Problem 30
Question
Write the expression in the form \(a+b i\), where \(a\) and \(b\) are real numbers. $$ (-3+\sqrt{-25})(8-\sqrt{-36}) $$
Step-by-Step Solution
Verified Answer
The expression is simplified to \(6 + 58i\).
1Step 1: Simplify Square Roots of Negative Numbers
First, we simplify the square roots of negative numbers using the imaginary unit, which is defined as \(i = \sqrt{-1}\). Therefore, \(\sqrt{-25} = \sqrt{25} \cdot \sqrt{-1} = 5i\) and \(\sqrt{-36} = \sqrt{36} \cdot \sqrt{-1} = 6i\). Now the expression becomes \((-3 + 5i)(8 - 6i)\).
2Step 2: Distribute the Terms
To multiply the expression \((-3 + 5i)(8 - 6i)\), we use the distributive property (FOIL method): - Multiply \(-3\) by \(8\): \(-3 \cdot 8 = -24\).- Multiply \(-3\) by \(-6i\): \(-3 \cdot -6i = 18i\).- Multiply \(5i\) by \(8\): \(5i \cdot 8 = 40i\).- Multiply \(5i\) by \(-6i\): \(5i \cdot -6i = -30i^2\).
3Step 3: Simplify the Terms
Now, add these results together: \(-24 + 18i + 40i - 30i^2\). The term \(-30i^2\) simplifies to \(30\) because \(i^2 = -1\). Thus, the expression becomes:\(-24 + 58i + 30\).
4Step 4: Combine Real Parts and Imaginary Parts
Combine the real parts and the imaginary parts separately: - Real part: \(-24 + 30 = 6\).- Imaginary part: \(58i\).So, the expression is simplified to \(6 + 58i\).
Key Concepts
Imaginary UnitDistributive PropertySimplifying Expressions
Imaginary Unit
The imaginary unit, denoted as \(i\), is a fundamental concept in complex numbers. It is defined as the square root of \(-1\), making it unique and essential when dealing with numbers that involve square roots of negative values. In mathematics, the symbol \(i\) is specifically used to handle equations where a negative value appears under a square root.
When you encounter a square root of a negative number, such as \(\sqrt{-25}\), it can be simplified using the imaginary unit. This is done by separating the negative sign as \(\sqrt{-1} = i\), allowing for further calculations. For instance:
When you encounter a square root of a negative number, such as \(\sqrt{-25}\), it can be simplified using the imaginary unit. This is done by separating the negative sign as \(\sqrt{-1} = i\), allowing for further calculations. For instance:
- \(\sqrt{-25} = \sqrt{25} \cdot \sqrt{-1} = 5i\)
- \(\sqrt{-36} = \sqrt{36} \cdot \sqrt{-1} = 6i\)
Distributive Property
The distributive property is a key principle used when multiplying expressions, particularly those involving complex numbers. It allows us to systematically expand an expression by distributing each term across another. In this exercise, we use the distributive property to simplify the product \((-3 + 5i)(8 - 6i)\).
This method, often associated with the acronym FOIL (First, Outer, Inner, Last), involves multiplying each pair of terms from the binomials:
This method, often associated with the acronym FOIL (First, Outer, Inner, Last), involves multiplying each pair of terms from the binomials:
- First: \(-3 \times 8 = -24\)
- Outer: \(-3 \times -6i = 18i\)
- Inner: \(5i \times 8 = 40i\)
- Last: \(5i \times -6i = -30i^2\)
Simplifying Expressions
Simplifying expressions involves combining like terms and arranging the expression into a more readable and compact form. With complex numbers, this means separately dealing with real and imaginary components, then combining them whenever possible.
Consider the expression: \(-24 + 18i + 40i - 30i^2\). Here, you:
Consider the expression: \(-24 + 18i + 40i - 30i^2\). Here, you:
- Recognize and simplify \(-30i^2\) to \(30\) using \(i^2 = -1\)
- Combine imaginary terms: \(18i + 40i = 58i\)
- Add real numbers: \(-24 + 30 = 6\)
Other exercises in this chapter
Problem 29
Exer. 11-46: Simplify. $$ \left(5 x^{2} y^{-3}\right)\left(4 x^{-5} y^{4}\right) $$
View solution Problem 29
Exer. 25-32: Rewrite the expression without using the absolute value symbol, and simplify the result. $$ |a-b| \text { if } a
View solution Problem 30
Express as a polynomial. $$ \left(2 x^{2}+5 y^{2}\right)^{2} $$
View solution Problem 30
Exer. 11-46: Simplify. $$ \left(-2 r^{2} s\right)^{5}\left(3 r^{-1} s^{3}\right)^{2} $$
View solution