Problem 30
Question
Which kind of isomerism is exhibited by octahedral \(\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{4} \mathrm{Br}_{2} \mathrm{Cl} ?\) (a) Geometrical and Ionization (b) Geometrical and Optical (c) Optical and Ionization (d) Geometrical only
Step-by-Step Solution
Verified Answer
The complex exhibits geometrical and ionization isomerism.
1Step 1: Understanding the Complex Structure
The given complex is \( \mathrm{Co}\left(\mathrm{NH}_{3}\right)_{4} \mathrm{Br}_{2} \mathrm{Cl} \). It is an octahedral coordination compound with cobalt as the central metal atom. It is surrounded by four \(\mathrm{NH}_3\) ligands, two bromide ions (\(\mathrm{Br}^-\)), and one chloride ion (\(\mathrm{Cl}^-\)).
2Step 2: Identifying Possible Isomers
Due to the presence of different ligands (\(\mathrm{NH}_3\), \(\mathrm{Br}^- ext{ and }\mathrm{Cl}^-\)), this complex can exhibit geometrical isomerism due to different possible arrangements of these ligands around the central metal atom. Also, different ions (\(\mathrm{Br}^-\) and \(\mathrm{Cl}^-\)) provide the possibility for ionization isomerism.
3Step 3: Geometrical Isomerism Explanation
Geometrical isomerism is possible in octahedral complexes when there are different ways to arrange the ligands around the metal. In this complex, the \(\mathrm{Br}^- ext{ and }\mathrm{Cl}^-\) ions can be next to each other (cis) or opposite each other (trans).
4Step 4: Checking for Optical Isomerism
Optical isomerism typically occurs in chiral complexes that have no plane of symmetry. In octahedral complexes, it arises when the ligands are arranged in a non-superimposable mirror image fashion. However, this specific structure of \( \mathrm{Co}\left(\mathrm{NH}_{3}\right)_{4} \mathrm{Br}_{2} \mathrm{Cl} \) does not allow for optical activity due to its symmetric substitution pattern.
5Step 5: Ionization Isomerism Explanation
Ionization isomerism occurs when the exchange of ligands between the inner coordination sphere and the outer coordination sphere leads to different compounds. The exchange between \(\mathrm{Br}^-\) and \(\mathrm{Cl}^-\) can result in different ionization products, indicating that ionization isomerism is possible. Thus, both geometrical and ionization isomerism are exhibited by this complex.
Key Concepts
Geometrical IsomerismIonization IsomerismOptical Isomerism
Geometrical Isomerism
Geometrical isomerism is a form of stereoisomerism that occurs in coordination compounds where the spatial arrangement of ligands around the central metal atom differ. Imagine a simple model where ligands can be oriented in different positions such as side-by-side or opposite from one another.
In the case of the octahedral complex \( \mathrm{Co}\left(\mathrm{NH}_{3}\right)_{4} \mathrm{Br}_{2} \mathrm{Cl} \), it can exhibit geometrical isomerism due to the different orientations of the bromide (\(\mathrm{Br}^-\)) and chloride (\(\mathrm{Cl}^-\)) ions compared to each other.
In the case of the octahedral complex \( \mathrm{Co}\left(\mathrm{NH}_{3}\right)_{4} \mathrm{Br}_{2} \mathrm{Cl} \), it can exhibit geometrical isomerism due to the different orientations of the bromide (\(\mathrm{Br}^-\)) and chloride (\(\mathrm{Cl}^-\)) ions compared to each other.
- Cis isomer: Bromide ions are adjacent to each other.
- Trans isomer: Bromide ions are across from each other.
Ionization Isomerism
Ionization isomerism occurs when there is an exchange of ligands between the coordination sphere and the outside of the complex. This leads to different isomeric compounds which possess different ions in solution. Each isomer has a distinct identity and chemical formula based on its ion composition.
For the compound \( \mathrm{Co}\left(\mathrm{NH}_{3}\right)_{4} \mathrm{Br}_{2} \mathrm{Cl} \), ionization isomerism arises because of the switch between \( \mathrm{Br}^- \) and \( \mathrm{Cl}^- \) ions.
The coordination sphere can contain either one of these ligands while the other remains outside.
This creates different compounds which can affect the compound's reactivity, color, and how it conducts electricity when dissolved in water.
For the compound \( \mathrm{Co}\left(\mathrm{NH}_{3}\right)_{4} \mathrm{Br}_{2} \mathrm{Cl} \), ionization isomerism arises because of the switch between \( \mathrm{Br}^- \) and \( \mathrm{Cl}^- \) ions.
The coordination sphere can contain either one of these ligands while the other remains outside.
This creates different compounds which can affect the compound's reactivity, color, and how it conducts electricity when dissolved in water.
- Two isomers: One with bromide inside the coordination complex and chloride outside.
- Another with chloride inside and bromide outside.
Optical Isomerism
Optical isomerism is a type of stereoisomerism related to the presence of chirality. In simple terms, it occurs when a complex has non-superimposable mirror images, much like a pair of hands.
These isomers, called enantiomers, rotate plane-polarized light in different directions – one clockwise and the other counterclockwise. This property leads us to the "optical" part of its name.
However, not all complexes exhibit optical isomerism. For an octahedral compound like \( \mathrm{Co}\left(\mathrm{NH}_{3}\right)_{4} \mathrm{Br}_{2} \mathrm{Cl} \), the presence of a symmetric arrangement of ligands means it does not possess optical isomerism.
These isomers, called enantiomers, rotate plane-polarized light in different directions – one clockwise and the other counterclockwise. This property leads us to the "optical" part of its name.
However, not all complexes exhibit optical isomerism. For an octahedral compound like \( \mathrm{Co}\left(\mathrm{NH}_{3}\right)_{4} \mathrm{Br}_{2} \mathrm{Cl} \), the presence of a symmetric arrangement of ligands means it does not possess optical isomerism.
- The compound must lack a plane of symmetry for optical isomers to exist.
- The specific symmetric layout in this complex disallows optical activity.
Other exercises in this chapter
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