Problem 30
Question
Use the dot product to determine whether v and w are orthogonal. $$ \mathbf{v}=5 \mathbf{i}, \quad \mathbf{w}=-6 \mathbf{i} $$
Step-by-Step Solution
Verified Answer
No, the vectors \( \mathbf{v} \) and \( \mathbf{w} \) are not orthogonal.
1Step 1: Identify the vectors
The vectors given are \( \mathbf{v}=5 \mathbf{i} \) and \( \mathbf{w}=-6 \mathbf{i} \)
2Step 2: Compute the dot product
The dot product of two vectors \( \mathbf{v} \) and \( \mathbf{w} \) is calculated by multiplying the corresponding i, j, and k coefficients. In this case, only i coefficients are given. So, the dot product is \( (5)(-6) = -30 \).
3Step 3: Determine orthogonality
Since the dot product of vectors \( \mathbf{v} \) and \( \mathbf{w} \) is not zero (-30 ≠ 0), the vectors are not orthogonal.
Key Concepts
Orthogonal VectorsVector MathematicsAlgebra
Orthogonal Vectors
In vector mathematics, two vectors are said to be orthogonal if they meet at a right angle (90 degrees). The concept of orthogonal vectors is crucial because it simplifies many mathematical operations, particularly those involving geometry and physics.
For two vectors to be orthogonal, their dot product must be zero. The dot product gives us a measure of how much one vector extends in the direction of another. If there's no extension at all, as would be the case when vectors are perpendicular, the dot product is zero.
In the exercise provided, the vectors \( \mathbf{v}=5 \mathbf{i} \) and \( \mathbf{w}=-6 \mathbf{i} \) were considered. By calculating the dot product and finding it was \(-30\), it became clear these vectors are not orthogonal. This is because their product wasn’t zero, indicating they do not meet at a right angle.
For two vectors to be orthogonal, their dot product must be zero. The dot product gives us a measure of how much one vector extends in the direction of another. If there's no extension at all, as would be the case when vectors are perpendicular, the dot product is zero.
In the exercise provided, the vectors \( \mathbf{v}=5 \mathbf{i} \) and \( \mathbf{w}=-6 \mathbf{i} \) were considered. By calculating the dot product and finding it was \(-30\), it became clear these vectors are not orthogonal. This is because their product wasn’t zero, indicating they do not meet at a right angle.
Vector Mathematics
Vector mathematics involves operations that are fundamental to physics and engineering. Vectors can represent quantities like velocity, force, and displacement. These quantities have both magnitude and direction, which differentiates vectors from scalars.
The exercise demonstrates the use of the dot product. This operation is one way to measure how two vectors relate in space. Calculating the dot product of vectors \( \mathbf{v}=5 \mathbf{i} \) and \( \mathbf{w}=-6 \mathbf{i} \) involves multiplying their components. Since these vectors only include the \( i \)-component, the calculation simplifies to \( 5 \times (-6) = -30 \).
This highlights how simple vector calculations can be when vectors are aligned along the same axis. More complex vectors have components in multiple directions, each requiring consideration. Nevertheless, the intuitive result that only non-zero products prevent orthogonality simplifies reasoning about vector orientation.
The exercise demonstrates the use of the dot product. This operation is one way to measure how two vectors relate in space. Calculating the dot product of vectors \( \mathbf{v}=5 \mathbf{i} \) and \( \mathbf{w}=-6 \mathbf{i} \) involves multiplying their components. Since these vectors only include the \( i \)-component, the calculation simplifies to \( 5 \times (-6) = -30 \).
This highlights how simple vector calculations can be when vectors are aligned along the same axis. More complex vectors have components in multiple directions, each requiring consideration. Nevertheless, the intuitive result that only non-zero products prevent orthogonality simplifies reasoning about vector orientation.
Algebra
In algebra, the dot product is an example of how abstract mathematical concepts can be applied to solve problems in physics and engineering. Algebra provides the tools for working with vectors and understanding relationships between their components.
When using algebra to solve for the dot product between \( \mathbf{v} \) and \( \mathbf{w} \), do the following:
When using algebra to solve for the dot product between \( \mathbf{v} \) and \( \mathbf{w} \), do the following:
- Identify the corresponding components. Here, that is 5 for \( \mathbf{v} \) and \(-6\) for \( \mathbf{w} \).
- Multiply these components: \( 5 \times -6 \).
- Summing the products of all corresponding components gives the dot product, which here is \(-30\).
Other exercises in this chapter
Problem 29
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