Problem 30
Question
Use the given conditions to write an equation for each line in point-slope form and slope-intercept form. Passing through \((-2,-4)\) and \((1,-1)\)
Step-by-Step Solution
Verified Answer
The equation of the line in point-slope form is \(y=x-2\), and in slope-intercept form, it is \(y=x-2\).
1Step 1: Find the slope
Firstly, the slope of the line must be calculated. The slope \(m\) between two points \((x_1, y_1)\) and \((x_2, y_2)\) can be found using the formula \(m = \frac{y_2 - y_1}{x_2 - x_1}\). Here, \((x_1,y_1)=(-2,-4)\) and \((x_2,y_2)=(1,-1)\), so the slope becomes \(m = \frac{-1 - (-4)}{1 - (-2)} = 1\).
2Step 2: Write the point-slope form
Now, substitute the slope and one point \((x_1, y_1)\) into the point-slope form formula. That yields \(y-y_1=m(x-x_1)\). Insert the values: \(y - (-4) = 1(x - (-2))\), which reduces to \(y + 4 = x + 2\), finally simplified to \(y = x - 2\).
3Step 3: Write the slope-intercept form
Finally, substitute the slope and the y-intercept into the slope-intercept form formula. In this case, the y-intercept is the point where the line crosses the y-axis. By looking at the equation from Step 2, the y-intercept \(b\) is -2, and the slope \(m\) is 1. With those values, the slope-intercept form of the line is \(y=1x-2\), which can be further simplified to \(y=x-2\).
Key Concepts
Point-Slope FormSlope-Intercept FormSlope Calculation
Point-Slope Form
Point-slope form is a convenient way of writing the equation for a line when you have a point on the line and its slope. The general formula for point-slope form is given by \(y - y_1 = m(x - x_1)\), where \((x_1, y_1)\) is the point on the line, and \(m\) represents the slope.
For instance, with a slope of 1 and a point (-2, -4), you substitute these values into the formula, ending up with \(y - (-4) = 1(x - (-2))\). Algebraic simplification gives you the equation \(y = x - 2\), as seen in the textbook solution. It's a straightforward way to draft a line's equation, and understanding this concept enables students to easily model linear relationships from real-world scenarios.
For instance, with a slope of 1 and a point (-2, -4), you substitute these values into the formula, ending up with \(y - (-4) = 1(x - (-2))\). Algebraic simplification gives you the equation \(y = x - 2\), as seen in the textbook solution. It's a straightforward way to draft a line's equation, and understanding this concept enables students to easily model linear relationships from real-world scenarios.
Slope-Intercept Form
The slope-intercept form is another popular way of expressing the equation of a line and is particularly useful when you're looking to immediately identify the slope and y-intercept of the line. It is written as \(y = mx + b\), where \(m\) is the slope and \(b\) is the y-intercept, which is the point where the line crosses the y-axis.
In our example, taking the slope, 1, from the calculation and the y-intercept, -2, from the simplified point-slope equation, you place these into the slope-intercept formula to get \(y = 1x - 2\), which simplifies to the very concise equation \(y = x - 2\). This is the ideal form for quickly graphing the line or determining how the line will behave without further calculations.
In our example, taking the slope, 1, from the calculation and the y-intercept, -2, from the simplified point-slope equation, you place these into the slope-intercept formula to get \(y = 1x - 2\), which simplifies to the very concise equation \(y = x - 2\). This is the ideal form for quickly graphing the line or determining how the line will behave without further calculations.
Slope Calculation
The slope is a measure of how steep a line is and the direction it tilts. The calculation of the slope is a critical step in defining the equation of a line and is determined using the coordinates of two distinct points on the line. The formula to find the slope \(m\) is \(m = \frac{y_2 - y_1}{x_2 - x_1}\).
To calculate the slope for our exercise, use the points (-2, -4) and (1, -1). By plugging these into the formula, we find that \(m = \frac{-1 - (-4)}{1 - (-2)} = \frac{3}{3} = 1\). Slope calculation forms the basis for both point-slope and slope-intercept forms and is essential for understanding the dynamics of linear relationships.
To calculate the slope for our exercise, use the points (-2, -4) and (1, -1). By plugging these into the formula, we find that \(m = \frac{-1 - (-4)}{1 - (-2)} = \frac{3}{3} = 1\). Slope calculation forms the basis for both point-slope and slope-intercept forms and is essential for understanding the dynamics of linear relationships.
Other exercises in this chapter
Problem 29
Find the domain of each function. $$ f(x)-\frac{2 x+7}{x^{3}-5 x^{2}-4 x+20} $$
View solution Problem 30
Find the midpoint of each line segment with the given endpoints. $$(\sqrt{50},-6)\( and \)(\sqrt{2}, 6)$$
View solution Problem 30
Find the domain of each function. $$ f(x)-\frac{7 x+2}{x^{3}-2 x^{2}-9 x+18} $$
View solution Problem 31
If two lines are parallel, describe the relationship between their slopes.
View solution