find the language generated by each grammar \(G=(N, T, P, \sigma)\) where: $$\begin{array}{l} N=\\{\sigma, \mathrm{A}, \mathrm{B}\\}, T=\\{\mathrm{a}, \mathrm{b
View solution Problem 31
Create a NDFSA that accepts the regular language over \(\\{a, b\\}\) of strings that: Contain \(a b a\) as a substring.
View solution Problem 32
Create a NDFSA that accepts the regular language over \(\\{a, b\\}\) of strings that: Contain \(a^{3}\) as a substring.
View solution Problem 32
Let \(A=\\{a, b c\\}\) and \(B=\\{\lambda, a b, b c\\} .\) Find each concatenation. \(A^{2}\)
View solution