Problem 31
Question
Determine whether or not the given vectors are perpendicular. $$(0.3,1.2,-0.9),(10,-5,10)$$
Step-by-Step Solution
Verified Answer
The vectors are not perpendicular.
1Step 1: Understand Perpendicular Vectors
Two vectors are perpendicular if their dot product equals zero. The dot product of two vectors \( \mathbf{a} = (a_1, a_2, a_3) \) and \( \mathbf{b} = (b_1, b_2, b_3) \) is given by \( a_1b_1 + a_2b_2 + a_3b_3 \).
2Step 2: Identify Components of Vectors
Identify the components of the vectors. For vector \( \mathbf{a} = (0.3, 1.2, -0.9) \), the components are \( a_1 = 0.3 \), \( a_2 = 1.2 \), \( a_3 = -0.9 \). For vector \( \mathbf{b} = (10, -5, 10) \), the components are \( b_1 = 10 \), \( b_2 = -5 \), \( b_3 = 10 \).
3Step 3: Calculate Dot Product
Substitute the components into the dot product formula: \[ 0.3 \times 10 + 1.2 \times (-5) + (-0.9) \times 10 \] Calculate each term: \( 0.3 \times 10 = 3 \), \( 1.2 \times (-5) = -6 \), \( -0.9 \times 10 = -9 \).
4Step 4: Sum the Results
Compute the sum of the results from Step 3: \[ 3 + (-6) + (-9) = 3 - 6 - 9 = -12 \] Check if the sum is zero to determine perpendicularity.
5Step 5: Determine Perpendicularity
Since the dot product \(-12\) is not equal to zero, the vectors are not perpendicular.
Key Concepts
Dot ProductPerpendicular VectorsVector Components
Dot Product
The dot product is a fundamental concept in vector mathematics. It's a way to multiply two vectors, and the result is a scalar (a single number). This operation is denoted by a dot between the two vectors, like this:
- \( \mathbf{a} \cdot \mathbf{b} \).
- Multiplying their corresponding components.
- Then summing these products: \( a_1b_1 + a_2b_2 + a_3b_3 \).
Perpendicular Vectors
Perpendicular vectors are two vectors that meet at a 90-degree angle. Determining if vectors are perpendicular is crucial in physics and engineering.This condition is identifiable through their dot product.
- If the dot product is zero, the vectors are perpendicular.
- \( 0.3 \times 10 + 1.2 \times (-5) + (-0.9) \times 10 = -12 \).
Vector Components
Vectors have components that define their direction and magnitude in each dimension. Consider a vector in three-dimensional space \( (a_1, a_2, a_3) \), where each number is a component.
- The first component \( a_1 \) indicates direction along the x-axis.
- The second component \( a_2 \) along the y-axis.
- The third component \( a_3 \) along the z-axis.
- Components of vector \( \mathbf{a} \): \( 0.3, 1.2, -0.9 \)
- Components of vector \( \mathbf{b} \): \( 10, -5, 10 \)
Other exercises in this chapter
Problem 30
Write the given vector in terms of \(\mathbf{i}\) and \(\mathbf{j}\). $$\mathbf{u}=\langle 0,-5\rangle$$
View solution Problem 31
Three vectors \(\mathbf{a}\), \(\mathbf{b}\), and \(\mathbf{c}\) are given. \(\mathbf{(a)}\) Find their scalar triple product \(\mathbf{a} \cdot(\mathbf{b} \tim
View solution Problem 31
Calculate proj, u. (b) Resolve u into \(u_{1}\) and \(u_{2}\), where \(\mathbf{u}_{1}\) is parallel to \(\mathbf{v}\) and \(\mathbf{u}_{2}\) is orthogonal to \(
View solution Problem 31
Find \(2 u,-3 v, u+v,\) and \(3 u-4 v\) for the given vectors \(\mathbf{u}\) and \(\mathbf{v}\) $$\mathbf{u}=\langle 2,7\rangle, \quad \mathbf{v}=\langle 3,1\ra
View solution