Problem 30
Question
Use the distributive property to compute each product. \(95 \cdot 12\)
Step-by-Step Solution
Verified Answer
The product is 1140.
1Step 1: Break Down the Numbers
To make the multiplication easier, express 95 as a product of sums: \(95 = 90 + 5\). This allows us to use the distributive property easily.
2Step 2: Apply Distributive Property
Apply the distributive property to \(95 \cdot 12\) as follows: \((90 + 5) \cdot 12 = 90 \cdot 12 + 5 \cdot 12\). This breaks the calculation into simpler parts.
3Step 3: Multiply Each Term Separately
Calculate each part separately: \(90 \cdot 12 = 1080\) and \(5 \cdot 12 = 60\).
4Step 4: Add the Products
Sum the results of the separate multiplications: \(1080 + 60 = 1140\).
Key Concepts
MultiplicationBreaking Down NumbersSimplifying Calculations
Multiplication
Multiplication is a fundamental mathematical operation. It allows us to find the total number of objects in a set of equal groups. When you multiply, you are essentially adding the same number repeatedly. For example, multiplying 3 by 4 is the same as adding 3 four times:
- \( 3 + 3 + 3 + 3 = 12 \)
- \( 3 \times 4 = 12 \)
Breaking Down Numbers
Breaking down numbers is a helpful strategy in simplifying multiplication problems. It involves expressing a number as a sum of more manageable parts. For our exercise, breaking down 95 as \( 90 + 5 \) allows us to handle more straightforward calculations.
When numbers are broken down, it's easier to apply the distributive property, as with our original problem where 95 becomes \( 90 + 5 \). This decomposition lets us multiply each component separately. This step is crucial for simplifying the calculation process while maintaining accuracy. It’s much easier to compute calculations with round numbers like 90 or 10.
When numbers are broken down, it's easier to apply the distributive property, as with our original problem where 95 becomes \( 90 + 5 \). This decomposition lets us multiply each component separately. This step is crucial for simplifying the calculation process while maintaining accuracy. It’s much easier to compute calculations with round numbers like 90 or 10.
Simplifying Calculations
The goal of simplifying calculations is to make complex problems more manageable by breaking them into smaller, easy-to-handle parts. By using the distributive property, we convert a tough multiplication problem into a series of smaller, straightforward multiplications.
With the exercise example, once you break down 95 into \( 90 + 5 \) and apply the distributive property, you end up with two simpler multiplications: \( 90 \times 12 \) and \( 5 \times 12 \).
The distributive property allows:
With the exercise example, once you break down 95 into \( 90 + 5 \) and apply the distributive property, you end up with two simpler multiplications: \( 90 \times 12 \) and \( 5 \times 12 \).
The distributive property allows:
- \( 90 \times 12 = 1080 \)
- \( 5 \times 12 = 60 \)
Other exercises in this chapter
Problem 29
Estimate each calculation using the method of rounding. After you have made an estimate, find the exact value and compare this to the estimated result to see if
View solution Problem 30
Estimate each value using the method of rounding. After you have made an estimate, find the exact value. Compare the exact and estimated values. Results may var
View solution Problem 30
Estimate each calculation using the method of rounding. After you have made an estimate, find the exact value and compare this to the estimated result to see if
View solution Problem 31
Estimate each value using the method of rounding. After you have made an estimate, find the exact value. Compare the exact and estimated values. Results may var
View solution