Problem 31
Question
Describe the interval(s) on which the function is continuous. Explain why the function is continuous on the interval(s). If the function has a discontinuity, identify the conditions of continuity that are not satisfied. \(f(x)=\llbracket x-1 \rrbracket\)
Step-by-Step Solution
Verified Answer
The function \(f(x) = \llbracket x-1 \rrbracket\) is continuous for any interval that does not include an integer. The function is not continuous at integer values, as the conditions of continuity are not met (limit from the left is not equal to limit from the right).
1Step 1: Identify the Function Type
The floor function \(f(x) = \llbracket x-1 \rrbracket\) is plotted. Observe the graph and note where the function is undefined.
2Step 2: Identifying the Intervals of Continuity and Points of Discontinuity
The function is continuous on all intervals except at all integer points, following the expression \(x \in \mathbb{Z}\). At these particular integer points, the limit from the left-hand side is not the same as the limit from the right-hand side, thus marking these points as points of discontinuity.
3Step 3: Explain the Discontinuity
The condition of continuity that is not met at these points of discontinuity (integer points) is that, for all \(x \in \mathbb{Z}\), the right-hand limit (from x+) and left-hand limit (from x-) should coincide, which is not the case here.
Key Concepts
Discontinuity in FunctionsUnderstanding the Floor FunctionInterval Notation
Discontinuity in Functions
When we talk about a function being continuous, we mean that you can draw it without lifting your pen. However, when a function suddenly "jumps" or has a break in its graph, it is said to be discontinuous at that point.
For our specific function, which is a floor function, discontinuities occur at every integer point. This is because the left-hand limit and the right-hand limit do not match at these points.
For our specific function, which is a floor function, discontinuities occur at every integer point. This is because the left-hand limit and the right-hand limit do not match at these points.
- Left-hand limit: This is the value that the function approaches as you move from left towards the integer point.
- Right-hand limit: This is the value the function approaches as you move from right towards the integer point.
Understanding the Floor Function
The function given, \(f(x) = \lfloor x-1 \rfloor\), is known as a floor function. The floor function, denoted by \(\lfloor x \rfloor\), rounds down any real number to the nearest integer less than or equal to it.
This means if you input a real number like 3.7 into the floor function, it outputs 3.
This means if you input a real number like 3.7 into the floor function, it outputs 3.
- Behavior: Floor functions show a step-like behavior and are constant between integers.
- Graph: The graph looks like a series of steps, reflecting how it stays the same across a range but drops at integers.
Interval Notation
Interval notation is a way of describing the continuous and non-continuous parts of a function by specifying the start and end points of intervals. When using interval notation, pay attention to the symbols used:
- \((a, b)\): Represents all numbers between \(a\) and \(b\), not including \(a\) and \(b\) themselves.
- \([a, b]\): Includes both \(a\) and \(b\) in the interval.
Other exercises in this chapter
Problem 31
The cost \(C\) (in dollars) of producing \(x\) units of a product is given by \(C=3.6 \sqrt{x}+500\) (a) Find the additional cost when the production increases
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Find the value of the derivative of the function at the given point. $$ f(x)=-\frac{1}{2} x\left(1+x^{2}\right) \quad(1,-1) $$
View solution Problem 31
Use the limit definition to find the derivative of the function. $$ f(x)=x^{2}-4 $$
View solution Problem 31
Find the limit. $$ \lim _{x \rightarrow-3} \frac{2}{x+2} $$
View solution