Problem 30
Question
Solve the equation. $$ 4 \sqrt{3 x+3}=24 $$
Step-by-Step Solution
Verified Answer
The solution for the equation is \(x = 11\).
1Step 1: Isolate the square root
The first step is to isolate the square root. In our equation \(4\sqrt{3x+3} = 24\), we start by dividing both sides by 4 to get \(\sqrt{3x+3} = 6\).
2Step 2: Remove the square root
We want to remove the square root. We can do that by squaring both sides of the equation: \((\sqrt{3x+3})^2=6^2\), which simplifies to \(3x+3=36\).
3Step 3: Isolate \(x\)
Now, let's isolate the variable \(x\). First, subtract 3 from both sides to get \(3x = 33\), then divide both sides by 3 to isolate \(x\), so we get \(x = 11\).
Key Concepts
Square RootsIsolating VariablesAlgebraic Equations
Square Roots
Square roots are fundamental to solving radical equations. They are incredibly useful in various fields, including algebra and geometry. A square root function is essentially the opposite of squaring a number. When you take the square root of a number, you're asking "What number, when multiplied by itself, gives me this number?"
For example, the square root of 25 is 5, because \(5 \times 5 = 25\).
For example, the square root of 25 is 5, because \(5 \times 5 = 25\).
- Square roots undo the operation of squaring a number.
- They appear in equations that need a specific approach to be solved.
Isolating Variables
Isolating the variable is a critical step in solving equations. This process involves rearranging the equation term by term to get the variable alone on one side. In our example, we first isolated the square root by dividing by 4, which got us to \(\sqrt{3x+3} = 6\).
- This step simplifies the equation, making the variable clear.
- It’s crucial for identifying what operation to perform next to solve for the variable.
Algebraic Equations
Algebraic equations are foundational in mathematics and serve as precise, compact representations of relations between quantities. They consist of constants, variables, and arithmetic operations. Solving them involves finding values for the variables that make the equation true.
- They can be linear, quadratic, or involve higher-degree polynomials.
- Simplifying and solving algebraic equations entails a methodical approach.
Other exercises in this chapter
Problem 30
Simplify the expression. $$ \sqrt{6}(7 \sqrt{3}+6) $$
View solution Problem 30
Find the domain of the function. Then use severalvalues in the domain to make a table of values for the function. $$y=\sqrt{x-17}$$
View solution Problem 31
Determine whether the equation has two solutions, one solution, or no real solution. (Lesson 9.7) $$ 2 x^{2}+4 x-2=0 $$
View solution Problem 31
Find the midpoint of the line segment connecting the given points. Then show that the midpoint is the same distance from each point. \((-9,17),(5,-7)\)
View solution