Problem 31
Question
27–32 Simplify the expression by using a double-angle formula or a half-angle formula. (a) \(\frac{\sin 8^{\circ}}{1+\cos 8^{\circ}} \quad\) (b) \(\frac{1-\cos 4 \theta}{\sin 4 \theta}\)
Step-by-Step Solution
Verified Answer
(a) Simplifies to \(\tan 4^{\circ}\); (b) simplifies to \(\tan 2\theta\).
1Step 1: Choosing the Right Formula for (a)
We need to simplify \( \frac{\sin 8^{\circ}}{1+\cos 8^{\circ}} \). We will use the identity for the tangent of a half-angle: \( \tan\left(\frac{\theta}{2}\right) = \frac{1 - \cos\theta}{\sin\theta} \). However, we can rearrange this as: \( \tan\left(\frac{\theta}{2}\right) = \frac{\sin\theta}{1 + \cos\theta} \).
2Step 2: Simplifying Expression (a)
Recognize that the expression \( \frac{\sin 8^{\circ}}{1 + \cos 8^{\circ}} \) matches the form of \( \tan\left(\frac{8^{\circ}}{2}\right) \). Hence it simplifies directly to \( \tan 4^{\circ} \).
3Step 3: Choosing the Right Formula for (b)
We need to simplify \( \frac{1 - \cos 4\theta}{\sin 4\theta} \). Once again, using the tangent of half angle identity, \( \tan\left(\frac{\theta}{2}\right) = \frac{1 - \cos\theta}{\sin\theta} \), this expression simplifies to \( \tan 2\theta \) where \( \theta = 4\theta \).
4Step 4: Simplifying Expression (b)
Now \( \frac{1 - \cos 4\theta}{\sin 4\theta} \) simplifies to \( \tan 2\theta \) thus \( \tan 2\times 2\theta = \tan 2\theta \). Therefore, the expression is already in its simplest form as \( \tan 2\theta \).
Key Concepts
Double-Angle FormulasHalf-Angle FormulasTrigonometric Simplification
Double-Angle Formulas
Double-angle formulas are a type of trigonometric identity that relate functions of an angle to functions of its double, or twice its measure. They are especially handy when simplifying trigonometric expressions or solving trigonometric equations.
One of the most commonly used double-angle formulas is:
One of the most commonly used double-angle formulas is:
- \( \sin(2\theta) = 2 \sin\theta \cos\theta \)
- \( \cos(2\theta) = \cos^2\theta - \sin^2\theta \)
- \( \tan(2\theta) = \frac{2\tan\theta}{1 - \tan^2\theta}\)
Half-Angle Formulas
Half-angle formulas are another group of trigonometric identities useful for breaking down expressions involving angles that are halved. These formulas help simplify expressions by relating the trigonometric functions of an angle to those of half the angle.
Here are some key half-angle formulas:
Here are some key half-angle formulas:
- \( \sin\left(\frac{\theta}{2}\right) = \pm \sqrt{\frac{1 - \cos\theta}{2}} \)
- \( \cos\left(\frac{\theta}{2}\right) = \pm \sqrt{\frac{1 + \cos\theta}{2}} \)
- \( \tan\left(\frac{\theta}{2}\right) = \frac{\sin\theta}{1 + \cos\theta} = \frac{1 - \cos\theta}{\sin\theta} \)
Trigonometric Simplification
Trigonometric simplification involves rewriting complex trigonometric expressions into simpler or more manageable forms. This is particularly useful when working with equations that are challenging to solve directly.
In many cases, trigonometric identities, like the double-angle and half-angle formulas, are used to achieve simplification. The process typically involves:
In many cases, trigonometric identities, like the double-angle and half-angle formulas, are used to achieve simplification. The process typically involves:
- Identifying which identities can reduce complexity.
- Applying these identities to convert the original expression.
- Further simplifying using algebraic manipulations or additional identities.
Other exercises in this chapter
Problem 31
Find all solutions of the equation. $$\cos \frac{x}{2}-1=0$$
View solution Problem 31
\(23-40\) . Prove the identity. $$ \sin (x+y)-\sin (x-y)=2 \cos x \sin y $$
View solution Problem 32
Find all solutions of the equation. $$2 \sin \frac{x}{3}+\sqrt{3}=0$$
View solution Problem 32
\(23-40\) . Prove the identity. $$ \cos (x+y)+\cos (x-y)=2 \cos x \cos y $$
View solution