Problem 30
Question
The area of a rectangle is 25\(\sqrt{35}\) square feet and the width is 10\(\sqrt{5}\) feet. Find the length of the rectangle in simplest radical form.
Step-by-Step Solution
Verified Answer
The length of the rectangle is \( \frac{5\sqrt{7}}{2} \) feet.
1Step 1: Understand the formula
The formula for the area of a rectangle is given by \( \text{Area} = \text{Length} \times \text{Width} \). Here, the area of the rectangle is 25\( \sqrt{35} \) square feet and the width is 10\( \sqrt{5} \) feet.
2Step 2: Set up the equation
With the known values, our equation becomes \( 25\sqrt{35} = \text{Length} \times 10\sqrt{5} \).
3Step 3: Isolate the length
To find the length, divide both sides of the equation by the width (10\( \sqrt{5} \)): \( \text{Length} = \frac{25\sqrt{35}}{10\sqrt{5}} \).
4Step 4: Simplify the expression
Simplify the fraction \( \frac{25\sqrt{35}}{10\sqrt{5}} \):- Divide \( 25 \) by \( 10 \) to get \( 2.5 \).- Simplify the square roots: divide \( \sqrt{35} \) by \( \sqrt{5} \) to get \( \sqrt{7} \) because \( \frac{\sqrt{35}}{\sqrt{5}} = \sqrt{\frac{35}{5}} = \sqrt{7} \).- Thus, \( \text{Length} = 2.5 \times \sqrt{7} \).
5Step 5: Express in simplest radical form
Multiply 2.5 by \( \sqrt{7} \) to express the length in simplest radical form: \( \text{Length} = \frac{5}{2} \times \sqrt{7} \). This simplifies further to \( \frac{5\sqrt{7}}{2} \).
Key Concepts
Rectangle AreaSimplifying RadicalsRectangle Dimensions
Rectangle Area
The area of a rectangle is calculated by multiplying its length by its width. This basic formula is very important, especially when dealing with expressions involving radicals. In our problem, the area is given as \( 25\sqrt{35} \) square feet.
Understanding that the area represents the total size of the rectangle's surface helps us set up equations to solve for any missing dimensions. In our case, knowing the area allows us to determine the length of the rectangle from the width. Remember, every time numbers involve radicals, you have to follow the rules of radical operations which might include simplification.
Understanding that the area represents the total size of the rectangle's surface helps us set up equations to solve for any missing dimensions. In our case, knowing the area allows us to determine the length of the rectangle from the width. Remember, every time numbers involve radicals, you have to follow the rules of radical operations which might include simplification.
Simplifying Radicals
Simplifying radicals is about rewriting a radical so that no perfect square factors remain under the square root. It's an essential skill when working with radical expressions. In this exercise, we simplified \( \frac{25\sqrt{35}}{10\sqrt{5}} \) by:
- Dividing the coefficients (numbers in front of the radicals), which gave us \( 2.5 \).
- Simplifying the radicals \( \sqrt{35} \) and \( \sqrt{5} \) by dividing them. This works because \( \frac{\sqrt{35}}{\sqrt{5}} = \sqrt{7} \).
Rectangle Dimensions
The dimensions of a rectangle are the measurements of its length and width. These are essential parameters that help define the rectangle's shape and size. When one or both dimensions involve radicals, extra steps are needed to manage these expressions properly.
In this exercise, the width was given as \( 10\sqrt{5} \) feet, and the task was to find the length. By using the formula for the area and simplifying the radicals, we managed to deduce that the length is \( \frac{5\sqrt{7}}{2} \) feet.
Understanding how to manipulate and simplify radical expressions is crucial for accurately determining a rectangle's dimensions when dealing with such problems. This makes it easier to visualize and utilize the rectangle in real-world applications.
In this exercise, the width was given as \( 10\sqrt{5} \) feet, and the task was to find the length. By using the formula for the area and simplifying the radicals, we managed to deduce that the length is \( \frac{5\sqrt{7}}{2} \) feet.
Understanding how to manipulate and simplify radical expressions is crucial for accurately determining a rectangle's dimensions when dealing with such problems. This makes it easier to visualize and utilize the rectangle in real-world applications.
Other exercises in this chapter
Problem 30
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