Problem 31
Question
31-32. Use a graphing calculator to graph each piecewise nonlinear function on the window [-2,10] by [-5,5] . Where parts of the graph do not touch, state which point is included and which is excluded. $$ f(x)=\left\\{\begin{array}{ll} x^{2} & \text { if } x \leq 2 \\ 6-x & \text { if } 2 < x < 6 \\ 2 x-17 & \text { if } x \geq 6 \end{array}\right. $$
Step-by-Step Solution
Verified Answer
Graph the pieces separately, (2,4) included; (2,4) excluded for line, (6,-5) included.
1Step 1: Understanding Piecewise Functions
We have a piecewise function defined with three rules based on the value of \(x\). For \(x \leq 2\), \(f(x) = x^2\). For \(2 < x < 6\), \(f(x) = 6 - x\). For \(x \geq 6\), \(f(x) = 2x - 17\). Each function rule will create a different section of the graph depending on these intervals.
2Step 2: Graph the First Piece
The first part \(f(x) = x^2\) applies when \(x \leq 2\). This is a parabolic curve opening upwards with a vertex at \( (0,0) \). On the interval from \(-2\) to \(2\), the parabola starts from \((4,16)\) at x=-2, moves through \((0,0)\), and ends at \((2, 4)\). The point \((2,4)\) is included, marked by a solid dot on the graph.
3Step 3: Graph the Second Piece
For \(2 < x < 6\), \(f(x) = 6 - x\). This is a linear function with a slope of -1, starting just beyond \(x=2\). At \(x = 2\), the value is \(4\), and at \(x = 6\), it reaches 0. Thus it goes through \((2, 4)\) with an open point (not included) and \((6, 0)\) also as an open point.
4Step 4: Graph the Third Piece
For \(x \geq 6\), \(f(x) = 2x - 17\). This function is linear with a slope of 2, beginning at \((6, -5)\) and continuing. The point \((6, -5)\) is included, shown by a solid dot, and the line extends rightward from there.
5Step 5: Identifying Included and Excluded Points
Review the transitions at the boundaries of each piece: At \(x=2\), the point on the parabola \((2,4)\) is included, while on the line \((-x + 6)\), it is considered not included. At \(x=6\), the \(6-x\) line value \((6,0)\) is not included, while \((6,-5)\) on the \(2x-17\) line is included.
Key Concepts
Understanding and Graphing Piecewise FunctionsExploring Piecewise Nonlinear FunctionsInterpreting Graphs of Piecewise Functions
Understanding and Graphing Piecewise Functions
When working with piecewise functions, you will notice that these are a set of multiple functions, each given a specific interval over which it is applied. In our piecewise function example, we have three separate functions, each with its own domain:
- For \(x \leq 2\), the function is \(f(x) = x^2\), a quadratic curve.
- For \(2 < x < 6\), we use \(f(x) = 6 - x\), a linear function with a negative slope.
- Finally, for \(x \geq 6\), we have another linear function, \(f(x) = 2x - 17\), with a positive slope.
- Draw each segment of the function separately, observing the specified intervals.
- Mark endpoints carefully to show inclusion (solid dots) or exclusion (open dots).
- Check each transition between segments for continuity and the inclusion or exclusion of boundary values.
Exploring Piecewise Nonlinear Functions
Piecewise nonlinear functions can be more complex to graph due to the different types of equations involved. In our example, \(f(x) = x^2\) is a nonlinear function within the interval \(x \leq 2\). This type of function forms part of our piecewise function's graph as a parabola.Working with these functions requires:
- Identifying the vertex and shape of the nonlinear graph segment, like the parabola opening upwards from \(x \leq 2\) that travels from \((-2, 4)\) to \((2,4)\).
- Ensuring smooth curves and avoiding abrupt jumps within the individual sections, unless transitioning between different function rules.
Interpreting Graphs of Piecewise Functions
Understanding a piecewise function graph involves reading and interpreting each segment's characteristics. Let's break down how to interpret the segments and transitions effectively:
- Acknowledge how each sub-function behaves within its interval. The initial quadratic segment indicates a gradual change, portraying an ascending curve until \(x = 2\).
- Notice the linear portion \(6 - x\), reflecting a steady decline from \(x = 3\) to just before \(x = 6\). This part illustrates how a constant linear decrease looks over its interval. Both endpoints \((2, 4)\) and \((6, 0)\) are represented as open circles in the graph.
- The final equation \(2x - 17\) begins from \(x = 6\) with a significant increase, forming a straight line with a steep slope. The transition at \(x = 6\) involves a shift from a closed to open point, clearly representing the inclusion/exclusion of certain values.
Other exercises in this chapter
Problem 31
Evaluate each expression without using a calculator. $$ \left(\frac{1}{32}\right)^{2 / 5} $$
View solution Problem 31
For each quadratic function: a. Find the vertex using the vertex formula. b. Graph the function on an appropriate window. (Answers may differ.) $$ f(x)=x^{2}-40
View solution Problem 31
For each equation, find the slope \(m\) and \(y\) -intercept \((0, b)\) (when they exist) and draw the graph. $$ \frac{2 x}{3}-y=1 $$
View solution Problem 32
Evaluate each expression without using a calculator. $$ \left(\frac{1}{32}\right)^{3 / 5} $$
View solution