Problem 30
Question
Solve the inequality. Express the answer using interval notation. $$ |5 x-2|<6 $$
Step-by-Step Solution
Verified Answer
The solution is \((-\frac{4}{5}, \frac{8}{5})\).
1Step 1: Understand Absolute Inequality
The inequality \(|5x - 2| < 6\) involves an absolute value. This can be understood as the expression inside the absolute value lying within a distance of 6 from 0. Thus, we split it into two separate inequalities: \(5x - 2 < 6\) and \(5x - 2 > -6\).
2Step 2: Solve the First Inequality
For the inequality \(5x - 2 < 6\), we first add 2 to both sides to isolate the term with the variable. This gives us \(5x < 8\). Next, divide each side by 5 to solve for \(x\). This results in \(x < \frac{8}{5}\).
3Step 3: Solve the Second Inequality
For the inequality \(5x - 2 > -6\), begin by adding 2 to both sides, resulting in \(5x > -4\). Divide each side by 5 to solve for \(x\). This results in \(x > -\frac{4}{5}\).
4Step 4: Combine the Results
We now have the two inequalities \(x < \frac{8}{5}\) and \(x > -\frac{4}{5}\). Together, they define the interval \(-\frac{4}{5} < x < \frac{8}{5}\).
5Step 5: Express in Interval Notation
Convert the combined inequality to interval notation. The solution is \((-\frac{4}{5}, \frac{8}{5})\). This expresses all values of \(x\) that satisfy the original absolute value inequality.
Key Concepts
Interval NotationSolving InequalitiesAbsolute Value Functions
Interval Notation
Interval notation is a method of representing a set of numbers, specifically the solutions to inequalities in a compact form. It succinctly describes the range of values within an interval, using parentheses and brackets to indicate whether endpoints are included or excluded.
In the exercise above, the solution to the inequality \(|5x - 2| < 6\) lies between the values \(-\frac{4}{5}\) and \(\frac{8}{5}\). In interval notation, this is represented as \((-\frac{4}{5}, \frac{8}{5})\). This means:
In the exercise above, the solution to the inequality \(|5x - 2| < 6\) lies between the values \(-\frac{4}{5}\) and \(\frac{8}{5}\). In interval notation, this is represented as \((-\frac{4}{5}, \frac{8}{5})\). This means:
- The parentheses indicate that the endpoints \(-\frac{4}{5}\) and \(\frac{8}{5}\) are not included in the interval.
- A comma separates the lower bound and the upper bound of the interval.
Solving Inequalities
Solving inequalities involves finding the set of all possible values of a variable that make an inequality true. The process is similar to solving equations but requires careful attention to the inequality signs.
To solve an inequality:
Once you have the solutions for both inequalities, you combine them to find the overall solution for the absolute inequality. This final step often involves understanding what values satisfy both conditions simultaneously.
To solve an inequality:
- Perform operations similar to those used in solving equations (like adding, subtracting, multiplying, and dividing).
- When multiplying or dividing by a negative number, reverse the direction of the inequality sign.
Once you have the solutions for both inequalities, you combine them to find the overall solution for the absolute inequality. This final step often involves understanding what values satisfy both conditions simultaneously.
Absolute Value Functions
Absolute value functions express the distance of a number from zero, without regard to direction. Mathematically, the absolute value of a number is defined as:
In the given exercise, the inequality \(|5x - 2| < 6\) means that the expression \(5x - 2\) lies within 6 units of distance from zero. Solving absolute inequalities typically requires splitting the expression inside the absolute value into two separate inequalities.
- If the number is positive or zero, its absolute value is the same number.
- If the number is negative, its absolute value is the number without its negative sign.
In the given exercise, the inequality \(|5x - 2| < 6\) means that the expression \(5x - 2\) lies within 6 units of distance from zero. Solving absolute inequalities typically requires splitting the expression inside the absolute value into two separate inequalities.
- One for the positive case: \(5x - 2 < 6\).
- One for the negative case: \(5x - 2 > -6\).
Other exercises in this chapter
Problem 29
Find all real solutions of the equation. \(2 x^{2}+x-3=0\)
View solution Problem 29
\(9- 46\) The given equation is either linear or equivalent to a linear equation. Solve the equation. $$ \sqrt{3} x+\sqrt{12}=\frac{x+5}{\sqrt{3}} $$
View solution Problem 30
Dimensions of a Lot A half-acre building lot is five times as long as it is wide. What are its dimensions? [Note: 1 acre \(=43,560 \mathrm{ft}^{2} . ]\)
View solution Problem 30
\(9-32\) me solve the linear inequality. Express the solution using interval notation and graph the solution set. $$ -3 \leq 3 x+7 \leq \frac{1}{2} $$
View solution