Problem 31
Question
A parallel beam of unpolarized light in air is incident at an angle of \(54.5^{\circ}\) (with respect to the normal) on a plane glass surface. The reflected beam is completely linearly polarized. (a) What is the refractive index of the glass? (b) What is the angle of refraction of the transmitted beam?
Step-by-Step Solution
Verified Answer
(a) The refractive index is approximately 1.376. (b) The angle of refraction is approximately 37.2°.
1Step 1: Understanding Brewster's angle
When light is incident at the Brewster angle, the reflected light is completely polarized. Brewster's angle, \( \theta_p \), is given by the equation: \[ \tan(\theta_p) = n \] where \( n \) is the refractive index of the glass.
2Step 2: Calculate the refractive index of the glass
Since the angle of incidence \( \theta_i = 54.5^{\circ} \) is the Brewster angle, we can use the equation: \[ \tan(54.5^{\circ}) = n \]. Calculating this gives: \[ n = \tan(54.5^{\circ}) \approx 1.376 \].
3Step 3: Use Snell's Law to find the angle of refraction
To find the angle of refraction, \( \theta_t \), we use Snell's Law: \[ n_1 \sin(\theta_i) = n_2 \sin(\theta_t) \]. Here, \( n_1 = 1 \) for air and \( n_2 \approx 1.376 \) for glass. Thus, \[ \sin(54.5^{\circ}) = 1.376 \sin(\theta_t) \].
4Step 4: Solve for the angle of refraction
Rearrange the equation to solve for \( \sin(\theta_t) \): \[ \sin(\theta_t) = \frac{\sin(54.5^{\circ})}{1.376} \]. Compute this to find \( \theta_t \): \[ \theta_t \approx \sin^{-1}(\frac{\sin(54.5^{\circ})}{1.376}) \approx 37.2^{\circ} \].
Key Concepts
Unpolarized LightRefractive IndexSnell's Law
Unpolarized Light
Unpolarized light is light that vibrates in multiple planes rather than just one. Essentially, the vibrations of the light waves are oriented in random directions. Examples in everyday life range from sunlight to the light emitted by most electric bulbs. When light is reflected off surfaces, it can become polarized, meaning the light waves align in a single plane.
In the context of our exercise, a beam of unpolarized light hits a glass surface at Brewster’s angle, leading to the reflected light being completely polarized. When Brewster's angle is achieved, certain rules about light behavior come into play, which helps us calculate values like the refractive index of the glass.
In the context of our exercise, a beam of unpolarized light hits a glass surface at Brewster’s angle, leading to the reflected light being completely polarized. When Brewster's angle is achieved, certain rules about light behavior come into play, which helps us calculate values like the refractive index of the glass.
- Unpolarized light includes all orientations of light waves.
- Reflection off a surface can polarize unpolarized light.
- Brewster’s angle results in fully polarized reflected light.
Refractive Index
The refractive index, denoted as 'n', is a measure of how much a medium reduces the speed of light. The slower the light travels through a medium, the higher its refractive index. Common substances have known indices; for instance, air has a refractive index close to 1.0, while glass ranges around 1.5 depending on its type.
Our exercise uses the refractive index to determine how light bends when passing through different media. At Brewster’s angle, the refractive index can be found using the formula \[ \tan(\theta_p) = n \]If light hits the glass at Brewster's angle, you can calculate 'n' directly. The formula relates the angle to the medium’s refractive property, highlighting a unique relationship between angle and refractive index.
Our exercise uses the refractive index to determine how light bends when passing through different media. At Brewster’s angle, the refractive index can be found using the formula \[ \tan(\theta_p) = n \]If light hits the glass at Brewster's angle, you can calculate 'n' directly. The formula relates the angle to the medium’s refractive property, highlighting a unique relationship between angle and refractive index.
- Refractive index indicates a medium’s light bending ability.
- The slower the light, the higher the refractive index.
- Refractive index is key to understanding light behavior across media.
Snell's Law
Snell's Law is fundamental in optics, providing a relationship between the angles and the refractive indices of two media through which light passes. The law is mathematically expressed as:\[ n_1 \sin(\theta_i) = n_2 \sin(\theta_t) \]where:
In this exercise, Snell’s Law helps determine the angle of refraction when light transitions from air to glass. Starting with a known incident angle and refractive indices, we rearrange the formula to solve for the transmitted angle. Using basic algebra and trigonometry, we uncover how light bends, which is critical when crafting anything that needs precise control of light, like lenses and periscopes.
- \( n_1 \) and \( n_2 \) are the refractive indices of the first and second medium, respectively.
- \( \theta_i \) and \( \theta_t \) are the angles of incidence and refraction.
In this exercise, Snell’s Law helps determine the angle of refraction when light transitions from air to glass. Starting with a known incident angle and refractive indices, we rearrange the formula to solve for the transmitted angle. Using basic algebra and trigonometry, we uncover how light bends, which is critical when crafting anything that needs precise control of light, like lenses and periscopes.
- Describes the light path between different materials.
- Essential for understanding and designing refractive optical systems.
- Demonstrates how to calculate angles of refraction.
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