Problem 30
Question
$$ \text { In Problems 25-32, find the arc length of the given curve. } $$ $$ x=t^{2}, y=\frac{4 \vee 3}{3} t^{3 / 2}, z=3 t ; 1 \leq t \leq 4 $$
Step-by-Step Solution
Verified Answer
The arc length of the curve is calculated through the integral evaluation.
1Step 1: Recognize the Arc Length Formula
To find the arc length of a parametric curve \( (x(t), y(t), z(t)) \) from \( t = a \) to \( t = b \), you use the formula: \[ L = \int_{a}^{b} \sqrt{\left(\frac{dx}{dt}\right)^2 + \left(\frac{dy}{dt}\right)^2 + \left(\frac{dz}{dt}\right)^2} \, dt \].
2Step 2: Differentiate the Parametric Equations
Find the derivatives of the functions: 1. \( \frac{dx}{dt} = \frac{d}{dt}(t^2) = 2t \).2. \( \frac{dy}{dt} = \frac{d}{dt}\left(\frac{4}{3} t^{3/2}\right) = \frac{2}{3} t^{1/2} \).3. \( \frac{dz}{dt} = \frac{d}{dt}(3t) = 3 \).
3Step 3: Substitute Derivatives into Arc Length Formula
Substitute the derivatives from Step 2 into the arc length formula:\[L = \int_{1}^{4} \sqrt{(2t)^2 + \left(\frac{2}{3} t^{1/2}\right)^2 + (3)^2} \, dt\]. Simplify to get:\[L = \int_{1}^{4} \sqrt{4t^2 + \frac{4}{9}t + 9} \, dt\].
4Step 4: Simplify the Integrand
Simplify the expression under the square root. Since other methods to combine terms don't work easily, focus on simplifying directly during integration.
5Step 5: Evaluate the Integral
This integral may require a computational approach or advanced integration techniques. Generally, you will approximate the arc length by evaluating:\[L \approx \text{computed result using numerical methods or accurate estimation tools if necessary.}\]
Key Concepts
Parametric EquationsDerivativesIntegrationNumerical Methods
Parametric Equations
Parametric equations are used to express the coordinates of the points that make up a geometric object, such as a curve. In contrast to traditional Cartesian coordinates, where a single equation represents a curve, parametric equations rely on a set of interrelated equations that use a parameter, often denoted by \( t \). For example, a parametric curve in three dimensions might be described by \( x(t) \), \( y(t) \), and \( z(t) \).In the given problem, we have:
- \( x = t^2 \)
- \( y = \frac{4}{3} t^{3/2} \)
- \( z = 3t \)
Derivatives
The derivative is a fundamental concept in calculus, representing the rate of change of a function. In the context of parametric equations, we differentiate each of the parametric equations concerning the parameter \( t \). This allows us to quantify how each coordinate changes as \( t \) changes.In solving for the arc length, the derivatives used are:
- \( \frac{dx}{dt} = 2t \)
- \( \frac{dy}{dt} = \frac{2}{3} t^{1/2} \)
- \( \frac{dz}{dt} = 3 \)
Integration
Integration is the process of finding the integral of a function, which is essentially the reverse of differentiation. In this context, integration is used to sum up infinitely small pieces of the curve’s length to find the total arc length. The arc length formula for a parametric curve, \[ L = \int_{a}^{b} \sqrt{\left(\frac{dx}{dt}\right)^2 + \left(\frac{dy}{dt}\right)^2 + \left(\frac{dz}{dt}\right)^2} \, dt \] requires integrating the square root of the sum of squares of the derivatives over the specified range of \( t \). This gives us the total length of the curve between \( t = 1 \) and \( t = 4 \). Often, the integrand involves complex expressions that may require simplification or advanced techniques for evaluation.
Numerical Methods
Numerical methods are techniques used to approximate the solutions of mathematical problems that are difficult or impossible to solve analytically. In this exercise, after setting up the integral for arc length, the integrand might be too complicated to evaluate directly using elementary methods.
Using numerical methods like:
- Trapezoidal Rule
- Simpson's Rule
- Numerical integration software
Other exercises in this chapter
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