Problem 31
Question
At STP the density of a gas (mol. wt \(=45\) ) in \(\mathrm{g} / \mathrm{L}\) is (a) \(11.2\) (b) 1000 (c) 2 (d) 224
Step-by-Step Solution
Verified Answer
The density of the gas at STP is approximately 2 g/L (option c).
1Step 1: Understand the Standard Conditions
STP stands for Standard Temperature and Pressure, which means the temperature is 273 K and the pressure is 1 atm. At these conditions, 1 mole of an ideal gas occupies a volume of 22.4 L.
2Step 2: Identify the Formula for Density
The density (\(d\)) of a gas is expressed as the mass of the gas per unit volume. The formula for density is \(d = \frac{m}{V}\), where \(m\) is the mass (in grams) and \(V\) is the volume (in liters).
3Step 3: Apply the Ideal Gas Law Concept
Use the concept that at STP, 1 mole of gas occupies 22.4 L. Therefore, for a gas with molecular weight (mol. wt) of 45 g/mol, the mass of 45 g will occupy 22.4 L.
4Step 4: Calculate the Density
Using the formula for density and the ideal gas volume:\[d = \frac{m}{V} = \frac{45}{22.4} \approx 2.01 \, \text{g/L}\]So, we can approximate this value to 2 g/L based on the given options.
Key Concepts
Standard Temperature and Pressure (STP)Ideal Gas LawMolecular Weight
Standard Temperature and Pressure (STP)
Standard Temperature and Pressure, abbreviated as STP, refers to a set of conditions for measuring gases, which is widely accepted in scientific calculations and experiments. STP conditions are standardized to ease comparison between different gases and various experiments. Typically, STP conditions are defined as a temperature of 273 Kelvin (0 degrees Celsius) and a pressure of 1 atmosphere (atm).
- At STP, 1 mole of an ideal gas occupies a volume of 22.4 liters.
- Understanding STP is crucial for accurate gas calculations in chemistry.
Ideal Gas Law
The Ideal Gas Law is a fundamental principle often used to relate the properties of gases. It combines several different laws into one equation, helping to understand and calculate the behavior of gases. The equation is expressed as:\[ PV = nRT \]Where:
- \(P\) is the pressure in atmospheres (atm)
- \(V\) is the volume in liters (L)
- \(n\) is the number of moles of gas
- \(R\) is the ideal gas constant, which is 0.0821 L·atm/mol·K
- \(T\) is the temperature in Kelvin (K)
Molecular Weight
Molecular Weight, sometimes referred to as molar mass, is an important concept when calculating the amount of a substance in a chemical equation or physical process. It represents the mass of one mole of a given substance, typically expressed in grams per mole (g/mol).
- Knowing the molecular weight is essential to determine the mass of the gas that occupies a specific volume, like at STP.
- The molecular weight is calculated as the sum of the atomic weights of all atoms in a molecule.
Other exercises in this chapter
Problem 28
The molecular weight of \(\mathrm{O}_{2}\) and \(\mathrm{SO}_{2}\) are 32 and 64 respectively. At \(15^{\circ} \mathrm{C}\) and \(150 \mathrm{~mm} \mathrm{Hg}\)
View solution Problem 29
\(7.5\) gram of a gas occupies \(5.6\) litres as STP. The gas is (a) \(\mathrm{CO}\) (b) NO (c) \(\mathrm{CO}_{2}\) (d) \(\mathrm{N}_{2} \mathrm{O}\)
View solution Problem 34
A compound possess \(8 \%\) sulphur by mass. The least molecular mass is (a) 200 (b) 400 (c) 155 (d) 355
View solution Problem 36
The weight of one molecule of a compound \(\mathrm{C}_{60} \mathrm{H}_{122}\) is (a) \(1.3 \times 10^{-20} \mathrm{~g}\) (b) \(5.01 \times 10^{-21} \mathrm{~g}\
View solution