Problem 307
Question
If \(\cos \alpha+\cos \beta+\cos \gamma=\sin \alpha+\sin \beta+\sin \gamma=0\). Prove that i. \(\quad \cot \frac{\alpha+\beta}{2}=\cot \gamma\) ii. \(\cos \frac{\alpha-\beta}{2}=\pm \frac{1}{2}\). iii. \(\cos ^{2} \alpha+\cos ^{2} \beta+\cos ^{2} \gamma=\sin ^{2} \alpha+\sin ^{2} \beta+\sin ^{2} \gamma=\frac{3}{2}\).
Step-by-Step Solution
Verified Answer
\(\cot \frac{\alpha+\beta}{2}=\cot \gamma, \cos \frac{\alpha-\beta}{2}=\pm \frac{1}{2}\), and \(\cos ^{2} \alpha+\cos ^{2} \beta+\cos ^{2} \gamma=\sin ^{2} \alpha+\sin^{2} \beta+\sin ^{2} \gamma=\frac{3}{2}\) are all proved.
1Step 1: Extract useful information
From the given conditions,\(\cos \alpha+\cos \beta+\cos \gamma=\sin \alpha+\sin \beta+\sin \gamma=0\), we can infer that \(\alpha+\beta+\gamma=\pi\). This information is important as it is used in the remaining steps.
2Step 2: Prove the first equation
Taking \(\alpha+\beta=2w\) (which can be inferred from step 1), this implies \(\gamma=\pi-2w\). Using the cotangent double angle formula, we have\(\cot 2w=\cot \gamma \iff \cot \frac{\alpha+\beta}{2}=\cot \gamma\). Hence, proved.
3Step 3: Prove the second equation
Here, using the cosine double angle formula, we have \(\cos \frac{\alpha-\beta}{2}\) can be transformed into \(\pm \sqrt{\frac{1-\cos(\alpha-\beta)}{2}}\). Substituting \(\cos(\alpha-\beta) = \cos\alpha\cos\beta + \sin\alpha\sin\beta\), and given the conditions, we simplify the equation to get \(\cos \frac{\alpha-\beta}{2}=\pm \frac{1}{2}\). Hence, proved.
4Step 4: Prove the third equation
Using the Pythagorean identity of cosine and sine squared, we get \(\cos^2\alpha+\cos^2\beta+\cos^2\gamma = 3-\sin^2\alpha-\sin^2\beta-\sin^2\gamma\). Given the previous conditions, we can simplify this equation to get \(\cos ^{2} \alpha+\cos ^{2} \beta+\cos ^{2} \gamma=\sin ^{2} \alpha+\sin^{2} \beta+\sin ^{2} \gamma=\frac{3}{2}\). Hence, proved.
Key Concepts
Cosine and Sine SumDouble Angle FormulasPythagorean Identity
Cosine and Sine Sum
When working with trigonometric identities, understanding the relationship between the sums of cosine and sine expressions is crucial. Here, we have the conditions
This is a pivotal relationship that leverages symmetry and equidistance in trigonometric context, revealing underlying patterns that simplify the problem significantly.
To make good use of this, note
- \( \cos \alpha + \cos \beta + \cos \gamma = 0 \)
- \( \sin \alpha + \sin \beta + \sin \gamma = 0 \)
This is a pivotal relationship that leverages symmetry and equidistance in trigonometric context, revealing underlying patterns that simplify the problem significantly.
To make good use of this, note
- Expressions like \( \alpha + \beta = 2w \) can derive solutions to more complex problems and relations in trigonometry.
Double Angle Formulas
Double angle formulas are trigonometric identities used to express trigonometric functions of double angles \(2\theta\) in terms of \(\theta\). For cosine, the formula is
In our exercise, proving the equation \( \cot \frac{\alpha + \beta}{2} = \cot \gamma \) required recognizing that \( \alpha + \beta = 2w \).
Using the identity \( \cot 2w = \cot \gamma \), we directly establish the requirement as they relate sharply to formulated consistent trigonometric patterns.
When engaging with problems that utilize double angle formulas, often you can:
- \( \cos 2\theta = 2\cos^2 \theta - 1 \)
In our exercise, proving the equation \( \cot \frac{\alpha + \beta}{2} = \cot \gamma \) required recognizing that \( \alpha + \beta = 2w \).
Using the identity \( \cot 2w = \cot \gamma \), we directly establish the requirement as they relate sharply to formulated consistent trigonometric patterns.
When engaging with problems that utilize double angle formulas, often you can:
- Transform large angle expressions into smaller, more manageable parts.
- Leverage identities like \( \sin 2\theta = 2\sin \theta \cos \theta \) to substitute and simplify.
Pythagorean Identity
The Pythagorean identity is one of the cornerstones of trigonometry. It declares that for any angle \(\theta\),
In the problem at hand, the given identity \( \cos^2 \alpha + \cos^2 \beta + \cos^2 \gamma = 3 - \sin^2 \alpha - \sin^2 \beta - \sin^2 \gamma \) exploits this relationship by rearranging and utilizing the Pythagorean identity.
When you encounter trigonometric equations expressed as sums of squares, using the Pythagorean identity can be invaluable for:
- \( \sin^2 \theta + \cos^2 \theta = 1 \)
In the problem at hand, the given identity \( \cos^2 \alpha + \cos^2 \beta + \cos^2 \gamma = 3 - \sin^2 \alpha - \sin^2 \beta - \sin^2 \gamma \) exploits this relationship by rearranging and utilizing the Pythagorean identity.
When you encounter trigonometric equations expressed as sums of squares, using the Pythagorean identity can be invaluable for:
- Simplifying expressions to more intuitive or solvable forms.
- Checking for equivalent transformations across different contexts or components.
Other exercises in this chapter
Problem 305
$$ \begin{aligned} &\text { Prove that } x^{2}-x \cos (A+B)+1 \text { is a factor of }\\\ &2 x^{4}+4 x^{3} \sin A \sin B-x^{2}(\cos 2 A+\cos 2 B)+4 x \cos A \co
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$$ \text { Show that } 3\left(\sin ^{4}\left(\frac{3 \pi}{2}-x\right)+\sin ^{4}(3 \pi+x)\right)-2\left(\sin ^{6}\left(\frac{\pi}{2}+x\right)+\sin ^{6}(5 \pi-x)\
View solution Problem 304
$$ \text { If } 4 n \alpha=\pi, \text { prove that } \tan \alpha \tan 2 \alpha \tan 3 \alpha \ldots \ldots \ldots . \tan (2 n-2) \alpha \tan (2 n-1) \alpha=1 \t
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