Problem 30
Question
Write with positive exponents. Simplify if possible. $$ 64^{-2 / 3} $$
Step-by-Step Solution
Verified Answer
\(\frac{1}{16}\)
1Step 1: Rewrite using the Positive Exponent
The expression given is \(64^{-2/3}\). To rewrite this with a positive exponent, we use the reciprocal property of exponents: \(a^{-b} = \frac{1}{a^b}\). Therefore, \(64^{-2/3} = \frac{1}{64^{2/3}}\).
2Step 2: Consider the Cube Root
Now, we need to simplify \(64^{2/3}\). The fractional exponent \(64^{2/3}\) means we first take the cube root of 64 and then square the result. Recall that \(64 = 4^3\). Therefore, \(64^{1/3} = 4\).
3Step 3: Square the Result from the Root
Having found the cube root to be 4 in the previous step, the next task is to square 4. Thus, \(4^2 = 16\). This means \(64^{2/3} = 16\).
4Step 4: Write the Simplified Expression
We substitute \(64^{2/3} = 16\) back into the expression \(\frac{1}{64^{2/3}}\) to get \(\frac{1}{16}\). This is the simplest form of the given expression.
Key Concepts
Positive ExponentsFractional ExponentsSimplifying ExpressionsReciprocal Property of Exponents
Positive Exponents
In math, dealing with positive exponents is all about positivity! When an exponent is positive, it suggests that we multiply the base with itself the number of times shown by the exponent. For example, with the expression \(a^b\), if \(b\) is a positive number, you'd multiply \(a\), \(b\) times.
This results in a larger number if the base \(a\) is greater than 1. Working with positive exponents makes our calculations straightforward.
This results in a larger number if the base \(a\) is greater than 1. Working with positive exponents makes our calculations straightforward.
- Expression: \(3^2\)
- Calculation: \(3 \times 3 = 9\)
Fractional Exponents
Fractional exponents offer a dynamic way to express roots and powers in a single step. Let's demystify this a little. A fractional exponent like \(a^{m/n}\) means you take the \(n\)-th root of \(a\) and then raise the result to the \(m\)-th power.
Consider \(64^{2/3}\):
Consider \(64^{2/3}\):
- Start by finding the cube root, since our denominator is 3. \(64^{1/3} = 4\) because \(4^3 = 64\).
- Next, take that result, 4, and square it because our numerator is 2: \(4^2 = 16\).
Simplifying Expressions
Simplifying expressions ensures that we are working with the most efficient or concise version of a number or equation. Simplification might involve turning a complex or cumbersome expression into something more digestible.
When simplifying \(64^{-2/3}\):
When simplifying \(64^{-2/3}\):
- We start by converting the negative exponent to its reciprocal form: \(\frac{1}{64^{2/3}}\).
- Then we simplify \(64^{2/3}\) by first finding the cube root of 64 and then squaring the result, leading us to \(\frac{1}{16}\).
Reciprocal Property of Exponents
The reciprocal property of exponents is a powerful tool when dealing with negative exponents. The property states that \(a^{-b} = \frac{1}{a^b}\). This means if you face a negative exponent, you can "flip" it into the denominator, turning it positive.
Using \(64^{-2/3}\) as an example, the reciprocal property came to the rescue:
Using \(64^{-2/3}\) as an example, the reciprocal property came to the rescue:
- Transformation: \(64^{-2/3} = \frac{1}{64^{2/3}}\)
- This step is crucial because it transforms a negative exponent into a manageable positive one.
Other exercises in this chapter
Problem 29
Add or subtract. $$ \sqrt[3]{54 x y^{3}}-5 \sqrt[3]{2 x y^{3}}+y \sqrt[3]{128 x} $$
View solution Problem 29
Rationalize each denominator. See Examples 1 through 3. $$ \sqrt[4]{\frac{81}{8}} $$
View solution Problem 30
Add or subtract. Write the sum or difference in the form \(a+b i .\) See Example 3 $$ (8-3 i)+(-8+3 i) $$
View solution Problem 30
Solve. \(\sqrt[4]{2 x-9}-3=0\)
View solution