Problem 309
Question
In the following exercises, simplify. $$ (-4+\sqrt{17})(-3+\sqrt{17}) $$
Step-by-Step Solution
Verified Answer
29 - 7\text{√}{17}
1Step 1: Apply the Distributive Property
Use the distributive property \((a+b)(c+d) = ac + ad + bc + bd\) to multiply \((-4+\text{√}{17})(-3+\text{√}{17})\).
2Step 2: Multiply Each Term
Multiply each term in the first binomial by each term in the second binomial: \((-4 \times -3) + (-4 \times \text{√}{17}) + (\text{√}{17} \times -3) + (\text{√}{17} \times \text{√}{17})\).
3Step 3: Simplify the Products
Calculate the individual products: \(-4 \times -3 = 12\), \(-4 \times \text{√}{17} = -4\text{√}{17}\), \(\text{√}{17} \times -3 = -3\text{√}{17}\), and \(\text{√}{17} \times \text{√}{17} = 17\).
4Step 4: Combine Like Terms
Combine the calculated products: \(12 - 4\text{√}{17} - 3\text{√}{17} + 17\)
5Step 5: Final Simplification
Add and combine like terms: \(12 + 17 - 4\text{√}{17} - 3\text{√}{17} = 29 - 7\text{√}{17}\)
Key Concepts
distributive propertybinomial multiplicationcombining like termssquare roots in algebra
distributive property
To understand algebra simplification, the distributive property is a good starting point. The distributive property states that \( a(b+c) = ab + ac \). This means you distribute the term outside the parenthesis to each term inside the parenthesis.
In our exercise, we have: \((-4 + \sqrt{17})(-3 + \sqrt{17})\).
By using the distributive property, we distribute each term in the first binomial, \((-4 + \sqrt{17})\), to each term in the second binomial, \((-3 + \sqrt{17})\). This breaks down the multiplication into simpler steps, which we can solve individually.
In our exercise, we have: \((-4 + \sqrt{17})(-3 + \sqrt{17})\).
By using the distributive property, we distribute each term in the first binomial, \((-4 + \sqrt{17})\), to each term in the second binomial, \((-3 + \sqrt{17})\). This breaks down the multiplication into simpler steps, which we can solve individually.
binomial multiplication
Binomial multiplication is an extension of the distributive property, applied when we have two binomials.
In the exercise, we multiplied each term in the first binomial by each term in the second binomial.
For example, \( (-4 + \sqrt{17})(-3 + \sqrt{17})\) results in 4 separate products:
In the exercise, we multiplied each term in the first binomial by each term in the second binomial.
For example, \( (-4 + \sqrt{17})(-3 + \sqrt{17})\) results in 4 separate products:
- \(-4 \times -3\)
- \(-4 \times \sqrt{17}\)
- \(\sqrt{17} \times -3\)
- \(\sqrt{17} \times \sqrt{17}\)
combining like terms
After multiplying the binomials, our next step is to combine like terms. Like terms are terms that have the same variable raised to the same power
From the multiplication, we have: \(12, -4\sqrt{17}, -3\sqrt{17},\) and \(17\).
Our simplified expression is \( 29 - 7\sqrt{17} \). Combining like terms helps to simplify the expression into its most reduced form.
From the multiplication, we have: \(12, -4\sqrt{17}, -3\sqrt{17},\) and \(17\).
- Combine the constants \(12 + 17\), which equals \(29\).
- Combine the square root terms: \(-4\sqrt{17} - 3\sqrt{17}\), which equals \(-7\sqrt{17}\).
Our simplified expression is \( 29 - 7\sqrt{17} \). Combining like terms helps to simplify the expression into its most reduced form.
square roots in algebra
Dealing with square roots in algebra often requires understanding their properties. For instance, \(\sqrt{a} \times \sqrt{a} = a\). In our case, \(\sqrt{17} \times \sqrt{17} = 17\).
Working with square roots also means recognizing them as like terms when they have the same radicand.
In our exercise, \(-4\sqrt{17} \) and \(-3\sqrt{17}\) are like terms that can be combined easily.
Working with square roots also means recognizing them as like terms when they have the same radicand.
In our exercise, \(-4\sqrt{17} \) and \(-3\sqrt{17}\) are like terms that can be combined easily.
Other exercises in this chapter
Problem 307
In the following exercises, simplify. $$ (\sqrt{29})^{2} $$
View solution Problem 308
In the following exercises, simplify. $$ (-4 \sqrt{17})(-3 \sqrt{17}) $$
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Use the binomial square pattern to simplify \((3+\sqrt{2})^{2} .\) Explain all your steps.
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In the following exercises, simplify. $$ \frac{\sqrt{27}}{6} $$
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