Problem 30
Question
Verify that the given functions form a fundamental set of solutions of the differential equation on the indicated interval. Form the general solution. $$ y^{(4)}+y^{\prime \prime}=0 ; 1, x, \cos x, \sin x,(-\infty, \infty) $$
Step-by-Step Solution
Verified Answer
The functions form a fundamental set; the general solution is \( y = C_1 + C_2 x + C_3 \cos x + C_4 \sin x \).
1Step 1: Understanding the Differential Equation
The given differential equation is a fourth-order linear homogeneous differential equation: \( y^{(4)} + y'' = 0 \). We need to verify if the functions \( 1, x, \cos x, \sin x \) form a fundamental set of solutions for this equation over the interval \( (-\infty, \infty) \).
2Step 2: Checking Linear Independence
To verify if these functions form a fundamental set of solutions, they must be linearly independent. Calculate the Wronskian determinant of the functions: \( W(1, x, \cos x, \sin x) \). If the Wronskian is non-zero for some \( x \) in the interval, the functions are linearly independent.
3Step 3: Computation of the Wronskian
Compute the Wronskian: \[W(1, x, \cos x, \sin x) = \begin{vmatrix}1 & x & \cos x & \sin x \0 & 1 & -\sin x & \cos x \0 & 0 & -\cos x & -\sin x \0 & 0 & \sin x & -\cos x\end{vmatrix}.\]Simplifying the determinant, we find it is non-zero, confirming linear independence.
4Step 4: Verify the Solutions for the DE
Verify that each function satisfies the differential equation. 1. The fourth derivative of \(1\) and \(x\) is zero, and their second derivatives are zero, so they satisfy the equation.2. The fourth derivative of \(\cos x\) is \(\cos x\), and its second derivative is \(-\cos x\); hence, \(\cos x\) satisfies the equation.3. Similarly, the fourth derivative of \(\sin x\) is \(\sin x\), and its second derivative is \(-\sin x\); thus, \(\sin x\) satisfies the equation.
5Step 5: Forming the General Solution
With the confirmed fundamental set \( \{ 1, x, \cos x, \sin x \} \), the general solution for the differential equation is a linear combination of these functions: \[ y(x) = C_1 + C_2 x + C_3 \cos x + C_4 \sin x, \]where \( C_1, C_2, C_3, C_4 \) are arbitrary constants.
Key Concepts
Fundamental Set of SolutionsWronskian DeterminantLinear IndependenceGeneral Solution of Differential Equations
Fundamental Set of Solutions
When solving higher-order differential equations, one of the key steps is identifying a fundamental set of solutions. A fundamental set effectively gives us a basis for the solution space of the differential equation. In simpler terms, it is a group of solutions that can be combined to form the most general solution for the equation. For a set of solutions to be deemed 'fundamental,' they must be linearly independent. This ensures they provide a complete representation of the solution space.
In the context of the exercise, the functions \(1, x, \cos x, \sin x\) were considered to form a fundamental set of solutions for the given differential equation. They together cover various behaviors of the potential solutions, such as constant, linear, and trigonometric forms.
In the context of the exercise, the functions \(1, x, \cos x, \sin x\) were considered to form a fundamental set of solutions for the given differential equation. They together cover various behaviors of the potential solutions, such as constant, linear, and trigonometric forms.
Wronskian Determinant
The Wronskian determinant is an essential tool in determining whether a group of functions is linearly independent. To calculate it, we construct a matrix where each row is composed of the derivatives of the functions being tested. The determinant of this matrix is the Wronskian. If a Wronskian is non-zero at any point in the interval, the functions are linearly independent.
For the functions \(1, x, \cos x, \sin x\), calculating the Wronskian yields a non-zero value, indicating these functions are linearly independent. Computing the determinant involves differentiating each function up to the third derivative and organizing these into a matrix. Simplifying the determinant shows it is not zero, confirming our functions are a fundamental set.
For the functions \(1, x, \cos x, \sin x\), calculating the Wronskian yields a non-zero value, indicating these functions are linearly independent. Computing the determinant involves differentiating each function up to the third derivative and organizing these into a matrix. Simplifying the determinant shows it is not zero, confirming our functions are a fundamental set.
Linear Independence
Linear independence between functions means that no function in the set can be written as a linear combination of the others. This is crucial when forming a fundamental set of solutions because it confirms the uniqueness and completeness of the set.
By using the Wronskian determinant, it is straightforward to test for linear independence. In this exercise, the fact that the determinant of the matrix \(W(1, x, \cos x, \sin x)\) is non-zero confirms that these functions cannot be written in terms of each other. Therefore, they span the solution space of the differential equation without any redundancies.
By using the Wronskian determinant, it is straightforward to test for linear independence. In this exercise, the fact that the determinant of the matrix \(W(1, x, \cos x, \sin x)\) is non-zero confirms that these functions cannot be written in terms of each other. Therefore, they span the solution space of the differential equation without any redundancies.
General Solution of Differential Equations
The general solution of a differential equation is a combination of all possible solutions expressed in their simplest form. It represents the entire solution space and includes arbitrary constants, which can be adjusted based on initial conditions or specific requirements.
For the given fourth-order differential equation \(y^{(4)} + y'' = 0\), with the verified fundamental set \( \{1, x, \cos x, \sin x\} \), the general solution can be constructed by taking a linear combination of these functions. Thus, the solution is given by:
\[ y(x) = C_1 + C_2 x + C_3 \cos x + C_4 \sin x \]
Here, \(C_1, C_2, C_3,\) and \(C_4\) are arbitrary constants that allow the general solution to meet specific boundary or initial conditions.
For the given fourth-order differential equation \(y^{(4)} + y'' = 0\), with the verified fundamental set \( \{1, x, \cos x, \sin x\} \), the general solution can be constructed by taking a linear combination of these functions. Thus, the solution is given by:
\[ y(x) = C_1 + C_2 x + C_3 \cos x + C_4 \sin x \]
Here, \(C_1, C_2, C_3,\) and \(C_4\) are arbitrary constants that allow the general solution to meet specific boundary or initial conditions.
Other exercises in this chapter
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