Problem 30
Question
Translate the ellipse with the given equation so that it is centered at the given point. Find the new equation and sketch its graph. $$ \frac{x^{2}}{9}+\frac{y^{2}}{2}=1 ;(-3,7) $$
Step-by-Step Solution
Verified Answer
New equation: \( \frac{(x+3)^2}{9} + \frac{(y-7)^2}{2} = 1 \).
1Step 1: Understand the Current Equation
The given equation \( \frac{x^2}{9} + \frac{y^2}{2} = 1 \) represents an ellipse centered at the origin \((0,0)\). The semi-major axis is \(3\) units along the x-axis and the semi-minor axis is \(\sqrt{2}\) units along the y-axis.
2Step 2: Identify the New Center
We are required to translate the ellipse so that it is centered at \((-3, 7)\). Translation of the center involves moving the center from \((0,0)\) to \((-3,7)\).
3Step 3: Translate the Equation
To translate the ellipse, adjust the variables to reflect the new center \((-3, 7)\). This results in the transformed equation: \( \frac{(x+3)^2}{9} + \frac{(y-7)^2}{2} = 1 \).
4Step 4: Sketch the Graph
Draw the new ellipse with its center at \((-3, 7)\). The ellipse retains its shape, with a semi-major axis of 3 units along the x-axis and a semi-minor axis of \(\sqrt{2}\) units along the y-axis.
Key Concepts
Equation of an EllipseCenter of an EllipseGraphing Ellipses
Equation of an Ellipse
An ellipse is a fascinating shape in mathematics. Its equation can describe its dimensions and location on a coordinate plane. A standard form of an ellipse centered at the origin is expressed as \[\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1\]Here, \(a\) and \(b\) are the semi-major and semi-minor axes respectively. These axes measure the distance from the center of the ellipse to its perimeter along the x and y axes.
The given equation \( \frac{x^2}{9} + \frac{y^2}{2} = 1 \) reveals an ellipse centered at the origin \((0,0)\). In this version:
The given equation \( \frac{x^2}{9} + \frac{y^2}{2} = 1 \) reveals an ellipse centered at the origin \((0,0)\). In this version:
- The semi-major axis \(a\) is \(\sqrt{9} = 3\).
- The semi-minor axis \(b\) is \(\sqrt{2}\).
Center of an Ellipse
The center of an ellipse is a pivotal point that determines the ellipse's position but not its shape. When an ellipse's center is moved from one point to another, it's called a translation. This change shifts the entire ellipse on the coordinate plane without altering its dimensions or orientation.
Originally, our ellipse is centered at the origin \((0,0)\). In the exercise, we aim to move this center to the new location \((-3,7)\). To achieve this translation, we adjust every occurrence of \(x\) and \(y\) in the ellipse equation by modifying their variables:
Originally, our ellipse is centered at the origin \((0,0)\). In the exercise, we aim to move this center to the new location \((-3,7)\). To achieve this translation, we adjust every occurrence of \(x\) and \(y\) in the ellipse equation by modifying their variables:
- Replace \(x\) with \(x+3\).
- Replace \(y\) with \(y-7\).
Graphing Ellipses
Graphing ellipses visually represents the solution to its equation, giving a clear view of its features. When graphing an ellipse, a few steps ensure accuracy and clarity:
- Identify the Center: Start with marking the ellipse's center based on the given or transformed equation. For our new ellipse, this point is \((-3, 7)\).
- Plot the Axes: Use the values of \(a\) and \(b\) to draw the semi-major and semi-minor axes originating from the center. This determines the size and orientation of the ellipse. The semi-major axis extends 3 units along the x-axis from \((-3, 7)\), while the semi-minor axis stretches approximately \(\sqrt{2}\) units along the y-axis.
- Sketch the Ellipse: Once the axes are plotted, draw a smooth, oval shape ensuring it intersects the endpoints of these axes, forming the ellipse.
Other exercises in this chapter
Problem 27
Find an equation of the ellipse, centered at the origin, satisfying the conditions. Bccentricity \(\frac{2}{3},\) horizontal major axis of length 6
View solution Problem 28
Find an equation of the ellipse, centered at the origin, satisfying the conditions. Eccentricity \(\frac{3}{4},\) vertices \((0, \pm 8)\)
View solution Problem 31
Translate the ellipse with the given equation so that it is centered at the given point. Find the new equation and sketch its graph. $$ \frac{x^{2}}{2}+\frac{y^
View solution Problem 31
Find an equation of the parabola with vertex \((0,0)\) that satisfies the given conditions. $$ \text { Focus }\left(0, \frac{3}{4}\right) $$
View solution