Problem 31
Question
Challenge Calculate the \(\left[\mathrm{H}^{+}\right]\) and \(\left[\mathrm{OH}^{-}\right]\) in a sample of seawater with a pOH \(=5.60 .\)
Step-by-Step Solution
Verified Answer
\([\mathrm{H}^{+}] \approx 3.98 \times 10^{-9} \text{ M}\) and \([\mathrm{OH}^{-}] \approx 2.51 \times 10^{-6} \text{ M}\).
1Step 1: Understanding pOH and its Relation to pH
The pOH of a solution is related to the pH through the equation: \[ \text{pH} + \text{pOH} = 14 \]Given that the pOH is 5.60, we can calculate the pH using this relationship.
2Step 2: Calculating the pH
Using the relation from the first step:\[\text{pH} = 14 - \text{pOH} = 14 - 5.60 = 8.40\]So, the pH of the solution is 8.40.
3Step 3: Finding \\[\mathrm{H}^{+}\] from pH
To find the \[\mathrm{H}^{+}\] ion concentration, we use the formula:\[\left[ \mathrm{H}^{+} \right] = 10^{-\text{pH}}\]Plugging in the pH value we found:\[\left[ \mathrm{H}^{+} \right] = 10^{-8.40}\]Calculate the value to find \[\mathrm{H}^{+}\].
4Step 4: Calculating the \\[\mathrm{H}^{+}\] Concentration
Continuing from the previous step, calculate:\[\left[ \mathrm{H}^{+} \right] \approx 3.98 \times 10^{-9} \text{ M}\]This is the concentration of hydrogen ions in the seawater.
5Step 5: Finding \\[\mathrm{OH}^{-}\] from pOH
The \[\mathrm{OH}^{-}\] ion concentration is calculated using the formula:\[\left[ \mathrm{OH}^{-} \right] = 10^{-\text{pOH}}\]Plug in the pOH value:\[\left[ \mathrm{OH}^{-} \right] = 10^{-5.60}\]Calculate the value to find \[\mathrm{OH}^{-}\].
6Step 6: Calculating the \\[\mathrm{OH}^{-}\] Concentration
Now, compute the value:\[\left[ \mathrm{OH}^{-} \right] \approx 2.51 \times 10^{-6} \text{ M}\]This is the concentration of hydroxide ions in the seawater.
Key Concepts
pH and pOH calculationsHydrogen Ion ConcentrationHydroxide Ion Concentration
pH and pOH calculations
In acid-base chemistry, the concepts of pH and pOH are crucial in understanding the acidity or basicity of a solution. The relation \[ \text{pH} + \text{pOH} = 14 \] is fundamental and provides a convenient way to interconvert between these two variables. In essence, if you know either the pH or the pOH, you can easily find the other by this equation.
For instance, if the pOH of seawater is given as 5.60, the pH can be calculated as: \[ \text{pH} = 14 - \text{pOH} = 14 - 5.60 = 8.40 \] This value indicates a slightly basic solution. Breaking down these calculations helps emphasize the logarithmic scale used in pH and pOH, where each unit represents a tenfold change in ionic concentration. Therefore, understanding this relationship allows us to adjust our approach in various chemical environments efficiently.
For instance, if the pOH of seawater is given as 5.60, the pH can be calculated as: \[ \text{pH} = 14 - \text{pOH} = 14 - 5.60 = 8.40 \] This value indicates a slightly basic solution. Breaking down these calculations helps emphasize the logarithmic scale used in pH and pOH, where each unit represents a tenfold change in ionic concentration. Therefore, understanding this relationship allows us to adjust our approach in various chemical environments efficiently.
Hydrogen Ion Concentration
The concentration of hydrogen ions \( \left[ \text{H}^+ \right] \) plays a central role in determining the acidity of a solution. The pH is a logarithmic measure of this concentration, defined by the formula: \[ \text{pH} = -\log_{10}(\left[ \text{H}^+ \right]) \] To find the \( \left[ \text{H}^+ \right] \) given a pH, reverse this relationship: \[ \left[ \text{H}^+ \right] = 10^{-\text{pH}} \] Continuing with our seawater example where \( \text{pH} = 8.40 \),we compute: \[ \left[ \text{H}^+ \right] = 10^{-8.40} \approx 3.98 \times 10^{-9} \text{ M} \] This result suggests that the seawater is basic, as the concentration of hydrogen ions is low. Understanding these calculations can aid in predicting chemical behavior in different aquatic environments, which is essential in marine chemistry and environmental science.
Hydroxide Ion Concentration
The hydroxide ion concentration \( \left[ \text{OH}^- \right] \) is equally important when discussing basic solutions. The pOH gives us a direct path to find this concentration through the formula: \[ \left[ \text{OH}^- \right] = 10^{-\text{pOH}} \] In our example, where the pOH is 5.60, we calculate: \[ \left[ \text{OH}^- \right] = 10^{-5.60} \approx 2.51 \times 10^{-6} \text{ M} \] This higher concentration of hydroxide ions compared to hydrogen ions reinforces the idea that the solution is basic.
Remember, the presence of hydroxide ions is pivotal in understanding reactions such as neutralization, where acids and bases interact to produce water and salts. These calculations provide clarity on the dynamics of ionic interactions in solutions, facilitating insights into their balancing mechanisms and potential applications.
Remember, the presence of hydroxide ions is pivotal in understanding reactions such as neutralization, where acids and bases interact to produce water and salts. These calculations provide clarity on the dynamics of ionic interactions in solutions, facilitating insights into their balancing mechanisms and potential applications.
Other exercises in this chapter
Problem 29
Challenge Calculate pH and pOH for an aqueous solution containing \(1.0 \times 10^{-3}\) mol of HCl dissolved in 5.0 \(\mathrm{L}\) of solution.
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